Question Library
Browse, filter, and study verified past examination questions with step-by-step mathematical reasoning.
Searching 18,000+ Questions...
Sifting topics, KaTeX formulas & verified solutions
Showing 8236–8250 of 14893 verified questions
Sort by:
Biology
UTME / JAMB 2002
Variation & Genetics (Heredity)
Solution
If XN is the dominant allele for normal vision and Xn the recessive allele for colour blindness, a boy with the genotype YXn will be
A
have normal vision
B
be colour-blind
C
be totally blind
D
be a carrier of colour blindness
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
The correct answer is B. Be colour blind.
Since the boy has the genotype YXn:
- The Y chromosome indicates that he is male.
- The Xn allele is the recessive allele for colour blindness.
As a male, he only has one X chromosome, and since it carries the Xn allele, he will express the trait of colour blindness. Males are more likely to express X-linked recessive traits, such as colour blindness, because they have only one X chromosome. Females, on the other hand, would need to inherit two copies of the Xn allele (one from each X chromosome) to express colour blindness.
The other options are not correct:
A. The boy will not have normal vision because he has the Xn allele.
C. The boy will not be totally blind; colour blindness is a specific visual impairment, not total blindness.
D. The boy cannot be a carrier of colour blindness because he is male and only has one X chromosome. Carriers are typically females who have one Xn allele and one normal allele (XN).
Source: Myschool Past Questions Archive (Record #7209)
Biology
UTME / JAMB 2002
Variety of Organisms & Classification of Living Things
Solution
The first four children of a couple were all girls. The probability that the fifth will also be a girl is
A
1/5
B
1/4
C
1/3
D
1/2
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
the number of boys or girls the couple has given birth to does not affect their future offspring so it's 1/2 because it is either a boy or a girl
Source: Myschool Past Questions Archive (Record #7210)
Biology
UTME / JAMB 2002
Variety of Organisms & Classification of Living Things
Solution
Genetic counselling is important when a marriage is planned between a
A
Rh- woman and Rh man+
B
Rh- woman and Rh- man
C
Rh+ woman and Rh+ man
D
Rh+ woman and Rh- man
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
Most people — about 85% — are Rh positive. But if a woman who is Rh negative and a man who is Rh positive conceive a baby, there is the potential for a baby to have a health problem. The baby growing inside the Rh-negative mother may have Rh-positive blood, inherited from the father. Approximately half of the children born to an Rh-negative mother and Rh-positive father will be Rh positive
Source: Myschool Past Questions Archive (Record #7211)
Biology
UTME / JAMB 2002
Variation & Genetics (Heredity)
What proportion of the offspring of a cross between two heterozygous parents will exhibit the recessive condition phenotypically
A
1/4
B
1/2
C
3/4
D
4/4
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #7212)
Biology
UTME / JAMB 2002
Supporting Tissues & Skeletal System
Solution
The correct evolutionary sequence of the organisms represented is
A
IV->II->III->I
B
III->II->I->IV
C
II->III->IV->I
D
I->III=>II->IV
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
The first to evolve is the bony fish which evolved from a jawless fish. The amphibians evolved next after fish. The first amphibians evolved from a lobe-finned fish ancestor about 365 million years ago. They were the first vertebrates to live on land, but they had to return to water to reproduce. For this reason, they had to live near water bodies. They had few characteristics of fish in their early life. The reptiles evolved from the amphibians. They lived completely on land. They laid amniotic eggs and had fertilization. They were the first vertebrates that didn't have to return to water for reproduction. Reptiles developed certain added features such as feathers, hollow bones, and warm bodies. These animals were called birds or Aves. Then mammals.
Note: Mammals and birds both evolved from reptiles-like ancestors.
Source: Official Exam / Past Question Archive
Biology
UTME / JAMB 2002
Nervous, Hormonal Coordination & Sense Organs
Diagram
Solution
A hormone secreted at IV serves to
Attached Figure / Diagram
A
make the body react to emergencies
B
lower blood glucose level
C
raise the level of calcium ions in the blood
D
facilitate the development of facial hairs
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
The primary hormone facilitating facial hair development in both men and women is testosterone, along with its derivative dihydrotestosterone (DHT). These androgens stimulate hair follicle growth, converting fine, vellus hairs into thicker, darker terminal hairs, particularly in areas like the face, chest, and back.
Testosterone is the main androgen hormone responsible for the development of male secondary sexual characteristics, including facial hair. It also plays a role in hair growth in women, although in lower concentrations. Testosterone is primarily found in the testicles (testes) in men and ovaries in women. Additionally, adrenal glands in both sexes also produce testosterone, though in smaller amounts.
Source: Myschool Past Questions Archive (Record #41431)
Biology
UTME / JAMB 2002
Reproduction in Plants & Animals
Diagram
Solution
Ovoviparity is the type of fertilization exhibited by the organism labelled
Attached Figure / Diagram
A
IV
B
III
C
II
D
I
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
Ovoviparity is a reproductive strategy where embryos develop inside eggs that are retained within the female's body until they hatch, resulting in live birth, but without placental attachment. Some reptiles (like certain snakes and lizards), fish (like some sharks and rays), and some insects exhibit ovoviparity.
Source: Myschool Past Questions Archive (Record #41432)
Biology
UTME / JAMB 2002
Supporting Tissues & Skeletal System
Diagram
Solution
The correct evolutionary sequence of the organisms represented is
Attached Figure / Diagram
A
IV->II->III->I
B
III->II->I->IV
C
II->III->IV->I
D
I->III=>II->IV
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
The first to evolve is the bony fish which evolved from a jawless fish. The amphibians evolved next after fish. The first amphibians evolved from a lobe-finned fish ancestor about 365 million years ago. They were the first vertebrates to live on land, but they had to return to water to reproduce. For this reason, they had to live near water bodies. They had few characteristics of fish in their early life. The reptiles evolved from the amphibians. They lived completely on land. They laid amniotic eggs and had fertilization. They were the first vertebrates that didn't have to return to water for reproduction. Reptiles developed certain added features such as feathers, hollow bones, and warm bodies. These animals were called birds or Aves. Then mammals.
Note: Mammals and birds both evolved from reptiles-like ancestors.
Source: Myschool Past Questions Archive (Record #41433)
Mathematics
UTME / JAMB 2001
Fractions, Decimals, Percentages & Approximations
Solution
Evaluate 21.05347 - 1.6324 x 0.43 to 3 decimal places
A
20.980
B
20.351
C
20.981
D
20.352
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
Hint: Use BODMAS, in other words, do multiplication of the second and the last first before subtracting value obtained from the first.
Source: Myschool Past Questions Archive (Record #1114)
Mathematics
UTME / JAMB 2001
Plane Geometry, Polygons & Circle Theorems
Solution
Simplify \((\sqrt[3]{64a^{3}})^{-1}\)
A
4a
B
1/8a
C
8a
D
1/4a
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
\((\sqrt[3]{64a^{3}})^{-1} = (\sqrt[3]{(4a)^{3}})^{-1}\)
= \((4a)^{-1} \)
= \(\frac{1}{4a}\)
Source: Myschool Past Questions Archive (Record #1115)
Mathematics
UTME / JAMB 2001
Indices, Logarithms & Surds
Solution
Given that \(p = 1 + \sqrt{2}\) and \(q = 1 - \sqrt{2}\), evaluate \(\frac{p^{2} - q^{2}}{2pq}\).
A
2(2+√2)
B
-2(2+√2)
C
2√2
D
-2√2
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
\(\frac{p^{2} - q^{2}}{2pq} = \frac{(p + q)(p - q)}{2pq}\)
= \(\frac{(1 + \sqrt{2} - (1 - \sqrt{2}))(1 + \sqrt{2} + 1 - \sqrt{2})}{2(1 + \sqrt{2})(1 - \sqrt{2})}\)
= \(\frac{(2\sqrt{2})(2)}{-2}\)
= \(-2\sqrt{2}\)
Source: Myschool Past Questions Archive (Record #1120)
Mathematics
UTME / JAMB 2001
Fractions, Decimals, Percentages & Approximations
Solution
A car dealer bought a second-hand car for N250,000 and spent N70,000 refurbishing it. He then sold the car for N400,000. What is the percentage gain?
A
60%
B
32%
C
25%
D
20%
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
Total cost = N(250,000 + 70,000) = N320,000
Selling price = N400,000 (given)
Gain = SP - CP = N(400,000 - 320,000) = N80,000
Gain % = gain/CP x 100 = (80,000/320,000) x 100
Gain % = 25%
Source: Myschool Past Questions Archive (Record #1122)
Mathematics
UTME / JAMB 2001
Plane Geometry, Polygons & Circle Theorems
Solution
If \(x = \frac{y}{2}\),evaluate\(\left(\frac{x^{3}}{y^{3}}+\frac{1}{2}\right) \div \left(\frac{1}{2} - \frac{x^{2}}{y^{2}}\right)\)
A
5/8
B
5/2
C
5/32
D
5/16
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
\(x = \frac{y}{2} \)
\(\left(\frac{x^{3}}{y^{3}}+\frac{1}{2}\right) \div \left(\frac{1}{2} - \frac{x^{2}}{y^{2}}\right)\)
\(\frac{x^3}{y^3} + \frac{1}{2} = (\frac{y}{2})^{3} \div y^{3} + \frac{1}{2}\)
= \(\frac{y^{3}}{8} \times \frac{1}{y^3} + \frac{1}{2}\)
= \(\frac{1}{8} + \frac{1}{2}\)
= \(\frac{5}{8}\)
\(\frac{1}{2} - \frac{x^2}{y^2} = \frac{1}{2} - (\frac{y}{2})^{2} \div y^2)\)
= \(\frac{1}{2} - \frac{y^2}{4} \times \frac{1}{y^2}\)
= \(\frac{1}{2} - \frac{1}{4}\)
= \(\frac{1}{4}\)
\(\therefore \left(\frac{x^{3}}{y^{3}}+\frac{1}{2}\right) \div \left(\frac{1}{2} - \frac{x^{2}}{y^{2}}\right) = \frac{5}{8} \div \frac{1}{4}\)
= \(\frac{5}{2}\)
Source: Myschool Past Questions Archive (Record #1126)
Mathematics
UTME / JAMB 2001
Fractions, Decimals, Percentages & Approximations
Solution
Find the principal which amounts to N5,500 at a simple interest in 5 years at 2% per annum.
A
N4,900
B
N5,000
C
N4,700
D
N4,800
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
Principal, P = Amount, A - Interest, I.
A = P + I
I = (P.T.R)/100 = (P x 5 x 2)/100 = 10P/100 = P/10
But A = P + I,
=> 5500 = P + (P/10)
=> 55000 = 10P + P
=> 55000 = 11P
Thus P = 55000/11 = N5,000
Source: Myschool Past Questions Archive (Record #1129)
Mathematics
UTME / JAMB 2001
Fractions, Decimals, Percentages & Approximations
Solution
Evaluate \(\frac{(0.14^2 \times 0.275)}{7(0.02)}\) to 3 decimal places.
A
0.039
B
0.385
C
0.033
D
0.038
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
\(\frac{(0.14)^{2} \times 0.275}{7(0.02)} = \frac{(0.14)^{2} \times 0.275}{0.14}\)
= \(0.14 \times 0.275\)
= \(0.0385 \approxeq 0.039\)
Note: Embedded zeroes are counted just the same as non-zero digits and For the number of decimal places stated, count that number of digits to the right of the decimal and underline it.
The next number to its right is called the 'rounder decider'. If the 'rounder decider' is 5 or more, then round the previous digit up by 1
Source: Myschool Past Questions Archive (Record #1132)