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English Language
UTME / JAMB 1997
Lexis, Structure & Register (Cloze & Vocabulary)
Fill each gap with the most appropriate option from the list following the gap.
The ..... of what she was cooking filled the whole compound?
A
fragrance
B
scent
C
aroma
D
smell
medium Difficulty
Verified Correct Answer: Option C
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #10894)
English Language
UTME / JAMB 1997
Question Tags, Modals & Pronouns
Fill each gap with the most appropriate option from the list following the gap.
I hope i have not ...... too much on your time?
A
invaded
B
encroached
C
intruded
D
trespassed
medium Difficulty
Verified Correct Answer: Option B
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #10896)
English Language
UTME / JAMB 1997
Lexis, Structure & Register (Cloze & Vocabulary)
Fill each gap with the most appropriate option from the list following the gap.
The exercise presented us with a lot of problems but later it was all ...... sailing?
A
plain
B
smooth
C
rough
D
tough
medium Difficulty
Verified Correct Answer: Option B
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #10897)
Physics
UTME / JAMB 1997
Reflection, Refraction & Dispersion of Light
Solution
In the diagram above, which of the angles \( \theta _1 \) , \( \theta _2 \) , \( \theta _3 \) and \( \theta _4 \) is the angle of deviation of the ray of light passing through the glass prism XYZ?
A
\( \theta _3 \)
B
\( \theta _2 \)
C
\( \theta _1 \)
D
\( \theta _4 \)
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
\( \theta _3 \) shows the angle of deviation
Source: Official Exam / Past Question Archive
Physics
UTME / JAMB 1997
Units, Measurements & Dimensional Analysis
Solution
At what respective values of X, Y and Z would the unit of force, the newton, be dimensionally equivalent to MxLyTz?
A
-1, 1, 2
B
1, 1, -2
C
1, -1, 2
D
-1, 1, -2
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
F = m (v-u)
= kg x m x S-2
= M1L1T-2
Source: Myschool Past Questions Archive (Record #27677)
Physics
UTME / JAMB 1997
Current Electricity & Electric Circuits
Solution
The distance x m travelled by a particle in time t seconds is described by the equation x = 10 + 12t\(^2\), Find the average speed of the particle between the time interval t = 2s and t = 5s
A
60 ms-1
B
72 ms-1
C
84 ms-1
D
108 ms-1
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
To find the average speed of the particle between \( t = 2 \) seconds and \( t = 5 \) seconds, we use the formula for average speed:
\(\text{Average Speed} = \frac{\Delta x}{\Delta t}\)
Calculate \( x \) at \( t = 2 \) seconds}
Using the equation \( x = 10 + 12t^2 \):
\(x(2) = 10 + 12(2^2) = 10 + 12(4) = 10 + 48 = 58 \, \text{m}\)
Calculate \( x \) at \( t = 5 \) seconds
\(x(5) = 10 + 12(5^2) = 10 + 12(25) = 10 + 300 = 310 \, \text{m}\)
Calculate \( \Delta x \) and \( \Delta t \)
\(\Delta x = x(5) - x(2) = 310 - 58 = 252 \, \text{m}\)
\(\Delta t = 5 - 2 = 3 \, \text{s}\)
Calculate the average speed
\(\text{Average Speed} = \frac{252 \, \text{m}}{3 \, \text{s}} = 84 \, \text{m/s}\).
Source: Myschool Past Questions Archive (Record #27678)
Physics
UTME / JAMB 1997
Work, Energy, Power & Simple Machines
Solution
A 5kg block is released from rest on a smooth plane inclined at an angle of 30o to the horizontal. What is the acceleration down the plane? [g = 10ms-2]
A
5.0 ms-2
B
5.8 ms-2
C
8.7 ms-2
D
25.0 ms-2
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
ma = mgsin\(\theta\)
a = \(\frac{5 {\times} 10 {\times} sin30}{t}\)
a = 5ms2
Source: Myschool Past Questions Archive (Record #27679)
Physics
UTME / JAMB 1997
Current Electricity & Electric Circuits
Solution
An arrow of mass 0.1kg moving with a horizontal velocity of 15ms-1 is shot into a wooden block of mass 0.4kg lying at rest on a smooth horizontal surface. Their common velocity after impact is
A
15.0 ms-1
B
7.5 ms-1
C
3.8 ms-1
D
3.0 ms-1
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
M1U1 + M2U2
= (m1 + m2)v
= \(\frac{(0.1 {\times} 15) + (0.4 {\times} 0)}{(0.1 + 0.4)}\)
v = 3ms-1
Source: Myschool Past Questions Archive (Record #27680)
Physics
UTME / JAMB 1997
Current Electricity & Electric Circuits
Solution
Two bodies X and Y are projected on the same horizontal plane, with the same initial speed but at angles 30 and 60 respectively to the horizontal. Neglecting air resistance, the ratio of the range of X to that of Y is
A
1:1
B
1:2
C
√3:1
D
√3
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Range = \(\frac{U^2sin2{\theta}}{g}\)
\(\frac{R_x}{R_y}\) = \(\frac{U^2_xsin60}{U^2_ysin120}\)
sin60o = sin120o
\(\frac{R_x}{R_y}\) = \(\frac{1}{1}\)
hence, = 1:1
Source: Myschool Past Questions Archive (Record #27681)
Physics
UTME / JAMB 1997
Circular Motion, Gravitation & Simple Harmonic Motion
Solution
Which of the following with respect to a body performing simple harmonic motion are in phase?
A
displacement and velocity of the body
B
displacement and force on the body
C
velocity and acceleration of the body
D
force acting on the body and the acceleration
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
In simple harmonic motion (SHM), the force acting on the body is directly proportional to its displacement from the equilibrium position and is in the opposite direction (according to Hooke's Law). This force results in an acceleration of the body, which is also directly proportional to its displacement but in the opposite direction. When the displacement of the body is maximum (either positive or negative), the force acting on it is also maximum, leading to maximum acceleration. Similarly, when the displacement is zero (at the equilibrium position), the force and acceleration are also zero. Thus, the force acting on the body and its acceleration are in phase, meaning they reach their maximum and minimum values simultaneously during the oscillatory motion.
Source: Myschool Past Questions Archive (Record #27682)
Physics
UTME / JAMB 1997
Current Electricity & Electric Circuits
Solution
A body of mass 2kg moving vertically upwards has its velocity increased uniformly from 10ms-1 to 40ms-1 in 4s. Neglecting air resistance, calculate the upward vertical force acting on the body.[g = 10 ms-1]
A
15N
B
20N
C
35N
D
45N
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
F = mg + ma
F = 2 [10 + \(\frac{(40 - 10)}{4}\)]
F = 35 N
Source: Myschool Past Questions Archive (Record #27683)
Physics
UTME / JAMB 1997
Circular Motion, Gravitation & Simple Harmonic Motion
Solution
A planet has mass m1 and is at a distance r, from the sun. A second planet has mass m2 = 10m1 and at a distance of r2 = 2r1 from the sun. Determine the ratio of the gravitational force experienced by the planets.
A
1 : 5
B
2 : 5
C
3 : 5
D
4 : 5
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
g = \(\frac{GM}{R^2}\)
\(\frac{G_1M_1}{r^2_1}\) = \(\frac{G_2M_2}{r^2_2}\)
\(\frac{G_1M_1}{r^2_1}\) = \(\frac{G_2 {\times}10 M_1}{(2r_1)^2}\)
\(\frac{G_1}{G_2}\) = \(\frac{2}{5}\)
Source: Myschool Past Questions Archive (Record #27684)
Physics
UTME / JAMB 1997
Work, Energy, Power & Simple Machines
Solution
An object of mass 100g projected vertically upwards from the ground level has a velocity of 20ms\(^{-1}\) at a height of 10m. Calculate its initial kinetic energy at the ground level.[g = 10ms\(^{-2}\), neglect air resistance]
A
10 J
B
20 J
C
30 J
D
50 J
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Using, v\(^2\) = u\(^2\) - 2gx
(20)\(^2\) = u\(^2\) - 2 x 10 x 10
u\(^2\) = 400 + 200 = 600(m/s\(^2\))
initial K.E = \(\frac{1}{2}\)mu\(^2\)
= \(\frac{1}{2}\) x 0.1 x 600
= 30 J
(100g = 0.1kg)
Source: Myschool Past Questions Archive (Record #27685)
Physics
UTME / JAMB 1997
Work, Energy, Power & Simple Machines
Solution
An electric water pump rate 1.5 kW, lifts 200kg of water through a vertical height of 6 meters in 10 seconds. What is the efficiency of the pump? [g = 10ms-2, neglecting air resistance]
A
90.0%
B
85.0%
C
80.0%
D
65.0%
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Efficiency = output x 100
= \(\frac{\frac{200 {\times} 10 {\times} {6}}{10}}{1500}\) x \(\frac{100}{1}\)
= 80%
Source: Myschool Past Questions Archive (Record #27686)
Physics
UTME / JAMB 1997
Elasticity, Density, Pressure & Fluids
Solution
A load of 20N on a wire of cross-sectional area 8 x 10-7m2, produces an extension of 10m2. calculate Young's modulus for the material of the wire if its length is 3m
A
7.0 x 1011Nm-2
B
7.5 x 1011Nm-2
C
8.5 x 1011Nm-2
D
9.0 x 1011Nm-2
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Young's modulus = \(\frac{F}{A}\) \(\div\) \(\frac{e}{L}\)
= \(\frac{20}{8 \times 10^{-7}}\) \(\div\) \(\frac{10^{-4}}{3}\)
= 7.5 x 1011Nm-2
Source: Myschool Past Questions Archive (Record #27687)