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Biology
UTME / JAMB 1999
Supporting Tissues & Skeletal System
Diagram
Solution
Which of the bones is the radius?
Attached Figure / Diagram
A
I
B
II
C
III
D
IV
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
The radius bone is one of two major bones in the forearm. It extends from the elbow to the wrist and provides the base for muscular attachments of the forearm.
Source: Myschool Past Questions Archive (Record #6116)
Biology
UTME / JAMB 1999
Adaptation & Evolution
Solution
The least adaptive feature of aboreal life is the
A
possession of four limbs
B
possession of claws
C
development of long tail
D
shading of coat colour
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
Arboreal life refers to animals that live primarily in trees. The possession of four limbs is considered the least adaptive feature because it is a general trait shared by almost all tetrapods, regardless of whether they live on land, in water, or in trees. It is not a specialized adaptation specifically evolved for or unique to tree-dwelling survival.
Source: Myschool Past Questions Archive (Record #6129)
Biology
UTME / JAMB 1999
Adaptation & Evolution
Which of the following is one of Lamarck's theories?
A
Some variations are more favourable to existence in a given environment than others
B
All living organisms are constantly involved in a struggle to existence
C
The size of a given population remains fairly constant
D
New species originates through the inheritance of acquired traits
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #6130)
Biology
UTME / JAMB 1999
Variety of Organisms & Classification of Living Things
The loud cry made by a brooding hen when a predator is around is meant to
A
alert the poultry attendants
B
attract cocks to come and fight the predator
C
advertise the boundaries of its territory to intruders
D
warn its chicks and other chickens of impending danger
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #6131)
Biology
UTME / JAMB 1999
Variety of Organisms & Classification of Living Things
The most important environment factor which epiphytes in the rain forest compete for is
A
water
B
nutrients
C
light
D
cabinet minister
E
space
medium Difficulty
Verified Correct Answer: Option C
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #6132)
Biology
UTME / JAMB 1999
Variety of Organisms & Classification of Living Things
The biomass is likely to increase in the sequence
A
1→2→4→5
B
1→3→4→5
C
3→5→6→7
D
5→4→3→1
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Official Exam / Past Question Archive
Biology
UTME / JAMB 1999
Digestive System & Feeding Mechanisms
The habitat of the cysticercus of taenia solium is
A
Alimentary canal of cattle
B
Muscles of pig
C
Alimentary canal of pig
D
Muscles of cattle
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #41397)
Mathematics
UTME / JAMB 1999
Plane Geometry, Polygons & Circle Theorems
Solution
If \(\frac{^6C_r}{^6P_r}\) = \(\frac{1}{6}\), find the value of r.
A
1
B
3
C
5
D
6
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
Given: \(\frac{^6C_r}{^6P_r} = \frac{1}{6}\)
Recall the formulas:
\(^nC_r = \frac{n!}{r!(n-r)!}, \quad ^nP_r = \frac{n!}{r!}\)
Substitute \( n = 6 \):
\(\frac{^6C_r}{^6P_r} = \frac{\dfrac{6!}{r!(6-r)!}}{\dfrac{6!}{r!}} = \frac{6!}{r!(6-r)!} \times \frac{r!}{6!} = \frac{1}{(6-r)!}\)
So the equation simplifies to:
\(\frac{1}{(6-r)!} = \frac{1}{6}\)
Therefore: (6-r)! = 6
We know that 3! = 6, so:
6 - r = 3 \(\implies\) r = 3
Source: Myschool Past Questions Archive (Record #77196)
Mathematics
UTME / JAMB 1999
Statistics (Data Representation, Central Tendency & Dispersion)
Solution
The mean of four numbers is 5, and the mean deviation is 3. Find the fourth number if the mean deviation of the first three numbers is 2
A
6
B
10
C
11
D
12
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
Let the four numbers be \(a, b, c, d\).
- Mean of the four numbers = 5
→ a + b + c + d = 20
- Mean deviation of the four numbers = 3
Mean deviation = \(\frac{|a-5| + |b-5| + |c-5| + |d-5|}{4} = 3\)
→ Sum of absolute deviations = 12
- Mean deviation of the first three numbers a, b, c = 2
→ \(\frac{|a-5| + |b-5| + |c-5|}{3} = 2\)
→ Sum of absolute deviations for first three = 6
- Therefore, absolute deviation for the fourth number:
|d - 5| = 12 - 6 = 6
The fourth number = 6 + 5 = 11.
Source: Myschool Past Questions Archive (Record #77197)
Mathematics
UTME / JAMB 1999
Permutations, Combinations & Probability
Solution
A number is selected at random from 0 to 20. What is the probability that the number is odd prime?
A
\(\frac{8}{21}\)
B
\(\frac{1}{3}\)
C
\(\frac{2}{7}\)
D
\(\frac{5}{21}\)
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
The numbers from 0 to 20 inclusive are:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20.
Total numbers = 21
Odd prime numbers in this range:
Primes must be greater than 1 and have no divisors other than 1 and themselves.
Odd primes (exclude 2, which is even):
3, 5, 7, 11, 13, 17, 19
→ There are 7 odd prime numbers.
3. Probability = \(\frac{\text{Number of favourable outcomes}}{\text{Total outcomes}}\)
= \(\dfrac{7}{21} = \dfrac{1}{3}\)
Source: Myschool Past Questions Archive (Record #77198)
Biology
UTME / JAMB 1999
Basic Ecological Concepts, Ecosystems & Biomes
Solution
Primary consumers are found in
A
1, 2 and 3
B
1, 3 and 7
C
2, 3 and 7
D
2, 4 and 5
medium Difficulty
Verified Correct Answer: Option C
Biological Concept & Syllabus Guide
Primary consumers are organisms that eat plants or algae, and are the first step in a food chain. They are also known as herbivores or plant-eaters. In the Food web given in the question, immediately after the plants (Primary producers, because they are autotrophs), the organisms that feed on the plants in the different food chains are called primary consumers, and they are found in numbers 2,3 and 7( moth, grasshopper and herbivorous bug respectively).
Source: Myschool Past Questions Archive (Record #56106)
Mathematics
UTME / JAMB 1998
Plane Geometry, Polygons & Circle Theorems
Diagram
Solution
In diagram, PQ || ST and < PQR = 120º, < RST = 130º, find the angle marked x
Attached Figure / Diagram
A
50
B
65
C
70
D
80
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
Produce line PQ to meet line RS at U
< RQU = 180º - 120º = 60º (
In angle QRU: < QPT + RQU = < RUV ( 2 interior angles = one exterior angle)
x + 60º = 130º and x = 70º
Source: WAEC / JAMB / NECO Classroom Archive (Record #33077)
Mathematics
UTME / JAMB 1998
Sets, Logic & Venn Diagrams
Diagram
In the venn diagram, the shaded region is?
Attached Figure / Diagram
A
(P \(\cap\) Q) \(\cup\) R
B
(P \(\cap\) Q) \(\cap\) R
C
(P \(\cap\) Q1) \(\cap\) R
D
(P \(\cap\) Q1) \(\cup\) R
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: WAEC / JAMB / NECO Classroom Archive (Record #33074)
Mathematics
UTME / JAMB 1998
Linear, Simultaneous & Quadratic Equations
Solution
Factorize r2 - r(2p + q) + 2pq
A
(r - 2q)(2r - p)
B
(r - p)(r + p0
C
(r - q)(r - 2p)
D
(2r - q)(r + p)
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
r2 - r(2p + q) + 2pq = r2 - 2pr -qr + 2pq
= r(r - 2p) - q(r - 2p)
= (r - q)(r - 2p)
Source: WAEC / JAMB / NECO Classroom Archive (Record #30673)
Mathematics
UTME / JAMB 1998
Algebraic Expressions, Polynomials & Factorisation
Solution
When the expression pm\(^2\) + qm + 1 is divided by (m - 1), it has a remainder is 2, and when divided by (m + 1), the remainder is 4. Find p and q respectively
A
2, -1
B
-1, 2
C
3, -2
D
-2, 3
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
pm\(^2\) + qm + 1 = (m - 1) Q(x) + 2, where Q(x) = remainder.
p(1)\(^2\) + q(1) + 1 = 2
p + q + 1 = 2
p + q = 1.....(i)
pm\(^2\) + qm + 1 = (m - 1)Q(x) + 4
p(-1)\(^2\) + q(-1) + 1 = 4
p - q + 1 = 4
p - q = 3....(ii)
p + q = 1, p - q = 3
Using elimination method, add eqn i and ii
2p = 4, p = 2
from eqn ii
p - q = 3
2 - q = 3
-q = 3 - 2 = 1
q = - 1
Therefore, p = 2 and q = -1
q = 2
Source: WAEC / JAMB / NECO Classroom Archive (Record #30667)