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Physics
UTME / JAMB 1986
Elasticity, Density, Pressure & Fluids
Solution
Mercury is suitable as a barometric fluid because it?
A
expands uniformly
B
is opaque
C
is several times denser than water
D
is a good conductor of heat
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Mercury is employed in the barometer because its density is sufficiently high for a relative short column to be obtained.
Source: Myschool Past Questions Archive (Record #28499)
Physics
UTME / JAMB 1986
Gas Laws & Heat Transfer
Which of the following properties makes metals ideal for cooking utensils?
A
high coefficient of expansion
B
good conduction of heat
C
low specific heat capacity
D
poor radiation of heat
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #28501)
Physics
UTME / JAMB 1986
Current Electricity & Electric Circuits
Solution
A gas occupies a volume of 300cm3at a temperature of 27oC. What is its volume at 54oC, when the pressure is constant?
A
150cm3
B
273cm3
C
327cm3
D
600cm3
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
\(\frac{V_1}{T_1}\) = \(\frac{V_2}{T_2}\)
\(\frac{300}{27 + 273}\) = \(\frac{V_2}{54 + 273}\)
V2 = 327cm3
Source: Myschool Past Questions Archive (Record #28503)
Physics
UTME / JAMB 1986
Calorimetry, Latent Heat & Change of State
Solution
When two objects P and Q are supplied with the same quantity of heat, the temperature change in P is observed to be twice that of Q. The mass of P is half that of Q. The ratio of the specific heat capacity of P to Q is
A
1 : 4
B
4 : 1
C
1 : 1
D
2 : 1
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
\(\theta\)p = 2\(\theta\)q
mq = 2mp
Cp X mp X \(\theta\)p = Cq x mq x \(\theta\)q
\(\frac {C_pm_q\theta q}{C_qm_p \theta q}\) = \(\frac {\theta q \times 2mp}{2 \theta qmp}\)
\(\frac {C_p}{Cq}\) = \(\frac {2}{2}\)
Source: Myschool Past Questions Archive (Record #28508)
Physics
UTME / JAMB 1986
Waves, Sound & Vibrations
Which of the following is true of sounds?
A
sound travels faster in air at 20oC than at 30oC
B
the frequency of a given sound wave changes when it crosses the boundary seperating two media
C
the wavelength of a given sound wave in air decreases as the temperature increases
D
sound waves cannot be reflected
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #28513)
Physics
UTME / JAMB 1986
Lenses & Optical Instruments
Solution
A lens of focal length 12.0cm forms an upright image three times the size of a real object. The distance between the object and the images is
A
8.0cm
B
16.0cm
C
24.0cm
D
32.0cm
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
an upright image is a virtual image and it is expected to be on the same side as the object for a lens but not for a mirror.
magnification M = \(\frac{v}{u}\) = \(\frac{v}{2}\) = 3 ⇒⇒ v = 3u ( image is virtual = -3u)
using \(\frac{1}{f}\) = \(\frac{1}{u}\) + \(\frac{}{v}\) ⇒⇒ \(\frac{1}{u}\) - \(\frac{1}{3u}\) = \(\frac{1}{12}\)
\(\frac{3 -1}{3u}\) = \(\frac{1}{12}\)
cross multiplying
24 = 3u = u = 8cm but v = 3u = 24cm
virtual image and object are at the side of the lens,
Hence, the distance between the object and the image = 24 - 8 = 16cm.
Source: Myschool Past Questions Archive (Record #28519)
Physics
UTME / JAMB 1986
Atomic, Quantum, Nuclear Physics & Electronics
In which of the following arrangements is the wavelength in an increasing order?
A
Gamma rays, infra-red rays, x-rays, radiowaves
B
Gamma rays, x-rays, infra-red ray, radiowaves
C
Radiowaves, x-rays, gamma ray, infra-red rays
D
Infra-red rays, radiowaves, x-rays, gamma rays
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #28521)
Physics
UTME / JAMB 1986
Reflection, Refraction & Dispersion of Light
Solution
If the refractive index of glass is 1.5, what is the critical angle at the air-glass interface?
A
sin-1\(\frac{1}{2}\)
B
sin-1\(\frac{2}{3}\)
C
sin-1\(\frac{3}{4}\)
D
sin-1\(\frac{8}{9}\)
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
sin ic \(\frac{1}{n}\) = \(\frac{1}{1 - 5}\)
i = sin-1\(\frac{1}{1 - 5}\)
= sin-1\(\frac{10}{15}\)
= sin-1\(\frac{2}{3}\)
Source: Myschool Past Questions Archive (Record #28525)
Physics
UTME / JAMB 1986
Reflection, Refraction & Dispersion of Light
Solution
A dentist obtains a linear magnification of 4 of a hole in a tooth by placing a concave mirror at a distance, of 2.0cm from the tooth. The radius of Curvature of the mirror is
A
5.3cm
B
3.2cm
C
2.7cm
D
1.6cm
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
v = 4u, if u = 2cm, v = 8cm
F = \(\frac{uv}{u + v}\)
= \(\frac{2 \times 8}{2 + 8}\)
= 1.6cm
r = 2F
= 2 x 1.6
= 3.2cm
Source: Myschool Past Questions Archive (Record #28529)
Physics
UTME / JAMB 1986
Current Electricity & Electric Circuits
What is the effect of the increase in the size of the hole of a pin-hole camera on the image? it
A
gives a blurred image
B
corrects for chromatic aberration
C
magnifies the image
D
brings the image into a sharper focus
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #28531)
Physics
UTME / JAMB 1986
Reflection, Refraction & Dispersion of Light
Solution
A pencil is placed vertically between a concave mirror and its focal point. The image of the pencil in the mirror will be
A
real, inverted and diminished
B
virtual, inverted and enlarged
C
real, erect and enlarged
D
virtual, erect and enlarged
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Virtual Image: The image formed is virtual because it cannot be projected on a screen; it appears to be behind the mirror.
Erect: The image is upright relative to the object.
Enlarged: The image is larger than the object when it is placed between the focal point and the mirror.
Source: Myschool Past Questions Archive (Record #28532)
Physics
UTME / JAMB 1986
Waves, Sound & Vibrations
Solution
A wave of frequency 10Hz forms a stationary wave pattern in a medium where the velocity is 20cms-1. The distance between adjacent nodes is
A
1.0cm
B
1.5cm
C
2.0cm
D
5.0cm
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
\(\lambda\) = \(\frac{v}{f}\)
= \(\frac{20}{10}\)
= 2cm ; distance between adjacent nodes
= 2cm \ 2
= 1cm
Source: Myschool Past Questions Archive (Record #28535)
Physics
UTME / JAMB 1986
Waves, Sound & Vibrations
Which of the following is true of the loudness of sound? It
A
depends on the square of the amplitude of the vibrating body
B
is proportional to the distance of the observer from the source of the sound
C
is greatest in vacuum
D
is dependent in vacuum
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #28536)
Physics
UTME / JAMB 1986
Waves, Sound & Vibrations
Solution
A man clapping his hands at regular intervals observes that the echo of a clap coincides with the next clap. If the reflecting cliff is 160m away and the speed of sound is 320ms-1, what is the frequency of the clapping?
A
1 Hz
B
2Hz
C
4Hz
D
8Hz
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Total distance = 2 x 160 = 320cm
Total time = \(\frac{320}{320}\) = 1s
F = \(\frac{1}{1}\) = \(\frac{1}{1}\)
= 1Hz
Source: Myschool Past Questions Archive (Record #28537)
Physics
UTME / JAMB 1986
Current Electricity & Electric Circuits
The vibration of an air column produces the sound in the
A
piano
B
guiter
C
flute
D
school handbell
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #28539)