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Physics
UTME / JAMB 1991
Current Electricity & Electric Circuits
Diagram
Solution
Find the tension T\(_1\) in the diagram above if the system is in equilibrium [G = 10ms\(^{-2}\)]
Attached Figure / Diagram
A
200/√3N
B
100/√3N
C
300/√3N
D
100N
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
The diagram transforms into the one above:
Tan 30º = \(\frac{\text{opp}}{\text{adja}}\) = \(\frac{T_1}{100}\)
But tan 30º = \(\frac{1}{\sqrt{3}}\)
\(\frac{1}{\sqrt{3}}\) = \(\frac{T_1}{100}\)
T\(_1\) = \(\frac{100}{\sqrt{3}}\)N
Source: Myschool Past Questions Archive (Record #41696)
Physics
UTME / JAMB 1991
Work, Energy, Power & Simple Machines
Diagram
A body is under action of a force F such that the force displacement graph of the body is semi circular as shown above. The work done on the body by the force in moving through 24 meters is
Attached Figure / Diagram
A
36π J
B
72π J
C
144π J
D
288π J
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #41697)
Physics
UTME / JAMB 1991
Current Electricity & Electric Circuits
Diagram
Solution
The internal resistance of each of the cells E\(^1\) and E\(^2\), shown in the figure above, is 2 Ohms. Calculate the total current in the circuit
Attached Figure / Diagram
A
0.80A
B
0.50A
C
0.40A
D
0.004A
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
The total internal resistance is \( r = 1 \, \Omega \) and the total resistance in the circuit is given by:
\(R = 4 + 1 = 5 \, \Omega\)
Using Ohm's law, we have:
\(V = I(R + r)\)
Substituting the values:
\(2 = I \cdot 5\)
Solving for \( I \):
\(I = \frac{2}{5} = 0.4 \, \text{A}\)
Source: Myschool Past Questions Archive (Record #41698)
Physics
UTME / JAMB 1991
Electrostatics & Capacitors
Diagram
Solution
The net capacitance of the circuit shown above is
Attached Figure / Diagram
A
8.0µF
B
6.0µF
C
4.0µF
D
2.0µF
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Capacitance in parallel.
\(C_4 = C_1 + C_2\) = 2 + 2 = 4µf.
\(\frac{1}{C_T} = \frac{ 1}{C_3} + \frac{1}{C_4}\)
= \(\frac{ 1}{4} + \frac{1}{4}\)
= \(\frac{ 1 + 1}{4}\)
\(\frac{1}{C_T} = \frac{2}{4}\)
\(C_T = \frac{4}{2}\) = 2µf.
Source: Myschool Past Questions Archive (Record #41699)
Physics
UTME / JAMB 1991
Current Electricity & Electric Circuits
Diagram
Solution
In the above circuit, The fuse wire melts when
Attached Figure / Diagram
A
K is Opened
B
K is closed
C
the 14 ohm resistor is doubled with k closed
D
the 6 ohm resistor is doubled with k closed
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
K is closed: This is when the current exceeds the 2 A rating of the fuse, causing it to melt.
Source: Myschool Past Questions Archive (Record #41700)
Chemistry
UTME / JAMB 1991
Nature of Matter & Separation Techniques
Which of the following can be obtained by fractional distillation?
A
Nitrogen from liquid air
B
Sodium chloride from sea water
C
Iodine from a solution of Iondine in carbon tetrachloride
D
Sulphur from a solution of sulphur incarbon disulphide
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #12974)
Chemistry
UTME / JAMB 1991
Organic Chemistry I: Hydrocarbons & Crude Oil
Which of the following are mixtures?
i, Petroleum
ii, Rubber latex
iii. Vulcanizer's solution
iv, Carbon (II)sulphide
A
i, ii and iii
B
i, ii and iv
C
i and ii only
D
i and iv
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #12975)
Chemistry
UTME / JAMB 1991
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
An iron ore is known to contain 70.0% Fe2O3. The obtain from 80kg of the ore is?
(Fe = 56, O = 16)
A
35.0 kg
B
39.2 kg
C
70.0 kg
D
78.4 kg
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
2Fe2O3 → 4Fe + 3O2
320g 224g 96g
(70) / (100) x (80) / (1) 56g
if 0.32kg of Fe293 contains 0.224 kg
Then 56kg will contain (56 x 0.224) / (0.32) =39.2 kg
Source: Myschool Past Questions Archive (Record #12981)
Chemistry
UTME / JAMB 1991
Particulate Nature of Matter, Laws & Formulae
Solution
In two separate experiments, 0.36g and 0.71g of chlorine combined with a metal X to give Y and Z respectively. An analysis showed that Y and Z contain 0.20g and 0.40g of X respectively. The data above represents the law of ?
A
multiple proportion
B
conservation of mass
C
constant composition
D
reciprocal proportion
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
0.36g of Cl combines with 0.2g of x
1g of Cl will combine with \(\frac{1 \times 0.2}{0.32}\) = 0.56
0.71g of U combines with 0.49g of x
1g of U will combine with \(\frac{1 \times 0.4}{71}\) = 0.56
Ratio 0.56 : 0.56 = 1:1
Source: Myschool Past Questions Archive (Record #12984)
Chemistry
UTME / JAMB 1991
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
30cm\(^3\) of oxygen at 10 atmospheres pressure is placed in a 20 cm\(^3\) container. Calculate the new pressure if temperature is kept constant?
A
6.7 atm
B
15.0 atm
C
60.0 atm
D
66. 0 atm
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
P\(_1\)V\(_1\) = P\(_2\)V\(_2\) (where T is kept constant)
30 x 10 = P\(_2\) x 20
P\(_2\) = \(\frac{30 \times 10}{20}\)
= 15.0 atm
Source: Myschool Past Questions Archive (Record #12985)
Chemistry
UTME / JAMB 1991
Kinetic Theory of Matter & Gas Laws
Solution
Calculate the volume of carbon (IV)oxide measured at s.t.p, produced when 1 kg of potassium hydrogen trioxocarbonate (IV) is totally decomposed by heat?
(G.M.V. at s.t.p 22.4 dm3, K = 39, O = 16, C = 12, H = 1)
A
28 dm3
B
56 dm3
C
112 dm3
D
196 dm3
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
2KHCOdm3 → K2CO3 + H2O + CO2
2(39 + 1 + 12 + 48) 22.4 dm3
200 g 22.4 dm3 of CO2
1000 g (1000) / (200) x 22.4 = 112 dm3
Source: Myschool Past Questions Archive (Record #12988)
Chemistry
UTME / JAMB 1991
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
A given quantity of a gas occupies a volume of 228 cm3 at a pressure of 750mm Hg. What will be its volume at atmospheric pressure?
A
220 cm3
B
225 cm3
C
230 cm3
D
235 cm3
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
P1V1 = P2V2 ∴ 750 x 228 = 760 V2
V2 = (750 x 228 cm3) / (760) = 225 cm3
Source: Myschool Past Questions Archive (Record #12989)
Chemistry
UTME / JAMB 1991
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
A sample of a gas exerts a pressure of 8.2 atm when confined in a 2.93 dm3 container at 20°C. The number of moles of gas in the sample is?
(R = 0.082 litre atm / deg mole)
A
1.00
B
2.00
C
3.00
D
4.00
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
PV = nRT
2.93 x 8.2 = 0.082 x 293 xn
∴ n = (2.93 x8.2) / (0.082 x 293)
n = 1
Source: Myschool Past Questions Archive (Record #12994)
Chemistry
UTME / JAMB 1991
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
Atoms of element X (with 2 electrons in the outer shell). combine with atoms of Y (with 7 electrons in the outer shell). Which of the following statements is FALSE? The compound formed?
A
has formula XY
B
is likely to be ionic
C
contains X2+ ions
D
contains Y- ions
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
The compound formed by a mixture of X and Y will be \(XY_{2}\) not XY.
Source: Myschool Past Questions Archive (Record #12997)
Chemistry
UTME / JAMB 1991
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
The ions X- and Y+ are isoelectronic, each containing a total of 10 electrons.
How many protons are in the nuclei of the neutral atoms of X and Y respectively?
A
10 and 10
B
9 and 9
C
11 and 9
D
9 and 11
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
X- means one excess electron, hence 9 protons while Y +/- means one deficit electron hence 11 protons X and Y = 9 and 11
Source: Myschool Past Questions Archive (Record #12999)