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No expanded working has been attached for this question yet. The verified answer is Option C.

From 40 to 50 = these number are prime i.e. 41, 43, 47 prob. of selecting a prime No. is \(\frac{3}{11}\)

Potential energy is energy possessed by a body by virtue of its position. when the body is above the ground, it possesses kinetic energy. acceleration due gravity is at constant value of 10m/s\(^2\)

Efficiency = \(\frac{M.A\times100}{V.R}\) V.R = 6 40= \(\frac{M.A\times100}{6}\) M.A = \(\frac{6 \times40}{100}\) M.A = 2.4 M.A= \(\frac{L}{E}\) E= \(\frac{120}{2.4}\) E = 50

expansion of wrist-watch causes lose of time

knocking, in an internal-combustion engine, sharp sounds caused by premature combustion of part of the compressed air-fuel mixture in the cylinder. Knocking is a phenomenon that occurs in a gasoline engine if the fuel used does not have a high enough octane rating. Anti – knocking agents are chemical compounds added in the fuels that help in effective combustion. An antiknock agent is a gasoline additive used to reduce engine knocking and increase the fuel's octane rating by raising the temperature and pressure at which auto-ignition occurs. Examples are: Methylcyclopentadienyl manganese tricarbonyl (MMT) Ferrocene. Iron pentacarbonyl. Toluene. Isooctane. Ethanol boosts the octane number of fuel, which helps prevent pre-ignition knock. Organic lead (tetraethyl lead) is used as an antiknock agent in gasoline and jet fuels.

Evaluate (212)3 - (121)3 + (222)3 (221)3+ (222)3 1211 121 ------ (1020)3

Let x represent Musa's total mark when he scores 57 in biology and Let Y represent Musa's total mark when he now scored 75 in biology, if he scored 75 in biology his new total mark will be \(\frac{Y}{4}\) = 60, y = 4 x 60 = 240 To get his total mark when he scored 57, subtract 57 from 75 to give 18, then subtract this 18 from the new total mark(ie. 240) = 240 - 18 = 222

48 = 24 x 3, 64 = 26, 80 = 24 x 5 L.C.M = 26 x 3 x 5 H.C.F = 24 \(\frac{2^6 \times 3 \times 5}{2^4}\) = 22 x 3 x 5 = 4 x 3 x 5 = 12 x 5 = 60

\(252 = 2^{2} \times 3^{2} \times 7\) \(\therefore\) To make 252 a perfect square, the smalest number to multiply with = 7. \(252 \times 7 = 1764 = 42^{2}\)

\(\frac{2}{3}\) = \(\frac{2}{3}\) = \(\frac{2}{3}\) x \(\frac{6}{5}\) = \(\frac{4}{5}\) reciprocal of \(\frac{4}{5}\) = \(\frac{1}{\frac{4}{5}}\) = \(\frac{5}{4}\)

let x represent the total number of oranges shared, let the three boys be A, B and C respectively. A received \(\frac{1}{3}\) of x, Remainder = \(\frac{2}{3}\) of x . B received \(\frac{2}{3}\) of remainder (i.e.) \(\frac{2}{3}\) of x ∴ C received \(\frac{2}{3}\) of remainder (\(\frac{2}{3}\) of x) = 12 \(\frac{1}{3}\) x \(\frac{2x}{3}\) = 12 2x = 108 x = 54

\(\frac{(P- Q)^3 + S^2}{R^3}\) = \(\frac{(18 - 21)^3 + (-4)^2}{(-6)^3}\) = \(\frac{-27 + 16}{R^3}\) = \(\frac{-11}{-216}\) = \(\frac{11}{216}\)

\(\frac{0.0324 \times 0.00064}{0.48 \times 0.012}\) = \(\frac{324 \times 10^{-4} \times 10^{-5}}{48 x 10^{-2} x 12 x 10^{-3}}\) \(\frac{324 \times 64 \times 1 0^{-9}}{48 \times 12 \times 10^{-5}}\) = 36 x 10-4 = 3.6 x 10-3

S.I = \(\frac{PTR}{100}\) R = \(\frac{100}{PT}\) \(\frac{100 \times 50}{150 \times 6}\) = \(\frac{22}{3}\) = 7\(\frac{1}{3}\)%