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Chemistry
UTME / JAMB 1986
Organic Chemistry I: Hydrocarbons & Crude Oil
Which of the following compounds is NOT formed by the action of chlorine on methane?
A
CH3CI
B
C2H5CI
C
CH2CI2
D
CHCI3
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #14183)
Chemistry
UTME / JAMB 1986
Stoichiometry, Mole Concept & Volumetric Analysis
Which of the following substance is a mixture?
A
Granulated sugar
B
Sea-water
C
Sodium chloride
D
Iron fillings
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #14184)
Chemistry
UTME / JAMB 1986
Stoichiometry, Mole Concept & Volumetric Analysis
The general formula of an alkyl halide (where X represents the halide) is?
A
CnH2n 2X
B
CnH2n + 1X
C
CnH2n + 2X
D
CnH2nX
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #14186)
Chemistry
UTME / JAMB 1986
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Which of the following are made by the process of polymerization?
A
Nylon and soap
B
Nylon and artificial rubber
C
Soap and butane
D
Margarine and nylon
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #14187)
Chemistry
UTME / JAMB 1986
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Starch can be converted to ethyl alcohol by?
A
distillation
B
fermentation
C
isomerization
D
cracking
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #14188)
Chemistry
UTME / JAMB 1986
Kinetic Theory of Matter & Gas Laws
The movement of liquid molecules from the surface of the liquid to the gaseous phase above it is known as?
A
Brownian movement
B
condensation
C
evaporation
D
liquefaction
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #14261)
Chemistry
UTME / JAMB 1986
Kinetic Theory of Matter & Gas Laws
Solution
What mass of a divalent metal M (atomic mass = 40) would react with excess hydrochloric acid to liberate 224cm^3 dry hydrogen gas measured at S.T.P?
A
8.0 g
B
4.0 g
C
0.8 g
D
0.4 g
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
let the divalent metal be Q
Q + 2HCl → QCl2 + H2
1mole of Q liberated 1 mole of Hydrogen gas ( one mole of any gas at STP has a volume of 22400cm^3 or 22.4dm^3 )
40 → 22400cm^3
? → 224cm^3
mass of Q = \(\frac{ 40 \times 224}{22400}\)
mass of Q = 0.4g.
Source: Myschool Past Questions Archive (Record #14263)
Chemistry
UTME / JAMB 1986
Water, Solutions & Solubility
Diagram
Solution
In the solubility curve above, water at 98\(^0\)C is saturated with KCl and KCIO\(_3\). What is the percentage of KCl impurity in the crystals formed when the solution is cooled to 30\(^0\)C?
Attached Figure / Diagram
A
51.5
B
45.5
C
34.5
D
26.5
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
From the graph, when you try to extrapolate the temperature to the solubility value of both KCl and KCIO\(_3\), we'll arrive at the following data:
KCl
KClO\(_3\)
@ 98\(^0\)C
55
55
@ 30\(^0\)C
37
5
Difference
18
50
Total weight dissolved in 100g of water = 18 + 50 = 68g
% KCl impurity = \(\frac{weight of KCl}{Total weight}\times 100\)
= \(\frac{18}{68}\times 100\)
= 26.47
= 26.5%
Source: Myschool Past Questions Archive (Record #31360)
Chemistry
UTME / JAMB 1986
Electrolysis & Electrochemical Cells
Diagram
In the electrolysis of aqueous solution of K2SO 4 in the above cell, which species migrate to the anode?
Attached Figure / Diagram
A
SO2-OH -
B
K + and SO 4 2-
C
OH and HO
D
H3O + and K
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #31363)
Chemistry
UTME / JAMB 1986
Stoichiometry, Mole Concept & Volumetric Analysis
Diagram
Solution
The tabulated results below were obtained by titration 10.0 cm3 of water with soup. The titration was repeated with the same sample of water after boiling. The ratio of permanent to temporary hardness is
Attached Figure / Diagram
A
1.5
B
1.4
C
4.1
D
5.1
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The ratio of permanent to temporary hardness will be 20:(20 - 15)
= 20:5
= 4:1
Source: Myschool Past Questions Archive (Record #31368)
Chemistry
UTME / JAMB 1986
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Diagram
Solution
Use the options above to answer this question. Which is the structural formula for pent-2-enoic acid?
Attached Figure / Diagram
A
A
B
B
C
C
D
D
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The structural formula for pent-2-enoic acid is CH\(_3\)CH\(_2\)CH=CHCOOH.
It is a 5-carbon carboxylic acid featuring a double bond between the second and third carbon atoms.
Source: Myschool Past Questions Archive (Record #31369)
Chemistry
UTME / JAMB 1986
Water, Solutions & Solubility
When 50cm3 of a saturated solution of sugar (molar mass 342.0g) at 40oC was evaporated to dryness, 34.2g of dry solid was obtained. The solubility of sugar at 40oC is
A
10.0 moles dm-3
B
7.0 moles dm-3
C
3.5 moles dm-3
D
2.0 moles dm-3
E
none of the options is correct
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Official Exam / Past Question Archive
Chemistry
UTME / JAMB 1986
Stoichiometry, Mole Concept & Volumetric Analysis
10cm3 of hydrogen fluoride gas react with 5cm3 of dinitrogen difluoride gas (N2F2) to form 103 of a single gas. Which of the following is the most likely equation of the reaction?
A
HF + N2F2 \(\to\) N2HF3
B
2HF + N2F2 \(\to\) 2NHF2
C
2HF + N2F2 \(\to\) N2H2F3
D
HF + 2N2F2 \(\to\) N4HF2
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #44457)
Chemistry
UTME / JAMB 1986
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
The number of atoms of chlorine present in 5.85g of NaCl is [Avogadro's Number = 6.02 x 10\(^{23}\)]
A
6.02 x 1022
B
5.85 x 1023
C
6.02 x 1023
D
5.85 x 1024
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
NaCl(s) ⇌ Na⁺(aq) + Cl⁻(aq).
Number of moles = \(\frac{Number of atom}{Avogadro number}\)
n = \(\frac{N}{L}\)
Recall that Number of moles, n = \(\frac{mass}{Molar mass}\)
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
n = \(\frac{5.85}{58.5}\)
n = 0.1 mole
⇒ N = n x L = 0.1 x 6.02 x 10\(^{23}\)
N = 6.02 x 10\(^{22}\)
Source: Myschool Past Questions Archive (Record #44458)
Chemistry
UTME / JAMB 1986
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
How much of magnesium is required to react with 260cm3 of 0.5 M HCl? [Mg = 24]
A
0.3g
B
1.5g
C
2.4g
D
3.0g
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
First write a balanced chemical equation to show the reaction
Mg + 2HCl → MgCl\(_2\) + H\(_2\)
1mole : 2 moles
From what we were given n = \(\frac{CV}{1000}\)
n = \(\frac{{0.5}\times{260}}{1000}\)
n = 0.13 mole
By Simple proportion,
1 mole of Mg → 2 moles of HCl
then x mole of Mg → 0.13mole of HCl
x = \(\frac{0.13}{2}\) = 0.065mole
Also recall that n = \(\frac{m}{M}\)
m = n x M
m = 0.065 x 24 = 1.56g
Therefore the mass of Magnesium required to react with 260cm3 of 0.5 M HCl is 1.56g
Source: Myschool Past Questions Archive (Record #44459)