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Biology
UTME / JAMB 1990
Population Ecology, Habitats & Conservation
The salinity of a brackish enviroment
A
increases immediately after rain
B
increase at the end of rainy season
C
Decrease with increase in micro-organisms
D
increase during dry season
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #4552)
Biology
UTME / JAMB 1990
Adaptation & Evolution
Physiological adaptation to very dry condition in animals is called
A
hibernation
B
aestivation
C
rejuvenation
D
xeromorphism
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #4554)
Biology
UTME / JAMB 1990
Growth, Micro-organisms & Public Health
Which set of disease is spread mainly by insect vectors?
A
Cholera, tenia and gonorrhoea
B
Poliomyelitis, tuberculosis and syphilis
C
Cholera, malaria and tuberculosis
D
Malaria, cholera and river blindness
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #4555)
Biology
UTME / JAMB 1990
Variety of Organisms & Classification of Living Things
Which of the following constitute pollution?
A
Droppings from birds
B
loud disco sound
C
A pack of cigarettes
D
Refuse in an incinerator
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #4557)
Biology
UTME / JAMB 1990
Population Ecology, Habitats & Conservation
Solution
An acidic soil can be improved upon by
A
sedimentation
B
leaching
C
flocculation
D
watering
medium Difficulty
Verified Correct Answer: Option C
Biological Concept & Syllabus Guide
Flocculation is the process where fine, individual soil particles (like clay) clump together into larger aggregates or "flocs". In acidic soils, the high concentration of hydrogen ions (H\(^+\)) and aluminum ions (Al\(^{3+}\)) often causes soil dispersion, which damages the soil structure, reduces aeration, and slows down drainage.
When alkaline soil conditioners like lime—Calcium hydroxide, (Ca(OH)\(_2\)), or Calcium carbonate, (CaCO\(_3\))—are added to correct acidity, the calcium ions (Ca\(^{2+}\)) naturally promote flocculation.
Source: Myschool Past Questions Archive (Record #4558)
Biology
UTME / JAMB 1990
Growth, Micro-organisms & Public Health
Solution
What do bacteria in root nodules derive from the host plant?
A
Protection and minerals
B
Water and minerals
C
Carbonhydrates and water
D
Protection and carbohydrates
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
Bacteria in root nodules, specifically rhizobia, engage in a symbiotic (mutualistic) relationship with leguminous host plants. In this exchange, the plant undergoes photosynthesis to produce sugars (carbohydrates), such as malate and succinate, which it transports to the root nodules to provide the bacteria with energy for nitrogen fixation.
Moreover, the host plant forms a physical structure (the nodule) that provides a controlled, anaerobic environment. This protects the bacteria and their oxygen-sensitive nitrogenase enzymes. The bacteria, in return, convert atmospheric nitrogen into ammonia, a form the plant can use for growth.
Source: Myschool Past Questions Archive (Record #4559)
Biology
UTME / JAMB 1990
Basic Ecological Concepts, Ecosystems & Biomes
Free nitrogen is released to the atmosphere by
A
Nitrogen-fixing bacteria
B
nitrifying bacteria
C
denitrifying bacteria
D
saprophytic bacteria
medium Difficulty
Verified Correct Answer: Option C
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #4561)
Biology
UTME / JAMB 1990
Excretion & Homeostasis
Diagram
Which structure is the glomerulus?
Attached Figure / Diagram
A
5
B
3
C
2
D
1
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #15561)
Biology
UTME / JAMB 1990
Excretion & Homeostasis
Diagram
Solution
If the blood is too concentrated, more water is absorbed from?
Attached Figure / Diagram
A
5
B
4
C
3
D
1
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
When blood is too concentrated, the kidneys absorb more water from the proximal convoluted tubule (PCT) and the descending loop of the loop of Henle. The PCT reabsorbs a large portion of the water, and this is enhanced by the descending loop of the loop of Henle, which reabsorbs water to help concentrate the urine and rehydrate the body.
The proximal convoluted tubule is the first and primary site for water reabsorption, reabsorbing approximately 70% of the filtered water. This reabsorption is largely passive, creating an osmotic gradient that draws water out of the tubule.
Source: Myschool Past Questions Archive (Record #15562)
Biology
UTME / JAMB 1990
Nervous, Hormonal Coordination & Sense Organs
Diagram
All the cell bodies in the spinal cord are found in
Attached Figure / Diagram
A
1
B
2
C
3
D
4
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #15563)
Biology
UTME / JAMB 1990
Nervous, Hormonal Coordination & Sense Organs
Diagram
In a reflex action, impulse flows from
Attached Figure / Diagram
A
1 to 2
B
2 to 1
C
4 to 1
D
4 to 2
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #15564)
Biology
UTME / JAMB 1990
Variety of Organisms & Classification of Living Things
Solution
In a saprophyte, sex organs are produced in the
A
Gamotrophyte
B
Rhizoid
C
Protonema
D
Sporopyte
E
sporophyte
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
In the plant kingdom, sex organs (antheridia and archegonia) are produced by the gametophyte phase, which is the leafy stage in bryophytes like mosses, not the sporophyte phase (saprophyte).
Source: Official Exam / Past Question Archive
Biology
UTME / JAMB 1990
Variety of Organisms & Classification of Living Things
Solution
In a saprophyte, sex organs are produced in the
A
Gamotrophyte
B
Rhizoid
C
Protonema
D
Sporopyte
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
In the plant kingdom, sex organs (antheridia and archegonia) are produced by the gametophyte phase, which is the leafy stage in bryophytes like mosses, not the sporophyte phase (saprophyte).
Source: Myschool Past Questions Archive (Record #41346)
Mathematics
UTME / JAMB 1989
Statistics (Data Representation, Central Tendency & Dispersion)
Diagram
Solution
In a class of 30 students, the marks scored in an examination are displayed in the histogram. What percentage of the student scored more than 40%?
Attached Figure / Diagram
A
14%
B
40%
C
46\(\frac{3}{4}\)%
D
53\(\frac{1}{3}\)%
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
This histogram is transferred into this frequency table
\(\begin{array}{c|c} Marks & 20 & 40 & 60 & 80 & 100 \\ \hline students & 9 & 7 & 6 & 6 & 2\end{array}\)
Students who scored more than 40 = 6 + 6 + 2 = 14
i.e. \(\frac{14}{30}\) x 100% = 46\(\frac{3}{4}\)%
Source: WAEC / JAMB / NECO Classroom Archive (Record #32905)
Physics
UTME / JAMB 1989
Current Electricity & Electric Circuits
Diagram
Solution
The total power drawn from the cell in the circuit above is
Attached Figure / Diagram
A
12W
B
24W
C
32W
D
40W
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Total resistance = resistance in series + resistance in parallel
= 4 + (\(\frac{4 \times 4}{4 + 4}\)) = 6\(\Omega\)
Total power drawn = \(\frac{V^2}{\text{R}}\) = \(\frac{12^2}{6}\) = 24W
Source: WAEC / JAMB / NECO Classroom Archive (Record #41688)