Question Library
Browse, filter, and study verified past examination questions with step-by-step mathematical reasoning.
Searching 18,000+ Questions...
Sifting topics, KaTeX formulas & verified solutions
Showing 11971–11985 of 14893 verified questions
Sort by:
Mathematics
UTME / JAMB 1987
Mensuration (Areas, Perimeters & Volumes)
Diagram
Solution
In the figure, PQRS is a rectangle. If the shaded area is 72 sq. cm, find h.
Attached Figure / Diagram
A
12cm
B
10cm
C
8cm
D
5cm
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
From the diagram, PQRS is a rectangle
Area of shaded part = 72sq.cm
But 72 = 3h - 4 + 6h - 4 + 4h
= 72 - 16h - 8
= 16h - 72 + 8
=16h = 80
h = \(\frac{80}{16}\)
= 5cm
Source: WAEC / JAMB / NECO Classroom Archive (Record #54911)
Physics
UTME / JAMB 1987
Equilibrium of Forces, Moments & Flotation
Diagram
Solution
the fig above shows two connected bodies of masses M\(_1\) and M\(_2\) in equilibrium under gravity. The tension in the upper string is
Attached Figure / Diagram
A
(m\(_1\)-m\(_2\))g
B
m\(_1\)g
C
m\(_2\)g
D
(m\(_1\)+m\(_2\))g
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
T = W but W = W\(_1\) + W\(_2\) = (m\(_1\) + m\(_2\))g
Source: WAEC / JAMB / NECO Classroom Archive (Record #41660)
Physics
UTME / JAMB 1987
Magnetism, Electromagnetism & AC Circuits
Solution
When a transformer has more secondary windings than primary windings, it?
A
has a smaller secondary current
B
has a greater power output
C
is a step-down transformer
D
increases the total energy output
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
A transformer that increases the voltage from primary to secondary (more secondary winding turns than primary winding turns) is called a step-up transformer.
Source: WAEC / JAMB / NECO Classroom Archive (Record #28474)
Physics
UTME / JAMB 1987
Atomic, Quantum, Nuclear Physics & Electronics
Solution
Which of the following statements is TRUE of photoelectric effect?
A
it cannot occur in liquids
B
the energy of the emitted electrons is independent of the work function of the surface
C
the energy of the emitted electron depends on the wavelength of the incident light
D
the greater the intensity of the incuident light, the greater the incident of the emitted electron
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
The photoelectric effect is the emission of electrons when electromagnetic radiation, such as light, hits a material.
The frequency of the incident light on the substance determines the kinetic energy of the emitted electrons.
The number of electrons emitted and the intensity of light incident are proportional to each other.
Source: WAEC / JAMB / NECO Classroom Archive (Record #28480)
Physics
UTME / JAMB 1987
Waves, Sound & Vibrations
Solution
The lowest note emitted by a stretched string has a frequency of 40Hz. How many overtones are there between 40Hz and 150Hz?
A
1
B
2
C
3
D
4
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
The fundamental frequency (Fo) = 40Hz
First overtone f1 = 2 \(\times\) 40 = 80
Second overtone f2 = 3 \(\times\) 40 = 120
Third overtone f3 = 4 \(\times\) 40 = 160.
Hence there are just two overtones between 40Hz and 150Hz
Source: WAEC / JAMB / NECO Classroom Archive (Record #28441)
Chemistry
UTME / JAMB 1987
Periodic Table & Periodicity
Solution
The greater the different in electronegativity between bonded atoms, the?
A
lower the polarity of the bond
B
higher the polarity of the bond
C
weaker the bond
D
higher the possibility of the substance formed being a molecule
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Bond polarity and ionic character increase with an increasing difference in electronegativity.
The electronegativity (χ) of an element is the relative ability of an atom to attract electrons to itself in a chemical compound and increases diagonally from the lower left of the periodic table to the upper right.
Source: WAEC / JAMB / NECO Classroom Archive (Record #14584)
Chemistry
UTME / JAMB 1987
Non-Metals & Their Compounds
Diagram
Solution
The times taken for iodine to be liberated in the reaction between sodium thiosulphate and hydrochloric acid at various temperature are as follows. These results suggest that
Attached Figure / Diagram
A
for a 10o rise in temperature, rate of reaction is double
B
for a 10 o rise in temperature, rate of reaction is halved
C
time taken for iodine to appear does not depend on temperature
D
for a 10 o rise in temperature rate of reaction is tripled
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The iodine liberation process is significantly affected by the amount of acid, that of potassium iodide added, the waiting time for the liberation, and light; therefore, the process plays a key role for the accuracy of the titration results.
For a 10\(^0\) rise in temperature, time of reaction is halved i.e as temperature increases from 25 - 35, time of reaction is halved from 72 to 36.
However, recall that rate of reaction = \(\frac{1}{time of reaction}\)
⇒ They are inversely proportional. Which means for a 10\(^0\) rise in temperature, if time of reaction is halved, then rate of reaction will be doubled.
Source: WAEC / JAMB / NECO Classroom Archive (Record #31380)
Mathematics
UTME / JAMB 1987
Number Bases & Modular Arithmetic
Solution
Convert 241 in base 5 to base 8,
A
718
B
1078
C
1768
D
2418
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
2415 = 2 x 52 + 4 x 5 + 1 x 5 + 1 x 5o
50 + 20 + 1 = 7110
Convert 7110 to base 8
\(\begin{array}{c|c} 8 & 71 \\ 8 & 8 R 7\\8 & 1 R 0\\8 & 0 R 1\end{array}\)
= 1078
Source: Myschool Past Questions Archive (Record #31788)
Mathematics
UTME / JAMB 1987
Fractions, Decimals, Percentages & Approximations
Solution
Find the least length of a rod which can be cut into exactly equal strips, each of either 40cm or 48cm in length
A
120cm
B
240cm
C
360cm
D
480cm
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
The least length is \(\frac{40}{48}\) = \(\frac{5}{8}\)
for the rod to be cut in exactly equal trips
Ratio \(\frac{5}{6}\) : \(\frac{48}{40}\)
\(\frac{\frac{5}{6}}{\frac{40}{48}}\) = 1
\(\frac{5}{6}\) x \(\frac{48}{40}\) = \(\frac{240}{240}\) = 1
The least length = 240cm
Source: Myschool Past Questions Archive (Record #31794)
Mathematics
UTME / JAMB 1987
Plane Geometry, Polygons & Circle Theorems
Solution
A rectangular lawn has an area of 1815 square yards. if its length is 50 meters, find its width in meters given that 1 metre equals 1.1 yards
A
39.93
B
35.00
C
33.00
D
30.00
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
1m = 1.1 yard, length(L)= 50m
= (50 x 1.1)yards
= 55 yards
Area(A) = length(L) y width (W)
1815 = 55y width (W)
width (w) = \(\frac{1815}{55}\)
= 33 yards
But 33 yards = 30 meters
Source: Myschool Past Questions Archive (Record #31800)
Mathematics
UTME / JAMB 1987
Fractions, Decimals, Percentages & Approximations
Solution
Reduce each number to two significant figures and then evaluate \(\frac{0.021741 \times 1.2047}{0.023789}\)
A
0.8
B
0.9
C
1.1
D
1.2
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
\(\frac{0.021741 \times 1.2047}{0.023789}\) = \(\frac{0.022 \times 1.2}{0.024}\) (to 216)
= \(\frac{0.0264}{0.024}\)
= 1.1
Source: Myschool Past Questions Archive (Record #31803)
Mathematics
UTME / JAMB 1987
Linear, Simultaneous & Quadratic Equations
Solution
A train moves from P to Q at an average speed of 90km/h and immediately returns from Q to P through the same route at an average speed of 45km/h. Find the average speed for the entire journey
A
55.00km/h
B
60.00km/h
C
67.50km\h
D
75.00km\h
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
Let the distance from P to Q = d km
(We don't need the actual value of d — it will cancel out.)
Time taken from P to Q = \(\frac{\text{d}}{90}\) hours
Time taken from Q to P = \(\frac{\text{d}}{45}\) hours
Total distance travelled = d + d = 2d km
Total time taken = \(\frac{\text{d}}{90}\) + \(\frac{\text{d}}{45}\)
= \(\frac{\text{d}}{90}\) + \(\frac{2d}{90}\) = \(\frac{3d}{90}\)
= \(\frac{\text{d}}{30}\) hours
Average speed = \(\frac{\text{total distance}}{\text{total time}}\)
= 2d \div (\(\frac{\text{d}}{30}\)) = 2d \times (\(\frac{30}{\text{d}}\)) = 60 km/h
Source: Myschool Past Questions Archive (Record #31804)
Mathematics
UTME / JAMB 1987
Fractions, Decimals, Percentages & Approximations
Solution
If the length of a square is increased by 20% while while its width is decreased by 20% to form a rectangle, what is the ratio of the area of the rectangle to the area of the square?
A
6 : 5
B
25 : 24
C
5 : 6
D
24 : 25
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
Let the length of the square be \( L \). The area of the square is:
\(A_s = L^2\)
After modifications, the new length \( L_r \) and width \( W_r \) of the rectangle are:
\(L_r = 1.2L, \quad W_r = 0.8L\)
The area of the rectangle \( A_r \) is:
\(A_r = L_r \times W_r = (1.2L)(0.8L) = 0.96L^2\)
The ratio of the areas is:
\(\text{Ratio} = \frac{A_r}{A_s} = \frac{0.96L^2}{L^2} = 0.96\)
Thus, the ratio of the area of the rectangle to the area of the square is \( 0.96 \). Or \(\frac{96}{100}\) = 24:25
Source: Myschool Past Questions Archive (Record #31805)
Mathematics
UTME / JAMB 1987
Fractions, Decimals, Percentages & Approximations
Solution
Two brothers invested a total of N5,000.00 on a farm project, the farm yield was sold for N 15,000.00 at the end of the season. If the profit was shared in the ratio 2 : 3, what is the difference in the amount to profit received by the brothers?
A
N2,000.00
B
N4,000.00
C
N6,000.00
D
N10,000.00
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
Total amount invested by A and B = N5,000
farm yield was sold for N15,000.00
profit = 15,000.00 - 5,000.00
= N10,000.00
Profit was shared in ratio 2 : 3
2 + 3 = 5
A received \(\frac{2}{5}\) of profit = \(\frac{2}{5}\) x 10,000 = N4,000.00
A receive \(\frac{3}{5}\) of profit = \(\frac{3}{5}\) x 10,000 = N6,000.00
Difference in profit received = N6,0000 - N4,000.00
= N2,000.00
Source: Myschool Past Questions Archive (Record #31811)
Mathematics
UTME / JAMB 1987
Fractions, Decimals, Percentages & Approximations
Solution
A man invests a sum of money at 4% per annum simple invest. After 3 years, the principal amounts to N7,000.00. Find the sum invested
A
N7,840
B
N6,250.00
C
N616.00
D
N5,833.33
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
I = \(\frac{PRT}{100}\)
100(A - P) = prt
P = \(\frac{100A}{100 + RT}\)
= \(\frac{100 \times 7000}{100 + (4 \times 3)}\)
p = \(\frac{700,000}{112}\)
= N6,250.00
Source: Myschool Past Questions Archive (Record #31814)