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Physics
UTME / JAMB 1987
Elasticity, Density, Pressure & Fluids
Solution
A load of 5N gives an extension of 0.56cm in a wire which obeys Hooke's law. What is the extension caused by a load of 20N?
A
1.12cm
B
2.14cm
C
2.24cm
D
2.52cm
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
\(\frac{F_1}{e_1}\) = \(\frac{F_2}{e_2}\)
\(\frac{5}{0.56}\) = \(\frac{20}{e_2}\)
e2 = 2.24cm
Source: Myschool Past Questions Archive (Record #28409)
Physics
UTME / JAMB 1987
Equilibrium of Forces, Moments & Flotation
Solution
A cube of side 10cm and mass 0.5kg floats in a liquid with only \(\frac{1}{5}\) of its height above the liquid surface. What is the relative density of the liquid?
A
0.125
B
0.250
C
0.625
D
2.500
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Height below liquid = 1 - \(\frac{1}{5}\) = \(\frac{4}{5}\)
volume of cube = 10\(^3\)cm\(^3\)
volume of liquid displaced = \(\frac{4}{5}\) x 1000
= 800cm\(^3\)
density of liquid displaced;
= \(\frac{500}{800}\)
= 0.625
Source: Myschool Past Questions Archive (Record #28410)
Physics
UTME / JAMB 1987
Temperature, Thermometry & Thermal Expansion
Solution
The distance between the fixed points of a centigrade thermometer is 20cm. What is the temperature when the mercury level is 4.5cm above the lower mark?
A
22.5oC
B
29.0oC
C
90.0oC
D
100.0oC
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
20cm .... 100oC
4.5cm .... \(\theta\)
0cm ....0oC
\(\frac{4.5 - 0}{20 - 0}\) = \(\frac{0 - 0}{100 - 0}\)
\(\theta\) = 22.5oC
Source: Myschool Past Questions Archive (Record #28416)
Physics
UTME / JAMB 1987
Temperature, Thermometry & Thermal Expansion
Solution
The length of a side of a metallic cube at 20ºC is 5.0cm. Given that the linear expansivity of the metal is 4.0 x 10\(^{-5}\)k\(^{-1}\), find the volume of the cube at 120^\circC.
A
126.50cm3
B
126.25cm3
C
126.00cm3
D
125.00cm3
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Recall that: Volume = L * L * L → 5 * 5 * 5 = 125
Y = \(\frac{V_2 - V_1}{V_1 \times \theta}\)
3 x 4 x 10\(^{-5}\) = \(\frac{V_2 - 125}{125 \times (120 - 20)}\)
V\(_2\) = 126.50cm\(^{3}\)
Source: Myschool Past Questions Archive (Record #28418)
Physics
UTME / JAMB 1987
Elasticity, Density, Pressure & Fluids
Solution
As a result of air at the top of a barometer, the height of the mercury column is 73.5cm when it should be 75.0cm; the volume of the space above the mercury is 8.0cm3. Calculate the correct barometer height when the barometer reads 74.0cm and the volume of the space above the mercury is 6.0cm3.
A
72.0cm
B
74.5cm
C
75.1cm
D
76.0cm
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Using, P1V1 = P2V2
(75 - 73.5) x 8 = (X - 74) x 6
X = 76cm
Source: Myschool Past Questions Archive (Record #28420)
Physics
UTME / JAMB 1987
Waves, Sound & Vibrations
Which of the following statements supports the assumption that light travels in straight lines?
A
light can be diffracted
B
a source of light produces distinct shadows of opaque objects
C
a source of light produces interference patterns on a suitably placed screen
D
light can be reflected
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #28447)
Physics
UTME / JAMB 1987
Atomic, Quantum, Nuclear Physics & Electronics
Solution
When the length I of a piece of wire under constant tension is varied, the relationship of the frequency of the vibration f\(\alpha\)/ is
A
f\(\alpha\)/
B
f\(\alpha \frac{1}{I^2}\)
C
f \(\alpha\sqrt I\)
D
f\(\alpha \frac{1}{1}\)
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
F = \(\frac{1}{2L}\sqrt\frac{T}{m}\)
Source: Myschool Past Questions Archive (Record #28452)
Physics
UTME / JAMB 1987
Current Electricity & Electric Circuits
Solution
If an object is placed in front of two mirrors inclined at 90o, how many images will be formed?
A
five
B
four
C
three
D
two
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
n = \(\frac{360}{\theta}\) - 1
= \(\frac{360}{90}\) - 1
= 3 images
Source: Myschool Past Questions Archive (Record #28454)
Physics
UTME / JAMB 1987
Lenses & Optical Instruments
Solution
An object 3.0cm high is placed 60.0cm from a converging lens whose focal length is 20.0cm. Calculate the size of the image formed
A
0.5cm
B
1.5cm
C
2.0cm
D
6.0cm
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
F = \(\frac{UV}{U + V}\)
20 = \(\frac{60 \times V}{60 + V}\)
V = 30cm
similarly, \(\frac{U}{V}\) = \(\frac{\text{height of object}}{\text{height of image}}\)
\(\frac{60}{30}\) = \(\frac{3}{h}\)
h = 1.5cm
Source: Myschool Past Questions Archive (Record #28457)
Physics
UTME / JAMB 1987
Reflection, Refraction & Dispersion of Light
Solution
A pool of water appears to be 1.0m deep when viewed vertically from above. If the refractive index of water is 1.33, what is the actual depth of the pool?
A
0.750m
B
1.013m
C
1.330m
D
13.3000m
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
n = \(\frac{\text {real depth}}{\text{apparent depth}}\)
1.33 = \(\frac{\text {real depth}}{1}\)
real depth = 1.33cm
Source: Myschool Past Questions Archive (Record #28462)
Physics
UTME / JAMB 1987
Calorimetry, Latent Heat & Change of State
Solution
Calculate the amount of heat required to convert 2kg of ice at 2oC to water at 0oC. [specific heat capacity of ice = 2090Jkg-1 oC-1, specific latent heat of fusion of ice = 333kJkg-1]
A
666J
B
8360J
C
666 000J
D
674 360J
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Q = mL + mc\(\theta\)
= (2 x 333000) + (2 x 2090 x 2)
= 674 360J
Source: Myschool Past Questions Archive (Record #28435)
Physics
UTME / JAMB 1987
Waves, Sound & Vibrations
Solution
A wave has a frequency of 2Hz and a wavelength of 30cm. The velocity of the wave is
A
60.0ms-1
B
6.0ms-1
C
1.5ms-1
D
0.6ms-1
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
V = F\(\lambda\)
= 2 x 0.3
= 0.6ms-1
Source: Myschool Past Questions Archive (Record #28436)
Physics
UTME / JAMB 1987
Waves, Sound & Vibrations
Solution
A boat at anchor is rocked by waves whose crest are 100m apart and whose velocity is 25ms-1. At what interval does the wave crest reach the boat?
A
2500.00s
B
75.00s
C
4.00s
D
0.25s
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Distance between the boat and crest = 100m
time = \(\frac{100}{25}\)
= 4sec
Source: Myschool Past Questions Archive (Record #28437)
Physics
UTME / JAMB 1987
Current Electricity & Electric Circuits
Which of the following instruments has a pure tone?
A
guitar
B
vibrating strings
C
tuning fork
D
siren
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #28438)
Physics
UTME / JAMB 1987
Current Electricity & Electric Circuits
Solution
Hot water is added to three times its mass of water at 10oC and the resultant temperature is 20oC. What is the initial temperature of the hot water?
A
100oC
B
80oC
C
50oC
D
40oC
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Heat loss = heat gained
mh x ch x \(\theta\)h = mc x cc x \(\theta\)c
mh x ch x (\(\theta\) - 20) = mc x cc x (20 - 10)
ch = cc ; mc = 3mh
(\(\theta\) - 20) = 3( 20 - 10)
\(\theta\) = 30 + 20
therefore, \(\theta\) = 50ºC
Source: Myschool Past Questions Archive (Record #28421)