Question Library

F \(\alpha\) \(\frac{1}{L}\)

\(\lambda\) = 4L = 4 X 45 = 180cm F = \(\frac {V}{\lambda}\) = \(\frac {360}{180 \times 10^{-2}}\) = 200Hz

F = \(\frac {1}{2L}\) \(\sqrt\frac{T}{m}\) T2 = 4T1 ; L2 = 2L1 \(\frac{2F_1L_1}{2F_2L_2}\) = \(\sqrt\frac{T_1}{T_2}\) \(\frac{400\times L_1}{F \times L_1}\) = \(\sqrt\frac{T_1}{4T_1}\) F = 400Hz

No expanded working has been attached for this question yet. The verified answer is Option A.

The frequency of light is constant across different media, so the frequency remains 6.0 x 10\(^{14}\) Hz

No expanded working has been attached for this question yet. The verified answer is Option C.

V = -2u F = \(\frac{uv}{u + v}\) 20 = \(\frac{uv - 2u}{u - 2u}\) u = 10cm

1.5 = \(\frac{3}{\text {apparent displacement}}\) Apparent depth = 2cm displacement = 3 - 2 = 1cm

the object is always located between the optical center of the lens and twice the focal length. or the object is placed at a point between F and 2F to produce a real, enlarged, upright image of the inverted object.

Yellow light is a mixture of red and green light, so yellow will reflect both red and green light. This means that a yellow object will appear red under red light and green under green light. So, the green stripes on the flag will appear green under yellow light, as green is part of yellow. The white stripe will look yellow because it reflects all colors. Thus, when viewed under pure yellow light, the Nigerian flag will show green, yellow, and green.

No expanded working has been attached for this question yet. The verified answer is Option C.

They are all charged either positively or negatively

Energy = \(\frac{1}{2}\)CV2 = \(\frac{1}{2}\) x 8 x 10-6 x (100)2 = 4 x 10-2J

P1 = \(\frac{V^2_1}{R_1}\) and P2 = \(\frac{V^2_2}{R_2}\) P1R1 = P2R2 4P1 = 5P2 \(\frac{p_1}{p_2}\) = \(\frac{5}{4}\) = 5 : 4

Diaphragm: Found in both the receiver and the microphone; it vibrates to convert sound waves into electrical signals in the microphone and back into sound in the receiver. Soft iron pole pieces: Used in microphones to direct the magnetic field, but not found in the receiver. Permanent magnet: Present in the receiver, where it converts electrical signals back into sound, but not found in carbon microphones. Carbon blocks: These are used in carbon microphones to convert sound into electrical signals; they are not found in the receiver. In a telephone handset, the following components are found in the receiver but not in the microphone: ii. Soft iron pole pieces iii. Permanent magnet