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The Bowman’s capsule is found in the cortex region of the kidney. i.e. the part labeled 2.

No expanded working has been attached for this question yet. The verified answer is Option E.

No expanded working has been attached for this question yet. The verified answer is Option E.

1 - \(\sqrt{13}\) and 1 + \(\sqrt{13}\) sum of roots - \(1 + \sqrt{13} + 1 - \sqrt{13} = 2\) Product of roots = (1 - \(\sqrt{13}\)) (1 + \(\sqrt{13}\)) = -12 x2 - (sum of roots) x + (product of roots) = 0 x2 - 2x - 12 = 0

\(\frac{\sin y}{3} = \frac{\sin 120^o}{5}\) sin 120o = sin 60o 5 sin y = 3 sin 60o sin y = \(\frac{3 \sin 60^o}{5}\) \(\frac{3 \times 0.866}{5}\) = \(\frac{2.598}{5}\) y = sin-1 0.5196 = 30o 18'

The dynamic microphone is constructed with a small magnet that oscillates inside a coil attached to the diaphragm. When a sound wave causes the diaphragm of the microphone to vibrate, the relative motion of the magnet and coil creates an electrical signal by magnetic induction.

Given Data: I\(_g\) = 100ma = 0.1A R\(_g\)=5 where I\(_s\) = I - I\(_g\) → 1 - 0.1 I\(_s\) = 0.9 I\(_g\)R\(_g\) = I\(_s\)R\(_s\) 0.1 * 5 = 0.9 * R\(_s\) R\(_s\) = \(\frac{0.1 * 5}{0.9}\) R\(_s\) = \(\frac{5}{9}\)

A carboxylic acid is an organic acid that contains a carboxyl group attached to an R-group. The general formula of a carboxylic acid is R−COOH or R−CO₂H, with R referring to the alkyl, alkenyl, aryl, or other group.

\(\frac{2}{3} - \frac{1}{5}\) = \(\frac{10 - 3}{15}\) = \(\frac{7}{15}\) \(\frac{1}{3}\) Of \(\frac{2}{5}\) = \(\frac{1}{3}\) x \(\frac{2}{5}\) = \(\frac{2}{15}\) (\(\frac{2}{3} - \frac{1}{5}\)) - \(\frac{1}{3}\) of \(\frac{2}{5}\) = \(\frac{7}{15} - \frac{2}{15}\) = \(\frac{1}{3}\) 3 - \(\frac{1}{1 \frac{1}{2}}\) = 3 - \(\frac{2}{3}\) = \(\frac{7}{3}\) \(\frac{\frac{2}{3} - \frac{1}{5} \text{of} \frac{2}{15}}{3 - \frac{1}{1 \frac{1}{2}}}\) = \(\frac{\frac{1}{3}}{\frac{7}{3}}\) = \(\frac{1}{3}\) x \(\frac{3}{7}\) = \(\frac{1}{7}\)

\(\frac{0.0001432}{1940000}\) = k x 10n where 1 \(\leq\) k \(\leq\) 10 and n is a whole number. Using four figure tables, the eqn. gives 7.38 x 10-11 k = 7.381, n = -11

Let the selling price(SP from P to Q be represented by x i.e. SP = x When SP = x at 10% profit CP = \(\frac{100}{100}\) + 10 of x = \(\frac{100}{110}\) of x when Q sells to R, SP = N209 at loss of 5% Q's cost price = Q's selling price CP = \(\frac{100}{95}\) x 209 = 220.00 x = 220 = \(\frac{2200}{11}\) = 200 = N200.00

Let x represent the price of an orange and y represent the number of oranges that can be bought xy = 240k, y = \(\frac{240}{x}\).....(i) If the price of an oranges is raised by \(\frac{1}{2}\)k per orange, number that can be bought for N240 is reduced by 16 Hence, y - 16 = \(\frac{240}{x + \frac{1}{2}\) = \(\frac{480}{2x + 1}\) = \(\frac{480}{2x + 1}\).....(ii) subt. for y in eqn (ii) \(\frac{240}{x}\) - 16 = \(\frac{480}{2x + 1}\) = \(\frac{240 - 16x}{x}\) = \(\frac{480}{2x + 1}\) = (240 - 16x)(2x + 1) = 480x = 480x + 240 - 32x2 - 16 480x = 224 - 32x2 x2 = 7 x = \(\sqrt{7}\) = 2.5 = 2\(\frac{1}{2}\)k

Total yield = N3,700 Total amount invested = N 50,000 Let x be the amount invested at 6% interest and let y be the amount invested at 8% interest then yield on x = \(\frac{6}{100}\) x and yield on y = \(\frac{8}{100}\)y Hence, \(\frac{6}{100}\)x + \(\frac{8}{100}\)y = 3,700.........(i) x + y = 50,000........(ii) 6x + 8y = 370,000 x 1 x + y = 50,000 x 6 6x + 8y = 370,000.........(iii) 6x + 6y = 300,000........(iv) eqn (iii) - eqn(2) 2y = 70,000 y = \(\frac{70,000}{2}\) = 35,000 Money invested at 8% is N35,000

Number of boy's = 30 Number of girls = x Mean of boys' score = 6, for girls = 8 Total score for boys = 30 x 6 Total score for both boys and girls = 468 180 + 8x = 468 x = \(\frac{288}{8}\) = 36

Total cost of production = N120.00 Labour Cost = \(\frac{70}{120}\) x \(\frac{360^o}{1}\) = 210o