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English Language
UTME / JAMB 2002
Synonyms (Nearest in Meaning)
Solution
Select the option that best explain the information conveyed in the sentence.
The politician was pilloried by the press for his inflammatory remarks?
A
The politician was snubbed by the press for his remarks
B
The politician was criticized by the press for his remarks
C
The politician was closely questioned by the press for his remarks
D
The politician was ridiculed by the press for his remarks
medium Difficulty
Verified Correct Answer: Option D
Grammar & Contextual Explanation
To transcribe the statement above, we first need to know the meaning of the various words used;
pilloried means to be attacked or ridiculed publicly.
inflammatory (relating to speech or writing) arousing or intended to arouse angry or violent feelings. example "inflammatory remarks"
synonyms: provocative · provoking · inflaming · inciting · agitating ·
option D best translate the statement.
Source: Myschool Past Questions Archive (Record #11670)
English Language
UTME / JAMB 2002
Concord (Subject-Verb Agreement)
Select the option that best explain the information conveyed in the sentence.
After the successful operation, he recovered by leaps and bounds?
A
He got well very rapidly
B
His well-bound wounds aided his recovery
C
He did a lot of keep-fit exercises
D
He used to jog regularly
medium Difficulty
Verified Correct Answer: Option A
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #11671)
English Language
UTME / JAMB 2002
Concord (Subject-Verb Agreement)
Select the option that best explain the information conveyed in the sentence.
Audu was taken bad in the middle of the night?
A
He was caught
B
He was robbed
C
He was ill
D
He was drunk
E
He was drunk
medium Difficulty
Verified Correct Answer: Option C
Grammar & Contextual Explanation
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #11672)
Physics
UTME / JAMB 2002
Equilibrium of Forces, Moments & Flotation
Solution
A copper cube weighs 0.25 N in air, 0.17N when completely immersed in paraffin oil and 0.15 N when completely immersed in water.The ratio of upthrust in oil to upthrust in water is
A
3 : 5
B
4 : 5
C
7 : 10
D
13 : 10
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Wt. in air = 0.25 N
Wt.in water = 0.15 N
Therefore, lost in wt. in water = Upthrust in water
= 0.25 - 0.15
= 0.10 N.
Wt. in paraffin oil = 0.17 N.
.. loss in wt. in oil = upthrust in the oil = 0.25 - 0.17 = 0.08
Ratio of upthrust in oil to upthrust in water
= \(\frac{0.08}{0.10}\) = \(\frac{8}{10}\) = \(\frac{4}{5}\) Or 4 : 5
Source: Myschool Past Questions Archive (Record #9561)
Physics
UTME / JAMB 2002
Work, Energy, Power & Simple Machines
Solution
A wheel and axle is used to raise a load of 500 N by the application of an effort of 250 N. If the radii of the wheel and the axle are 0.4 cm and 0.1 cm respectively, the efficiency of the machine is
A
20 %
B
40 %
C
50 %
D
60 %
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Efficiency = M.A/V.R X 100/1 M.A = Load/Effort = 500/250
= 2
V.R. = radius of wheel/radius of axle = 0.4/0.1 = 4.
therefore Efficiency = 2/4 x 100/1 = 50 %
Source: Myschool Past Questions Archive (Record #9562)
Physics
UTME / JAMB 2002
Linear Motion, Projectiles & Kinematics
Solution
The hydrostatic blood pressure difference between the head and the feet of a boy standing straight is 1.65 x 104 Nm-2. Find the height of the boy.
[ Density of blood = 1.1 x 103 kgm-3, g = 10ms-2]
A
0.5 m
B
0.6 m
C
1.5 m
D
2.0 m
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
[ Density of blood = 1.1 x 103 kgm-3, g = 10ms-2]
Pressure = pgh, where p = density, h = the height, g = acceleration of free fall due to gravity
1.6.5 x 104 = 1.1 x 103 x 10 x h
therefore h = 1.65 x 104/1.1 x 103 x 10 = 1.5m
Source: Myschool Past Questions Archive (Record #9563)
Physics
UTME / JAMB 2002
Current Electricity & Electric Circuits
Solution
A body weighing 80N stands in an elevator that is about to move. The force exerted by floor on the body as the elevator moves upward with an acceleration of 5 ms-2 is
[g = 10ms-2]
A
40 N
B
80 N
C
120 N
D
160 N
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
W = Mg
man's weight = 80N then his mass = \(\frac{80}{10}\) = 8kg
T = Mg + Ma = M( g + a) = 8(10 + 5) = 8 x 15 = 120N.
Source: Myschool Past Questions Archive (Record #9671)
Physics
UTME / JAMB 2002
Circular Motion, Gravitation & Simple Harmonic Motion
Solution
If the distance between two suspended masses 10kg each is tripled, the gravitational force of attraction between them is reduced by
A
one half
B
one third
C
one quarter
D
one ninth
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Let the distance apart the two masses = m.
From the equation F & M1 m2/ϒ2
F1 α 10 x 10/ϒ2 = F α 100/ ϒ2
F2 α 10 X 10/(3ϒ)2 => F2 α 100/9ϒ2
therefore F2/F1 = 100/9ϒ2/100/ϒ2 = 100/9ϒ2 ϒ2/100 = 1/9
Therefore F 2 : F 1 = 1 : 9
Source: Myschool Past Questions Archive (Record #9672)
Physics
UTME / JAMB 2002
Scalars, Vectors & Relative Motion
Solution
Two force each of 10N acts on a body, one towards the north and the other towards the east.
The magnitude and the direction of the resultant force are
A
20N, 45°E
B
20N, 45°W
C
10√2N, 45°W
D
10√2N, 45°E
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
From Pythagoras,
R2 = 102 + 102
= 100 + 100
= 200
therefore R2 = √200 = √2 x 100
= 10√2, in the direction 45°E
Source: Myschool Past Questions Archive (Record #9674)
Physics
UTME / JAMB 2002
Circular Motion, Gravitation & Simple Harmonic Motion
Solution
A particle in circular motion performs 30 oscillation in 6 seconds. Its angular velocity is
A
5 rad s-1
B
6 rad s-1
C
5π rad s-1
D
10π rad s-1
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Angular velocity w = 2π f.
But f = frequency no. of oscillations per second.
= 30/6 = 5Hz.
therefore W = 2π x 5
= 10π rad. s-1
Source: Myschool Past Questions Archive (Record #9675)
Physics
UTME / JAMB 2002
Elasticity, Density, Pressure & Fluids
The effect of a particle in a fluid attaining its terminal velocity is that the
A
acceleration is maximum
B
weight is equal to the retarding force
C
buoyancy force is equal to the to the viscous retardind force
D
buoyancy force is more than the weight of the fluid displaced
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #9677)
Physics
UTME / JAMB 2002
Reflection, Refraction & Dispersion of Light
Solution
A coin place below a rectangular glass block of thickness 9cm and refractive index 1.5 is viewed vertically above the block. The apparent displacement of the coin is
A
3 cm
B
5 cm
C
6 cm
D
8 cm
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Real depth = thickness of the glass block = 9cm.
Refractive index of the glass material = 1.5
But Refractive index = Real depth/Apparent depth
=> 1.5 = 9/Apparent depth
therefore Apparent depth = 9/1.5 = 6cm.
therefore Apparent displacement of the Coin = 9.6
= 3cm
Source: Myschool Past Questions Archive (Record #9678)
Physics
UTME / JAMB 2002
Gas Laws & Heat Transfer
Solution
The radiator of a motor car is cooled by
A
radiation
B
conduction
C
convection
D
radiation and conduction
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
The function of the radiator of a motor car is to "collect" heat from the circulating water and radiate some out, but it is itself cooled by the fan adjacent to it. whose function is primarily based on convection
Source: Myschool Past Questions Archive (Record #9679)
Physics
UTME / JAMB 2002
Gas Laws & Heat Transfer
Solution
I. Temperature.
II. Density of air molecules
III. Pressure
IV. Pitch
Which of the above will affect the velocity of sound in the air
A
I and II only
B
II and IV only
C
I,II and IV only
D
I,II,III nad IV
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Air pressure has no effect on speed of sound in an ideal gas because pressure and density both contribute to sound velocity equally, the two effects cancel each other out
Source: Myschool Past Questions Archive (Record #9680)
Physics
UTME / JAMB 2002
Waves, Sound & Vibrations
Solution
Which of the following is a characteristics of stationary waves?
A
They are formed by two identical waves travelling in opposite directions
B
they can be transverse or longitudinal
C
The distance between two successive nodes is one wavelenght
D
The antinode is a point of minimum displacement
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
They are produced by the superposition of two progressive identical waves travelling in opposite directions
Source: Myschool Past Questions Archive (Record #9681)