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Physics
UTME / JAMB 1989
Waves, Sound & Vibrations
Solution
In a sound wave in air, the adjacent rarefactions and compressions are separated by a distance of 17cm. If the velocity of the sound wave is 340ms-1. Determine the frequency
A
10Hz
B
20Hz
C
1000Hz
D
5780Hz
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
\(\lambda\) = 2L
2 x 17 = 34cm
F = \(\frac{V}{\lambda}\)
= \(\frac{340}{34 \times 10^{-2}}\)
= 1000Hz
Source: Myschool Past Questions Archive (Record #28342)
Physics
UTME / JAMB 1989
Waves, Sound & Vibrations
Solution
Light of wavelength 5000 x 10-8cm travels in free space with a velocity of 3 x 108ms-1. What is its wavelength in glass of refractive index 1.5?
A
3333 x 10-8cm
B
5000 x 10-8cm
C
6666 x10-8cm
D
750010-8cm
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
n = \(\frac{\text{wavelength in space}}{\text{wavelength in glass}}\)
1.5 = \(\frac{5000 \times 10^{-8}}{\lambda g}\)
\(\lambda\)g = 3333 x 10-8cm
Source: Myschool Past Questions Archive (Record #28344)
Physics
UTME / JAMB 1989
Reflection, Refraction & Dispersion of Light
Solution
The magnification of the image of an object placed in front of a convex mirror is \(\frac{1}{3}\). If the radius of curvature of the mirror is 24cm, what is the distance between its object and its image?
A
8cm
B
16cm
C
24cm
D
32cm
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
F = uv ; v = 1u
12 = \(\frac{v + 3v}{v + 3v}\)
v = 16cm, u = 48cm
distance between U and V
= 48 - 16 =32cm
Source: Myschool Past Questions Archive (Record #28345)
Physics
UTME / JAMB 1989
Reflection, Refraction & Dispersion of Light
The plane mirrors in a kaleidoscope are usually placed
A
at an angle of 60o
B
parallel to one another
C
perpendicular to one another
D
at an angle of 45o
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #28347)
Physics
UTME / JAMB 1989
Current Electricity & Electric Circuits
When a number of identical small magnets are arranged in a line, the strength of the resultant magnet
A
ia largest when they are arranged end to end
B
is greatest when they are arrangedparallel with like poles adjacent to each other
C
depends only on the number of magnets provided they arev parallel
D
is greater when the magnets are arranged on a wooden surface than on a metaln surface
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #28354)
Physics
UTME / JAMB 1989
Magnetism, Electromagnetism & AC Circuits
Solution
A bar magnet is most effectively demagnetized by
A
placing it in a N - S position and hitting it with a hammer
B
subjecting it to an electric current from a battery
C
bringing its north pole in contact with the north pole of a very strong magnet
D
heating the magnet
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
the most effective way of demagnetizing a magnet is Electrical method. option c is not correct since battery instead of a solenoid . option A is another method but the placing of the magnet is wrong it should of have been in the east-west direction not north-south direction. option C is not a method. so that leaves us with OPTION d which is also a method of demagnetizing a method, so when a magnets are strongly heated they lose their magnetism. therefore OPTION D is correct.
Source: Myschool Past Questions Archive (Record #28355)
Physics
UTME / JAMB 1989
Current Electricity & Electric Circuits
Solution
The resistance of a 5m uniform wire of cross-sectional area 0.2 x 10-6m2 is 0.425. What is the resistivity of the material of the wire?
A
1.10 x 10-6\(\Omega\)m
B
4.25 x 10-6\(\Omega\)m
C
2.40 x 10-7\(\Omega\)m
D
1.70 x 10-8\(\Omega\)m
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Resistance = \(\frac{\text{ Resistivity x Area}}{Area}\)
= 0.425 x 0.2 x 10-6
= 1.7 x 10-8\(\Omega\)m
Source: Myschool Past Questions Archive (Record #28356)
Physics
UTME / JAMB 1989
Current Electricity & Electric Circuits
Solution
Three resistors, with substances 250\(\Omega\), 500\(\Omega\) and 1k\(\Omega\) are connected in series. A 6V battery is connected to either end of the combination. Calculate the pot3ential difference between the end of the 250\(\Omega\) resistor.
A
0.20V
B
0.86V
C
1.71V
D
3.43V
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Using voltage - divider method
v1 = \(\frac{(R_1)}{R_T}\)VT
= \(\frac{250}{1750}\) x \(\frac{6}{1}\)
= 0.86V
Source: Myschool Past Questions Archive (Record #28357)
Physics
UTME / JAMB 1989
Current Electricity & Electric Circuits
A calibrated potentiometer is used to measure the e.m.f. of a cell because the
A
internal resistance of a cell is small compared with that of the potentiometer
B
potentiometer has a linear scale
C
potentiometer takes no current from the cell
D
resistance of the potentiometer is less than that of a voltmeter
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #28358)
Physics
UTME / JAMB 1989
Current Electricity & Electric Circuits
Solution
An ammeter of resistance 1.0\(\Omega\) has a full-scale deflection of 50mA. Determine the resultant full-scale deflection of the meter when a shunt of 0.0111\(\Omega\) is connected across its terminals.
A
400mA
B
450mA
C
500mA
D
550mA
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
V = 0.1 x 50 x 10-3 = 5 x 10-3volts
RT = \(\frac{0.1 \times 0.0111}{0.1 + 0.0111}\)
= 9.99 x 10-3\(\Omega\)
V = IR \(\Rightarrow\) I
= \(\frac{5 \times 10^{-3}}{9.9 \times 10^{-3}}\)
= 0.5A ; = 500mA
Source: Myschool Past Questions Archive (Record #28359)
Physics
UTME / JAMB 1989
Current Electricity & Electric Circuits
Solution
The electrochemical equivalent of silver is 0.0012gC-1. If 36.0g of silver is to be deposited by electrolysis on a surface by passing a steady current for 5.0mins, the current must be
A
6000A
B
100A
C
10A
D
1A
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
m = Itz \(\Rightarrow\) I = m = \(\frac{36}{5\times 60 \times 0.0012}\)
= 100A
Source: Myschool Past Questions Archive (Record #28360)
Physics
UTME / JAMB 1989
Gas Laws & Heat Transfer
Solution
When a radiation strikes a metal surface, electrons may be ejected from the metal. The maximum kinetic energy which may be acquired by an ejected electron depend on the
A
intensity of the radiation
B
source of the radiation
C
wavelength of the radiation
D
detection device of the electron
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
The maximum kinetic energy of an emitted electrons is independent of the intensity of the incident light but proportional to the frequency ( wavelength) of incident light. increasing the intensity of light only increases the number of photo-electrons
Source: Myschool Past Questions Archive (Record #28361)
Physics
UTME / JAMB 1989
Atomic, Quantum, Nuclear Physics & Electronics
Solution
Which of the following is TRUE of the particles emitted in radioactive disintegration?
A
the beta particle is the helium nucleus H
B
the alpha particle is lighter than the beta particle
C
the alpha particle is deflected more than the beta particle in a magnetic field
D
the beta particle is deflected more than the alpha particle in a magnetic field
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Due to their significantly smaller mass, beta particles have much less inertia and are easily "pushed" by the magnetic force, leading to a much greater deflection (curved path) compared to the heavy, bulky alpha particles.
Source: Myschool Past Questions Archive (Record #28362)
Physics
UTME / JAMB 1989
Atomic, Quantum, Nuclear Physics & Electronics
Solution
Eight alpha decays and six beta decays are necessary before an atom of 2 \(^{238}_{92}U\) achieves stability. The final product in the chain has an atomic number of
A
70
B
78
C
82
D
90
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
U \(\to\) 8(\(^{4}_{2}He\)) + 6(\(^{0}_{-1}e\)) + \(^{b}_{a}X\)
92 = (8 X 2) + (6 X -1) + a
a = 82
Source: Myschool Past Questions Archive (Record #28363)
Physics
UTME / JAMB 1989
Atomic, Quantum, Nuclear Physics & Electronics
Solution
A beam of radiation is passed between a pair of charged plates as indicated in the fig above. Beam P is undetected While Q is deflected to the left. P and Q respectively should be
I.γ-rays \beta-rays
II. x-rays \beta-rays
III. γ-rays x-rays
IV. x-rays x-rays
A
I only
B
III only
C
I and II
D
III and IV
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
studying the charges of the Gamma, Alpha, Beta and X-rays, you find that both the x-rays and theGamma rays possess zero-charge hence they could pass the charged plate undetected while the beta rays are negatively charged hence will deflect towards the positive charge of the plate. Alpha rays, on the other hand, are poisitively charged hence, they deflect towards the negative charge.
Source: Official Exam / Past Question Archive