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Physics
UTME / JAMB 1998
Equilibrium of Forces, Moments & Flotation
Solution
The atmospheric pressure due to water is 1.3 x 106Nm-2. What is the total pressure at the bottom of an ocean 10m deep? [Density of water = 1000kgm-3, g = 10ms-2]
A
1.3 x 107Nm-2
B
1.4 x 106Nm-2
C
1.4 x 105Nm-2
D
1.0 x 10 5Nm-2
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Pressure = heg = 1000 x 10 x 10 = 105Nm-2
Total pressure = (1.3 x 106) + (1 x 105)
= 1.4 x 106Nm-2
Source: Myschool Past Questions Archive (Record #27615)
Physics
UTME / JAMB 1998
Equilibrium of Forces, Moments & Flotation
Solution
A solid of weight 0.600N is totally immersed in oil and water respectively. If the upthrust of oil is 0.210N and the relative density of oil is 0.875. Find the upthrust in water.
A
0.600N
B
0.360N
C
0.240N
D
0.180N
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Rd = \(\frac{\text{upthrust in oil}}{\text{upthrust in }H_2O}\)
thus; 0.875 = \(\frac{0.21}{\text{upthrust in }H_2O}\)
upthrust in H2O = 0.24N
Source: Myschool Past Questions Archive (Record #27617)
Physics
UTME / JAMB 1998
Temperature, Thermometry & Thermal Expansion
Solution
A platinum resistance thermometer records 3.0\(\Omega\) at 0oC and 8.0\(\Omega\) at 100oC. If it records 6.0\(\Omega\) in a certain environment, The temperature of the medium is
A
80oC
B
60oC
C
50oC
D
30oC
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
8\(\Omega\).....100oC
6\(\Omega\).....\(\theta\)oC
3\(\Omega\).....0oC
\(\frac{6 - 3}{8 - 3}\) = \(\frac{\theta - 0}{100 - 0}\)
therefore, \(\theta\) = 60oC
Source: Myschool Past Questions Archive (Record #27619)
Physics
UTME / JAMB 1998
Temperature, Thermometry & Thermal Expansion
Solution
The linear expansivity of brass is 2 x 10-5C-1. If the volume of a piece of brass is 15.00cm3 at 00C, What is the volume at 100oC?
A
16.03cm3
B
16.00cm3
C
15.09cm3
D
15cm3
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
linear expansivity = \(\frac {V_2 - V_1}{V_1 {\times} {\Delta}{\theta}}\)
3 x 2 x 10-5 =\(\frac {V_2 - 15}{15 {\times} (100 - 0)}\)
V2 = 15.09cm3
Source: Myschool Past Questions Archive (Record #27621)
Physics
UTME / JAMB 1998
Current Electricity & Electric Circuits
Solution
A gas has a volume of 100cm3 at 27oC. If it is heated to temperature T until a final volume of 120cm3 is attained, calculate T
A
33oC
B
60oC
C
87oC
D
114oC
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
\(\frac {V_1}{T_1}\) = \(\frac {V_2}{T_2}\)
\(\frac {100}{27 + 273}\) = \(\frac {120}{T + 273}\)
T = 87oC
Source: Myschool Past Questions Archive (Record #27624)
Physics
UTME / JAMB 1998
Current Electricity & Electric Circuits
Solution
A 500W heater is used to heat 0.6kg of water from 25ºC to 100ºC in t\(_1\) seconds. If another 1000W heater is used to heat 0.2kg of water from 10ºC to 100ºC in t\(_2\), seconds, find \(\frac{t_1}{t_2}\)
A
50
B
5
C
5/4
D
1/5
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Heat energy = Electrical energy
mc\(\theta\) = power x time
0.6 x c x (100 - 25) = 500 x t\(_1\)
and, 0.2 x c x (100 - 10) = 1000 x t\(_2\)
\(\frac {t_1}{t_2}\) = \(\frac{0.09}{0.018}\) = 5
Source: Myschool Past Questions Archive (Record #27630)
Physics
UTME / JAMB 1998
Calorimetry, Latent Heat & Change of State
Solution
How many grams of water at 17oC must be added to 42g of ice at 0oC to melt the ice completely? [specific latent heat of fusion of ice = 3.4 x 105Jkg-1, specific heat capacity of water = 4200Jkg-1k-1]
A
200g
B
300g
C
320g
D
400g
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Heat lost = Heat gained
mc\(\theta\) = mL
m x 4200 x 17 = 42 x 3.4 x 105
therefore, m = 200g
Source: Myschool Past Questions Archive (Record #27634)
Physics
UTME / JAMB 1998
Elasticity, Density, Pressure & Fluids
A vapour is said to be saturated when
A
more molecules return to the liquid than the amount that left it
B
a dynamic equilibrium exists between the molecules of the liquid and the vapour molecules at a given temperature
C
the vapour pressure is equal to the atmospheric pressure
D
all molecules are moving with the same speed in all directions at a given temperature
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #27635)
Physics
UTME / JAMB 1998
Current Electricity & Electric Circuits
One valid assumption of the kinetic theory of gasses is the
A
the molecules of a gas are constantly in a state of motion and the number of collision remains constant
B
the number of molecule of gas increases with increasing pressure
C
as the temperature increases, the number of collision made by the gas molecule remains constant
D
the molecules of gas are all identical and are very small in size
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #27637)
Physics
UTME / JAMB 1998
Waves, Sound & Vibrations
The physical properties of sound waves can best be described by
A
reflection and diffraction
B
polarization and reflection
C
polarization and diffraction
D
polarization and refraction
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #27639)
Physics
UTME / JAMB 1998
Waves, Sound & Vibrations
In a closed organ pipe producing a musical note, an antinode will always be produced at
A
the closed end
B
the open end
C
the middle
D
all the parts of the pipe
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #27640)
Physics
UTME / JAMB 1998
Waves, Sound & Vibrations
Solution
A steel wire of length 0.50m is stretched between two fixed points and its fundamental frequency is 200Hz. The speed of the wave in the wire is
A
100ms-1
B
120ms-1
C
200ms-1
D
250ms-1
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
In strings, \(\lambda\) = 2L
V = F\(\lambda\)
= 200 x 2 x 0.5
= 200ms-1
Source: Myschool Past Questions Archive (Record #27641)
Physics
UTME / JAMB 1998
Waves, Sound & Vibrations
Solution
In a resonance tube experiment, if the fundamental frequency of the vibrating air column is 280Hz, the frequency of the third overtone is
A
70Hz
B
840Hz
C
1120Hz
D
1960Hz
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
F3 = 7Fo
= 7 x 280
= 1960Hz
Source: Myschool Past Questions Archive (Record #27643)
Physics
UTME / JAMB 1998
Reflection, Refraction & Dispersion of Light
Solution
An object 0 lies at a distance m in front of concave mirror of focal length f. If m < f, then the final image obtained will be
A
virtual and diminished
B
magnified and erect
C
real and inverted
D
diminished and erect
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
In a concave mirror, when the object distance is less than the focal length, we have an image which is:
- Virtual
- Erect and
- Magnified.
Source: Myschool Past Questions Archive (Record #27646)
Physics
UTME / JAMB 1998
Reflection, Refraction & Dispersion of Light
Solution
An object is placed in front of two plane mirrors inclined at an angle of 0o. If the total number of images formed is 7, Find the value of \(\theta\)
A
30o
B
45o
C
51o
D
90o
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Number of image = \(\frac{360}{\theta}\) -1
7 = \(\frac{360}{\theta}\) -1
thus,\(\theta\) = 45o
Source: Myschool Past Questions Archive (Record #27649)