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Physics
UTME / JAMB 1994
Equilibrium of Forces, Moments & Flotation
A cone in an unstable equilibrium has its potential energy
A
decreased
B
increased
C
unchanged
D
oscillating
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #27867)
Physics
UTME / JAMB 1994
Newton's Laws, Momentum & Collisions
Solution
Calculate the magnitude of the force required to just move a 20kg object along a horizontal surface if the coefficient of friction is 0.2. [g = 10ms-2]
A
400.0N
B
40.0N
C
4.0N
D
0.4N
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
F = \(\mu\)mg
= 0.2 x 20 x 10
= 40N
Source: Myschool Past Questions Archive (Record #27869)
Physics
UTME / JAMB 1994
Work, Energy, Power & Simple Machines
Solution
Calculate the velocity ratio of a screw jack of pitch 0.3cm if the length of the tommy bar is 21cm
A
\(\frac{1}{140}\)\(\pi\)
B
14\(\pi\)
C
70\(\pi\)
D
140\(\pi\)
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
V.R = \(\frac{2\pi L}{p}\)
= \(\frac{2 \times \pi \times 2}{0.3}\)
V.R = 140\(\pi\)
Source: Myschool Past Questions Archive (Record #27880)
Physics
UTME / JAMB 1994
Elasticity, Density, Pressure & Fluids
Solution
A force of 15N stretches a spring to a total length of 30cm. An additional force of 10N stretches the spring 5cm further. Find the natural length of the spring
A
25.0cm
B
22.5cm
C
20.0cm
D
15.0cm
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
\(\frac{15}{30 - L}\) = \(\frac{10}{5}\)
L = 22.5cm
Source: Myschool Past Questions Archive (Record #27882)
Physics
UTME / JAMB 1994
Elasticity, Density, Pressure & Fluids
Which of these statements are TRUE of pressure in liquids? i. pressure acts equally in all direction. ii. pressure decreases with depth. iii. pressure at the same level of a liquid is the same. iv pressure is dependent on the cross-sectional area of the barometer tube
A
i, iii only
B
i, ii, iii only
C
i, iii, and iv only
D
i, ii, iii and iv
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #27883)
Physics
UTME / JAMB 1994
Equilibrium of Forces, Moments & Flotation
Solution
The mass of a specific gravity bottle is 15.2g when it is empty. it is 24.8g when filled with kerosene and 27.2g when filled with distilled water. Calculate the relative density of kerosene
A
1.25
B
1.10
C
0.90
D
0.80
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Masses of kerosene = 24.8 - 15.2
= 9.6
mass of H2O = 27.2 - 15.2
= 12
R.d = \(\frac{9.6}{12}\) = 0.8
Source: Myschool Past Questions Archive (Record #27887)
Physics
UTME / JAMB 1994
Equilibrium of Forces, Moments & Flotation
Solution
If a solid X floats in liquids P of relative density 2.0 and in liquid Q of relative density 1.5, it can be inferred that the
A
weight of P displaced is greater than that of Q
B
weight of P displaced is less than that of Q
C
volume of P displaced is greater than that of Q
D
volume of P displaced is less than that of Q
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
R.d \(\alpha\) weight of liquid displaced
\(\frac{\text {R.d of P}}{\text {R.d of Q}}\) = \(\frac{\text{weight of p displaced}}{\text{weight of Q displaced}}\)
\(\frac{2}{1.5}\) = \(\frac{\text {weight of p displaced}}{\text {weight of Q displaced}}\)
A solid floats when the weight of the liquid it displaces is equal to the weight of the solid.
The relative density indicates that liquid P is denser than liquid Q.
Conclusion: Since liquid P is denser, for the same volume of the solid X displaced, the weight of the liquid displaced will be greater in liquid P than in liquid Q.
Source: Myschool Past Questions Archive (Record #27889)
Physics
UTME / JAMB 1994
Calorimetry, Latent Heat & Change of State
Solution
The melting point of naphthalene is 78oC. What is this temperature in kelvin
A
100k
B
351k
C
378k
D
444k
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
T = 78 + 273
= 351k
Source: Myschool Past Questions Archive (Record #27898)
Physics
UTME / JAMB 1994
Current Electricity & Electric Circuits
Solution
A Motor Tyre is inflated to pressure of 2.0 x 105Nm-2 when the temperature of air is 27oC. What will be the pressure in it at 87oC assuming that the volume of the Tyre does not change?
A
2.6 x 105Nm-2
B
2.4 x 105Nm-2
C
2.2 x 105Nm-2
D
1.3 x 105Nm-2
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
\(\frac{p_1}{T_1}\) = \(\frac{p_2}{T_2}\)
\(\frac{2 \times 10^5}{27 + 273}\) = \(\frac{p_2}{87 + 273}\)
P2 = 2.4 x 105Nm-2
Source: Myschool Past Questions Archive (Record #27903)
Physics
UTME / JAMB 1994
Calorimetry, Latent Heat & Change of State
Solution
When 100g of liquids L1 at 78^\circC was mixed with Xg of liquid L2 at 50^\circC, the final temperature was 66^\circC. Given that the specific heat capacity of L2is half that of L1, find x
A
50g
B
100g
C
150g
D
200g
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Heat lost by L1 = heat gained by L2
cL1 = 2cL2
100 x 2cL2 x (78 - 66)
= xg x cL2 x (66 - 50)
xg = 150g
Source: Myschool Past Questions Archive (Record #27907)
Physics
UTME / JAMB 1994
Calorimetry, Latent Heat & Change of State
Solution
Heat is supplied to a test tube containing 100g of ice at its melting point. The ice melts completely in 1 min.What is the power rating of the source of heat? [Latent heat of fusion of ice = 336Jg-1]
A
336W
B
450W
C
560W
D
600W
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
p x t = heat energy
P x 1 x 60 = 100 x 336
p = 560W
Source: Myschool Past Questions Archive (Record #27908)
Physics
UTME / JAMB 1994
Calorimetry, Latent Heat & Change of State
If a room is saturated with water vapour, the temperature of the room must be
A
at 0oC
B
above the dew point
C
at 100oC
D
below or at the dew point
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #27909)
Physics
UTME / JAMB 1994
Gas Laws & Heat Transfer
Two similar kettles containing equal masses of boiling water are placed on a table. If the surface of one is highly polished and the surface of the other is covered with soot, Which of the following observations is correct
A
The two kettles will cool down at the same rate
B
the polished kettle cools down more quickly by conduction
C
the kettle covered with soot cools down more quickly because it is a good radiator
D
the kettle covered with soot cools down more quickly by the process of heat convection
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #27913)
Physics
UTME / JAMB 1994
Waves, Sound & Vibrations
Solution
The equation of transverse wave traveling along a string is given by Y = 0.3 sin(0.5x - 50t) where Y and X are in cm and t is in seconds.Find the maximum displacement of the particles from the equilibrium position
A
50.0cm
B
2.5 cm
C
0.5cm
D
0.3cm
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Y = 0.3 sin(0.5x - 50t) compare with,
y = A sin(kx - wt)
A = 0.3m
Source: Myschool Past Questions Archive (Record #27915)
Physics
UTME / JAMB 1994
Waves, Sound & Vibrations
Solution
The sound from a source travelled to the bottom of the sea and the echo was heard 4s later. If the speed of sound in sea water is 1500ms-1 the depth of the sea is
A
6000m
B
3000m
C
1500m
D
375m
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
t = 4s ; v = 150ms-1
depth = X ; but 2X = vt
X = \(\frac {vt}{2}\) = \(\frac {1500 \times 4}{2}\)
X = 3000m
Source: Myschool Past Questions Archive (Record #27916)