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Biology
UTME / JAMB 1994
Adaptation & Evolution
The mouth part of the insect is adapted for
A
biting and chewing
B
sucking and chewing
C
biting and sucking
D
piercing and sucking
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Official Exam / Past Question Archive
Biology
UTME / JAMB 1994
Variety of Organisms & Classification of Living Things
Diagram
The parts used for feeding is labelled
Attached Figure / Diagram
A
I
B
J
C
K
D
L
medium Difficulty
Verified Correct Answer: Option C
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #41370)
Biology
UTME / JAMB 1994
Adaptation & Evolution
Diagram
The mouth part of the insect is adapted for
Attached Figure / Diagram
A
biting and chewing
B
sucking and chewing
C
biting and sucking
D
piercing and sucking
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #41372)
Mathematics
UTME / JAMB 1993
Indices, Logarithms & Surds
Diagram
Solution
From the figure, calculate TH in centimeters
Attached Figure / Diagram
A
\(\frac{5}{\sqrt{3} + 1}\)
B
\(\frac{5}{\sqrt{3} - 1}\)
C
\(\frac{5}{\sqrt{3}}\)
D
\(\frac{\sqrt{3}}{5}\)
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
TH = tan 45o, TH = QH
\(\frac{TH}{5 + QH}\) = tan 30o
TH = (b + QH) tan 30o
QH = 56 (5 + QH) \(\frac{1}{\sqrt{3}}\)
QH(1 - \(\frac{1}{\sqrt{3}}\)) = \(\frac{5}{\sqrt{3}}\)
QH = \(\frac{5\sqrt{3}}{\sqrt{3}} - \frac{1}{\sqrt{3}}\)
= \(\frac{5}{\sqrt{3} - 1}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #33020)
Mathematics
UTME / JAMB 1993
Sets, Logic & Venn Diagrams
Diagram
Solution
The shaded portion in the venn diagram is
Attached Figure / Diagram
A
x \(\cap\) z
B
xo \(\cap\) y \(\cap\) z
C
x \(\cap\) yo \(\cap\) z
D
x \(\cap\) y \(\cap\) zo
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
The shaded part exists on x \(\cap\) z but not in y
Source: WAEC / JAMB / NECO Classroom Archive (Record #32991)
Physics
UTME / JAMB 1993
Lenses & Optical Instruments
Solution
The property of the eye known as its power of accommodation is controlled by the
A
pupil
B
virteous humour
C
iris
D
ciliary muscles
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
The ciliary body produces the fluid in the eye called aqueous humor.
It also contains the ciliary muscle, which changes the shape of the lens when your eyes focus on a near object.
This process is called accommodation.
Source: WAEC / JAMB / NECO Classroom Archive (Record #28008)
Chemistry
UTME / JAMB 1993
Nature of Matter & Separation Techniques
Solution
Which of the following substances is a mixture?
A
Sulphur powder
B
Bronze
C
Distilled water
D
Ethanol
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Bronze is a mixture of copper and tin. Water is a compound of the elements hydrogen and oxygen.
Source: WAEC / JAMB / NECO Classroom Archive (Record #13302)
Chemistry
UTME / JAMB 1993
Oxidation, Reduction & Redox Reactions
Solution
NH\(_3\) + H\(_3\)O\(^+\) → NH\(_4\)\(^+\) + H\(_2\)O. It may be deduced from the reaction above that?
A
a redox reaction has occurred
B
H3O+ acts as an oxidizing agent
C
H3O+ acts as an acid
D
water acts as an acid
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
In the reaction NH\(_3\) + H\(_3\)O\(^+\), H\(_3\)O\(^+\) acts as an acid, donating a proton (H\(^+\)) to NH\(_3\), which then becomes NH\(_4\)\(^+\).
According to Brønsted-Lowry Acid-Base Theory, an acid is a substance that donates a proton (H\(^+\)), while a base is a substance that accepts a proton.
H\(_3\)O\(^+\) (Hydronium Ion) is formed when a proton (H\(^+\)) is added to a water molecule (H\(_2\)O.).
In the reaction NH\(_3\) + H\(_3\)O\(^+\) → NH\(_4\)\(^+\) + H\(_2\)O, H\(_3\)O\(^+\) donates a proton (H\(^+\)) to NH\(_3\), forming NH\(_4\)\(^+\) and H\(_2\)O.
Source: WAEC / JAMB / NECO Classroom Archive (Record #13337)
Mathematics
UTME / JAMB 1993
Integration & Applications
Solution
Integrate \(\frac{1 - x}{x^3}\) with respect to x
A
\(\frac{x - x^2}{x^4}\) + k
B
\(\frac{4}{x^4} - \frac{3 + k}{x^3}\)
C
\(\frac{1}{x} - \frac{1}{2x^2}\) + k
D
\(\frac{1}{3x^2} - \frac{1}{2x}\) + k
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
\(\int \frac{1 - x}{x^3}\)
= \(\int^{1}_{x^3} - \int^{x}_{x^3}\)
= x-3 dx - x-2dx
= \(\frac{1}{2x^2} + \frac{1}{x}\)
Source: Myschool Past Questions Archive (Record #31059)
Mathematics
UTME / JAMB 1993
Number Bases & Modular Arithmetic
Solution
change 7110 to base 8
A
1078
B
1068
C
718
D
178
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
\(\begin{array}{c|c} 8 & 71 \\ 8 & 8 \text{rem} 7\\ 8 & 1 \text{rem} 0\end{array}\)
= 1078
Source: Myschool Past Questions Archive (Record #31127)
Mathematics
UTME / JAMB 1993
Fractions, Decimals, Percentages & Approximations
Solution
Evaluate \(\frac{3524}{0.05}\) correct to 3 significant figures
A
705
B
70,000
C
70, 480
D
70, 500
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
\(\frac{3524}{0.05}\) = 70480
\(\approx\) 70500(3 s.g)
Source: Myschool Past Questions Archive (Record #31128)
Mathematics
UTME / JAMB 1993
Indices, Logarithms & Surds
Solution
If 9\(^{(x - \frac{1}{2})} = 3^{x^2}\) Find the value of x
A
\(\frac{1}{2}\)
B
1
C
2
D
3
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
9(x - \(\frac{1}{2}\)) 3x2 = 3\(^{2(x - \frac{1}{2})}\) = 3\(^x{^2}\)
∴ 2(x - \(\frac{1}{2}\)) = x2
2x - 1 = x\(^2\)
hence x\(^2\) - 2x + 1 = 0
(x - 1)(x - 1) = 0
x = 1
Source: Myschool Past Questions Archive (Record #31130)
Mathematics
UTME / JAMB 1993
Indices, Logarithms & Surds
Solution
Solve for y in the equation 10\(^y\) x 5\(^{(2y - 2)}\) x 4\(^{(y - 1)}\) = 1
A
\(\frac{3}{4}\)
B
\(\frac{5}{4}\)
C
\(\frac{2}{3}\)
D
5
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
10\(^y\) x 5\(^{(2y - 2)}\) x 4\(^{(y - 1)}\) = 1
but 10\(^y\) = (5 x 2)\(^y\) = 5\(^y\) x 2\(^y\)
= (Law of indices)
5\(^y\) x 2\(^y\) x 5\(^{(2y - 2)}\) x 4\(^{(y - 1)}\) = 1
but 4\(^{(y - 1)}\) = 2\(^{2(y - 1)}\)
= 2\(^{2y - 2}\) (Law of indices)
5\(^y\) x 5\(^{(2y -2)}\) x 2\(^{(2y- 2)}\) x 2\(^y\) = 1
5\(^{(3y -2)}\) x 2\(^y\) x 2\(^{(2y -2)}\) = 1
= 5\(^{(3y -2)}\) x 2\(^{(3y -2)}\) = 1
But a\(^o\) = 1
10\(^{(3y -2)}\) = 10\(^o\)
3y - 2 = 0
∴ y = \(\frac{2}{3}\)
Source: Myschool Past Questions Archive (Record #31135)
Mathematics
UTME / JAMB 1993
Plane Geometry, Polygons & Circle Theorems
Solution
simplify \(\frac{1}{√3 - 2}\) - \(\frac{1}{√3 + 2}\)
A
3
B
\(\frac{2}{3}\)
C
7
D
-4
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
\(\frac{1}{√3 - 2}\) - \(\frac{1}{√3 + 2}\)
L.C.M = (3- 2) (3 + 2)
∴ \(\frac{1}{\sqrt{3 - 2}}\) - \(\frac{1}{\sqrt{3 - 2}}\) = \(\frac{\sqrt{3 + 2} - \sqrt{3 - 2}}{\sqrt{3 - 2} + \sqrt{3 - 2}}\)
\(\frac{√3 + 2 - √3 + 2}{3 - 2√3 + 2√3 - 4}\) = \(\frac{4}{3 - 2}\)
= \(\frac{4}{-1}\)
= -4
Source: Myschool Past Questions Archive (Record #31138)
Mathematics
UTME / JAMB 1993
Indices, Logarithms & Surds
Solution
If 2log3 y + log3 x2 = 4, then y is
A
4 - log3
B
\(\frac{4}{log_3 x}\)
C
\(\frac{4}{x}\)
D
\(\pm\) \(\frac{9}{x}\)
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
2log3y + log3x2 = 4
log3y2 + log3x2 = 4
∴ log3 (x2y2) = log381(correct all to base 4)
x2y2 = 81
∴ xy = \(\pm\)9
∴ y = \(\pm\)\(\frac{9}{x}\)
Source: Myschool Past Questions Archive (Record #31142)