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Physics
UTME / JAMB 2024
Density and Relative Density
Solution
Calculate the upthrust on a spherical ball of volume 4.2 x 10\(^{-4}\)m\(^{3}\) when totally immersed in a liquid of density 1028kgm\(^{-3}\)
A
5.2N
B
4.3N
C
3.0N
D
2.4N
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Upthrust(Force) = volume of object x density of liquid x g = V x \(\rho\) x g
U = 4.2 x 10\(^{-4}\) x 1028 x 10 \(\approxeq\) 4.3N
Source: WAEC / JAMB / NECO Classroom Archive (Record #70529)
Physics
UTME / JAMB 2024
Deformation of Solids
Solution
The stress experienced by a wire of diameter \(\frac{\text{y}}{\pi}\)m loaded by a weight y\(^2\)N is
A
\(\pi\)Nm\(^{-2}\)
B
2\(\pi\)Nm\(^{-2}\)
C
4\(\pi\)Nm\(^{-2}\)
D
8\(\pi\)Nm\(^{-2}\)
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Stress = \(\frac{force}{area}\)
Force = weight = y\(^2\), Area = \(\pi\)r\(^2\), Diameter = \(\frac{\text{y}}{\pi}\)m ⇒ r = \(\frac{\text{y}}{2\pi}\)m
Stress = \(\frac{y^2}{\pi \times\frac{y^2}{(2\pi)^2}}\)
= \(\frac{y^2}{\pi y^2} \times 4(\pi)^2\) = 4\(\pi\)Nm\(^{-2}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #70351)
Physics
UTME / JAMB 2024
Deformation of Solids
Solution
The dimension of young's modulus,E is given by
A
MLT\(^{-1}\)
B
MT\(^{-2}\)
C
ML\(^{-1}\)T\(^{-2}\)
D
M\(^{-1}\)T
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Young's modulus E is given by the formula: E = \(\frac{\text{STRESS}}{\text{STRAIN}}\)
Stress = \(\frac{Force}{Area}\)
Dimension of force = MLT\(^{-2}\)
Dimension of Area = L\(^2\)
Dimension of strain = 1(dimensionless)
E = \(\frac{MLT^{-1}}{L^2}\) = ML\(^{-1}\)T\(^{-2}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #70371)
Physics
UTME / JAMB 2024
Deformation of Solids
Solution
The property by which a material returns to its original shape after the removal of force is called
A
Elasticity
B
Ductility
C
Malleability
D
Plasticity
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
The property described in this question is called Elasticity which is the ability of a substance to regain its original shape and size after the removal of the distorting force.
Source: WAEC / JAMB / NECO Classroom Archive (Record #70468)
Physics
UTME / JAMB 2024
Deformation of Solids
Solution
A force of 10N extends a spring of natural length 1m by 0.02m, calculate the length of the spring when the applied force is 40N.
A
0.08m
B
0.09m
C
1.08m
D
1.80m
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
F = ke
k = \(\frac{F_1}{e_1}\)
F\(_1\) = 10N, e\(_1\) = 0.02m
F\(_2\) = 40N, e\(_2\) = ?
\(\frac{F_1}{e_1}\) = \(\frac{F_2}{e_2}\)
\(\frac{10}{0.02}\) = \(\frac{40}{e_2}\)
e\(_2\) = \(\frac{40 \times 0.02}{10}\) = 0.08m
The new length = 1 + 0.08 = 1.08m
Source: WAEC / JAMB / NECO Classroom Archive (Record #70671)
Physics
UTME / JAMB 2024
Heat and Temperature
Solution
Pilots uses aneroid barometer to know the height above sea level because
A
Very accurate
B
Small and convenient
C
Heavy and huge
D
Costly
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Aneroid barometers are compact and lightweight, making them suitable for use in aircraft where space and weight are critical considerations. They provide a reliable measurement of altitude based on changes in atmospheric pressure.
Source: WAEC / JAMB / NECO Classroom Archive (Record #70361)
Physics
UTME / JAMB 2024
Heat and Temperature
Solution
A thick glass tumbler cracks when boiling water is poured into it because
A
The inside expands more rapidly than the outside
B
The inside expands less rapidly than the outside
C
The expansion is even
D
It does not expand
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
When boiling water is poured into the tumbler, the inner surface heats up and expands quickly, while the outer surface remains cooler and expands more slowly. This difference in expansion rates creates stress in the glass, leading to cracks.
Source: WAEC / JAMB / NECO Classroom Archive (Record #70406)
Physics
UTME / JAMB 2024
Heat and Temperature
Solution
A mass of gas at 40mmHg is heated from 298k to 348k at constant volume. Cal the pressure exerted by the gas.
A
50.21mmHg
B
46.71mmHg
C
42.35mmHg
D
35.12mmHg
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
From pressure law
\(\frac{P_1}{T_1} = \frac{P_2}{T_2}\)
P\(_2\) = \(\frac{P_1 \times T_2}{T_1}\)
P\(_1\) = 40mmHg, P\(_2\) = ?
T\(_1\) = 298k, T\(_2\) = 348k
\(\frac{40}{298} = \frac{P_2}{348}\)
P\(_2\) = \(\frac{40\times348}{298}\) = 46.71mmHg
Source: WAEC / JAMB / NECO Classroom Archive (Record #70409)
Physics
UTME / JAMB 2024
Heat and Temperature
Solution
The thermometer whose thermometric property is change in volume with temperature is
A
Resistance thermometer
B
Thermocouple
C
Bimetallic thermometer
D
Liquid-in-glass thermometer
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
D. Liquid-in-glass thermometer.
In a liquid-in-glass thermometer, the liquid (usually mercury or colored alcohol) expands and contracts with temperature changes, allowing for the measurement of temperature based on the volume change of the liquid.
Source: WAEC / JAMB / NECO Classroom Archive (Record #70411)
Physics
UTME / JAMB 2024
Heat and Temperature
Solution
Which of these gas laws is equivalent to workdone
A
Charle's law
B
Pressure law
C
Boyle's law
D
Gay Lussac's law
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Boyle's law states that at a constant temperature, the pressure of a gas is inversely proportional to its volume (P ∝\(\frac{1}{V}\) This relationship is fundamental when calculating the work done during the isothermal expansion or compression of a gas, as it directly involves changes in volume and pressure
Source: WAEC / JAMB / NECO Classroom Archive (Record #70415)
Physics
UTME / JAMB 2024
Heat and Temperature
Solution
The average translational kinetic energy of gas molecules depends on
A
Temperature only
B
Number of moles and temperature
C
Pressure and temperature
D
Pressure only
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Temperature only.
This means that the average kinetic energy is directly related to the gas's absolute temperature. The relationship can be defined by the equation:
K.E = \(\frac{3}{2}\)kT
where K.E = average kinetic energy, k = Boltzmann's constant, and T = absolute temperature.
Source: WAEC / JAMB / NECO Classroom Archive (Record #70424)
Physics
UTME / JAMB 2024
Heat and Temperature
Solution
Convert 60ºC to degree Fahrenheit
A
111.15\(^0\)F
B
115.56\(^0\)F
C
132.23\(^0\)F
D
140.00\(^0\)F
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Using \(^0\)F = ( \(^0\) C x \(\frac{9}{5}\)) + 32 → ( ºc x 1.8 ) + 32.
\(^0\) C = 60º
Then, Using \(^0\)F = ( 60 x \(\frac{9}{5}\)) + 32
= 108 + 32 = 140ºF
Source: WAEC / JAMB / NECO Classroom Archive (Record #70471)
Physics
UTME / JAMB 2024
Heat and Temperature
Solution
At absolute zero temperature, the average velocity of the molecules
A
Decreases
B
Increases
C
Is zero
D
Is uncertain
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Absolute zero is the lowest possible temperature where molecular motion is minimal. At this temperature, the kinetic energy of the molecules is effectively zero, meaning they do not have enough energy to move.
Source: WAEC / JAMB / NECO Classroom Archive (Record #70473)
Physics
UTME / JAMB 2024
Heat and Temperature
Solution
I It wets glass
II It needs to be coloured
III It has a low density
Water is not suitable for use as a thermometric liquid because
A
I only
B
I and II only
C
I, II, and III only
D
II and III only
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Water is not suitable for use as a thermometric liquid because:
a) It wets glass: This can cause issues with reading the level of the liquid.
b) It needs to be coloured: Water is typically clear, making it difficult to see the level without coloring.
c) It has a low density: This can affect the sensitivity and accuracy of the thermometer.
Source: WAEC / JAMB / NECO Classroom Archive (Record #70504)
Physics
UTME / JAMB 2024
Heat and Temperature
Solution
At a pressure of 10\(^5\)Nm\(^{-2}\), a gas has a volume of 20m\(^3\). Calculate the volume at 4 x 10\(^5\)Nm\(^{-2}\) at constant temperature.
A
2m\(^3\)
B
3m\(^3\)
C
4m\(^3\)
D
5m\(^3\)
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Using \(P_1\) \(V_1\) = \(P_2\) \(V_2\)
\(V_2\) = \(\frac{P_1\times V_2}{P_2}\)
\(V_2\) = \(\frac{10^5\times 20}{4 \times 10^5}\)
\(V_2\) = 5m\(^3\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #70530)