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Biology
UTME / JAMB 1986
Growth, Micro-organisms & Public Health
Which of these disease CANNOT be prevented by immunization?
A
Poliomyelitis
B
Tuberculosis
C
Cholera
D
onchocerciasis
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #3659)
Biology
UTME / JAMB 1986
Variety of Organisms & Classification of Living Things
Which of the following ecological factors are common to both terrestrial and aquatic habitats?
A
Rainfall, temperature and light
B
Salinity, rainfall and altitude
C
Tides, wind, rainfall and altitude
D
pH, salinity, rainfall and humidity.
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #3660)
Biology
UTME / JAMB 1986
Variety of Organisms & Classification of Living Things
Solution
In community, bacteria and fungi are referred to as
A
producers
B
decomposers
C
scavengers
D
consumers
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
In a food chain, bacteria and fungi are referred to as decomposers because they break down dead organic matter, returning nutrients to the soil.
Source: Myschool Past Questions Archive (Record #3661)
Biology
UTME / JAMB 1986
Growth, Micro-organisms & Public Health
The swollen shoot disease of cocoa tree is caused by a
A
virus
B
fungus
C
bacterium
D
protozoan
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #3662)
Biology
UTME / JAMB 1986
Variety of Organisms & Classification of Living Things
A larger percentage of tropical soils tends to be acidic because they
A
contain large quantities of potash
B
contain large quantities of lime
C
lose a high proportion of their organic matter to running water
D
lose lime and potash from the top soil through rain action
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #3663)
Biology
UTME / JAMB 1986
Population Ecology, Habitats & Conservation
The following are methods of soil conservation EXCEPT
A
contour terracing
B
strip cropping
C
contour ploughing
D
mixed grazing
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #3664)
Biology
UTME / JAMB 1986
Basic Ecological Concepts, Ecosystems & Biomes
Solution
Sample of different soil types are packed in glass tubes whose lower ends are plugged with cotton wool, if these tubes are suspended in a trough of water, water will rise highest after a few hours in
A
sand
B
loamy
C
clay
D
humus
medium Difficulty
Verified Correct Answer: Option C
Biological Concept & Syllabus Guide
Capillarity, the ability of a liquid to move against gravity through small spaces, is highest in clay soils due to their fine particles and small pore spaces. Clay soils are composed of very small, tightly packed particles, creating numerous small channels or pores. The small spaces between clay particles also contribute to a high water-holding capacity, meaning clay soils can retain moisture for extended periods.
While loamy soils also exhibit some capillarity, sandy soils have larger particles and pore spaces, resulting in lower capillarity and faster water drainage.
Source: Myschool Past Questions Archive (Record #3665)
Biology
UTME / JAMB 1986
Variety of Organisms & Classification of Living Things
Diagram
Which of the labelled parts will develop into a new maize plant?
Attached Figure / Diagram
A
2
B
3
C
4
D
5
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #15544)
Biology
UTME / JAMB 1986
Cell Structure, Organization & Cell Division
Diagram
Solution
The structure labelled 1 is the
Attached Figure / Diagram
A
plumule
B
radicle
C
cell membrane
D
seed coat
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
the structure labeled I is the seed coat.
Source: Myschool Past Questions Archive (Record #15545)
Biology
UTME / JAMB 1986
Reproduction in Plants & Animals
Diagram
The main function of the structure labelled 2 is to
Attached Figure / Diagram
A
protect the inner parts of the seed
B
nourish the embryo and the growing plant
C
keep the inner parts moist
D
maintain the shape if the seed
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #15546)
Biology
UTME / JAMB 1986
Reproduction in Plants & Animals
The main function of the structure labelled 2 is to
A
protect the inner parts of the seed
B
nourish the embryo and the growing plant
C
keep the inner parts moist
D
maintain the shape if the seed
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Official Exam / Past Question Archive
Mathematics
UTME / JAMB 1985
Indices, Logarithms & Surds
Solution
Find x if log\(_9\)x = 1.5
A
72.0
B
27.0
C
36.0
D
3.5
E
24.5
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
If log\(_9\)x = 1.5,
9\(^1.5\) = x
9^\(\frac{3}{2}\) = x
(\sqrt9)\(^3\) = 3
∴ x = 27
Source: WAEC / JAMB / NECO Classroom Archive (Record #32213)
Mathematics
UTME / JAMB 1985
Fractions, Decimals, Percentages & Approximations
Solution
Solve the following equation \(\frac{2}{2r - 1}\) - \(\frac{5}{3}\) = \(\frac{1}{r + 2}\)
A
(\(\frac{5}{2}\), 1)
B
(5, -4)
C
(2, 1)
D
(1, \(\frac{-5}{2}\))
E
(1,-2)
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
\(\frac{2}{2r - 1}\) - \(\frac{5}{3}\) = \(\frac{1}{r + 2}\)
\(\frac{2}{2r - 1}\) - \(\frac{1}{r + 2}\) = \(\frac{5}{3}\)
\(\frac{2r + 4 - 2r + 1}{2r - 1 (r + 2)}\) = \(\frac{5}{3}\)
\(\frac{5}{(2r + 1)(r + 2)}\) = \(\frac{5}{3}\)
5(2r - 1)(r + 2) = 15
(10r - 5)(r + 2) = 15
\(10r^2\) + 20r - 5r - 10 = 15
\(10r^2\) + 15r = 25
\(10r^2\) + 15r - 25 = 0
\(2r^2\) + 3r - 5 = 0
(\(2r^2 + 5r)\)(2r + 5) = r(2r + 5) - 1(2r + 5)
(r - 1)(2r + 5) = 0
r = 1 or \(\frac{-5}{2}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #32229)
Mathematics
UTME / JAMB 1985
Linear, Simultaneous & Quadratic Equations
Solution
Solve the simultaneous equations 2x - 3y + 10, 10x - 6y = - 5
A
x = 2\(\frac{1}{2}\), y = 5
B
x = \(\frac{1}{2}\), y = \(\frac{3}{2}\)
C
x = 2\(\frac{1}{4}\), y = 3\(\frac{1}{2}\)
D
x = 2\(\frac{1}{3}\), y = 3\(\frac{1}{2}\)
E
x = 2\(\frac{1}{3}\), y = 2\(\frac{1}{2}\)
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
2x - 3y = - 10; 10x - 6y = -5
2x - 3y = -10 x 2
10x - 6y = -5
4x - 6y = -20 .......(i)
10x - 6y = -5.......(ii)
eqn(ii) - eqn(1)
6x = 15
x = \(\frac{15}{6}\)
= \(\frac{5}{2}\)
x = 2\(\frac{1}{2}\)
Sub. for x in equ.(ii) 10(\(\frac{5}{2}\)) - 6y = -5
6y = 25 + 5 → 30
y = \(\frac{30}{6}\)
y = 5
Source: WAEC / JAMB / NECO Classroom Archive (Record #32230)
Mathematics
UTME / JAMB 1985
Mensuration (Areas, Perimeters & Volumes)
Solution
The ratio of the length of two similar rectangular blocks is 2 : 3. If the volume of the larger block is 351cm\(^3\), then the volume of the other block is?
A
234.00 cm3
B
526.50 cm3
C
166.00 cm3
D
687cm3
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
Let x represent total vol. 2 : 3 = 2 + 3 = 5
\(\frac{3}{5}\)x = 351
x = \(\frac{351 \times 5}{3}\)
= 585
Volume of smaller block = \(\frac{2}{5}\) x 585
= 234.00cm\(^3\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #32260)