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Biology
UTME / JAMB 2004
Variation & Genetics (Heredity)
Solution
Identical twins inherit their genes from
A
different eggs and sperms
B
the same egg and sperm
C
two eggs and a sperm
D
one egg and two sperms
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
Identical twins, also known as monozygotic twins, are formed when a single egg is fertilized by a single sperm to create one zygote. Shortly after fertilization, this single fertilized egg splits into two separate embryos. Because they originate from the exact same genetic combination, identical twins share nearly 100% of their DNA and are always the same biological sex.
Source: Myschool Past Questions Archive (Record #14372)
Biology
UTME / JAMB 2004
Variation & Genetics (Heredity)
Solution
Sex - linked genes are located on
A
Y - chromosomes
B
X - and Y - chromosomes
C
homologous chromosome
D
X - chromosome
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
Sex-linked genes are genes located on the sex chromosomes (the X and Y chromosomes) rather than the autosomes. While the term "sex-linked" is often used to refer specifically to genes on the X chromosome because it contains significantly more genes (about 800–900) than the Y chromosome (about 60–70), scientific definitions include both. X-linked genes are found on the X chromosome; examples include red-green color blindness and hemophilia while the Y-linked genes are found on the Y chromosome; these are passed only from father to son and are often involved in male sex determination (e.g., the SRY gene).
Although the term is frequently used as a synonym for "X-linked" in many Biology textbooks, it is technically incomplete because genes on the Y chromosome are also considered sex-linked. Hence, option B is more accurate when compared to option D.
Source: Myschool Past Questions Archive (Record #14373)
Biology
UTME / JAMB 2004
Adaptation & Evolution
Solution
Which of the following is an example of intraspecific competition?
A
a lizard and an ant-eater chasing an insect
B
a worker termite and a soldier in a limited space.
C
a hawk and an eagle targeting the same chicken
D
yam and potato shots growing out through the same window
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
Intraspecific competition is an interaction in population ecology where members of the same species compete for limited resources such as food, water, territory, or space. Worker and soldier termites belong to the same species (within a single colony), and their competition for space or resources in a confined environment is a classic example of this phenomenon.
Source: Myschool Past Questions Archive (Record #14374)
Biology
UTME / JAMB 2004
Respiration & Gaseous Exchange
Solution
Plants survive hot dry conditions by
A
storing water in large parenchyma cells
B
producing numerous leaves
C
having numerous stomata
D
having evergreen leaves
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
Plants adapted to hot, dry environments (known as xerophytes or succulents) often store water in specialized tissues to survive periods of drought. This water is typically stored in large parenchyma cells, which are found in fleshy stems, leaves, or roots. These storage tissues allow the plant to maintain its metabolic processes when water is scarce in the soil.
Producing many leaves would increase the surface area available for transpiration, leading to rapid water loss and dehydration in hot, dry conditions.
Stomata are the primary sites for water vapour to exit the plant. Having many stomata would accelerate water loss; instead, desert plants usually have fewer stomata to conserve moisture.
While some evergreen plants are drought-tolerant, "evergreen" simply means the plant retains its leaves year-round. In extreme hot and dry conditions, many plants actually shed their leaves (deciduous behavior) to reduce water loss rather than keeping them.
Source: Myschool Past Questions Archive (Record #14375)
Biology
UTME / JAMB 2004
Digestive System & Feeding Mechanisms
Solution
Rodents gnaw on food with their
A
molar teeth
B
strong jaws
C
flat-ridged teeth
D
chisel - like front teeth
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
Rodents gnaw on food with their chisel-like front teeth. These specialized, ever-growing incisors are designed for cutting, biting, and gnawing, often growing continuously throughout their lives to prevent being worn away. For example, rats, mice, squirrels, and beavers use these sharp front teeth to eat nuts, fruits, and seeds.
Source: Myschool Past Questions Archive (Record #14376)
Biology
UTME / JAMB 2004
Adaptation & Evolution
Solution
The spots and stripes of the leopard and tiger are example of
A
cryptic colouration
B
warning colouration
C
disruptive colouration
D
counter shading
medium Difficulty
Verified Correct Answer: Option C
Biological Concept & Syllabus Guide
The spots (rosettes) of a leopard and the stripes of a tiger are classic examples of disruptive colouration. This is a form of camouflage that uses high-contrast patterns to break up the outline of an animal's body. By visually "shattering" the animal's silhouette, these patterns make it difficult for prey to recognize the characteristic shape of a predator against a complex background of tall grass or dappled forest shadows.
Cryptic colouration: While disruptive colouration is technically a type of crypsis (camouflage), "disruptive colouration" is the more specific and scientifically accurate term for patterns like spots and stripes that break up a silhouette.
Warning colouration involves bright, conspicuous colours (like those of a poison dart frog or monarch butterfly) used to signal to predators that the animal is toxic or dangerous. Leopards and tigers use their patterns to hide, not to be seen.
Counter shading refers to a colour pattern where an animal is darker on top and lighter on the bottom (like a shark or a penguin) to counteract the effects of overhead light and self-shadowing. While leopards do have lighter underbellies, their defining spots and stripes are not examples of this specific mechanism.
Source: Myschool Past Questions Archive (Record #14377)
Biology
UTME / JAMB 2004
Adaptation & Evolution
Solution
An evidence of the relationship between living organisms and their extinct relatives can best be obtained from
A
embryology
B
comparative anatomy
C
comparative physiology
D
palaeontology
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
Palaeontology is the scientific study of life of the geologic past through the analysis of plant and animal fossils. It provides the most direct and best evidence of the relationship between living organisms and their extinct relatives because fossils serve as a physical record of extinct species, allowing scientists to document their existence and trace transitions between ancient and modern organisms.
The study of the relationship between living organisms and their extinct relatives relies on evidence from paleontology, specifically the fossil record, and other fields like comparative anatomy and molecular biology. Fossils document the existence of extinct species, providing insights into their ancestry and relationships with extant organisms.
Source: Myschool Past Questions Archive (Record #14378)
Biology
UTME / JAMB 2004
Reproduction in Plants & Animals
Diagram
Solution
The process of pollination involves the transfer of pollens from
Attached Figure / Diagram
A
II to III
B
IV to I
C
I to II
D
III to IV
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
Pollination is the transfer of pollen grains from the male anther of a flower to the female stigma, either within the same flower or to another flower.
From the diagram provided in the question, I - Petal II - anther III -stigma IV - ovule. Hence, the transfer of pollen grain is from II to III.
See diagram above for better understanding.
Source: Myschool Past Questions Archive (Record #41448)
Biology
UTME / JAMB 2004
Reproduction in Plants & Animals
Diagram
Solution
The part labelled II is the
Attached Figure / Diagram
A
stigma
B
anther
C
filament
D
style
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
From the diagram provided in the question,
I - Petal
II - anther
III -stigma
IV - ovule.
Option B is the correct answer.
Source: Myschool Past Questions Archive (Record #41449)
Biology
UTME / JAMB 2004
Supporting Tissues & Skeletal System
Diagram
Solution
The bones labelled II are called
Attached Figure / Diagram
A
lumbar vertebrae
B
thoracic vertebrae
C
cervical vertebrae
D
sacral vertebrae
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
From the diagram provided in the question,
I - Cervical vertebrae
II - Lumbar vertebrae
Therefore, the correct answer is option A.
(See diagram above for reference)
Source: Myschool Past Questions Archive (Record #41450)
Biology
UTME / JAMB 2004
Supporting Tissues & Skeletal System
Diagram
Solution
The type of joint between adjacent bones in the part labelled II is the
Attached Figure / Diagram
A
hinge joint
B
ball and socket joint
C
suture joint
D
sliding joint
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
The joints between the adjacent processes of the vertebrae (specifically the facet joints or zygapophyseal joints) are classified as sliding joints (also known as gliding or plane joints). These joints consist of flat or nearly flat articular surfaces that allow the bones to slide or glide over one another, providing the flexibility needed for the spine to bend and twist while maintaining stability.
A. hinge joint: These allow movement in only one plane, like a door. While some specialized spinal junctions in certain animals are described as hinge-like, the standard classification for human intervertebral facet joints is sliding/gliding.
B. ball and socket joint: These provide the highest range of motion and are found in the shoulders and hips, where a rounded bone head fits into a cup-like depression.
C. suture joint: These are immovable fibrous joints found only between the bones of the skull.
Source: Myschool Past Questions Archive (Record #41451)
Biology
UTME / JAMB 2004
Supporting Tissues & Skeletal System
Solution
The type of joint between adjacent bones in the part labelled II is the
A
hinge joint
B
ball and socket joint
C
suture joint
D
sliding joint
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
The joints between the adjacent processes of the vertebrae (specifically the facet joints or zygapophyseal joints) are classified as sliding joints (also known as gliding or plane joints). These joints consist of flat or nearly flat articular surfaces that allow the bones to slide or glide over one another, providing the flexibility needed for the spine to bend and twist while maintaining stability.
A. hinge joint: These allow movement in only one plane, like a door. While some specialized spinal junctions in certain animals are described as hinge-like, the standard classification for human intervertebral facet joints is sliding/gliding.
B. ball and socket joint: These provide the highest range of motion and are found in the shoulders and hips, where a rounded bone head fits into a cup-like depression.
C. suture joint: These are immovable fibrous joints found only between the bones of the skull.
Source: Official Exam / Past Question Archive
Mathematics
UTME / JAMB 2004
Binary Operations, Matrices & Determinants
Solution
The inverse of the matrix \(\begin{pmatrix} 2 & 1 \\ 1 & 1 \end{pmatrix}\) is
A
\(\begin{pmatrix} 1 & -1 \\ -1 & 2 \end{pmatrix}\)
B
\(\begin{pmatrix} 1 & -1 \\ 1 & 2 \end{pmatrix}\)
C
\(\begin{pmatrix} 1 & 1 \\ 1 & 2 \end{pmatrix}\)
D
\(\begin{pmatrix} -1 & 1 \\ 1 & 2 \end{pmatrix}\)
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
To find the inverse of the matrix
\(A = \begin{pmatrix} 2 & 1 \\ 1 & 1 \end{pmatrix}\)
We can use the formula for the inverse of a \( 2 \times 2 \) matrix:
\(A^{-1} = \frac{1}{ad - bc} \begin{pmatrix} d & -b \\ -c & a \end{pmatrix}\)
where \( A = \begin{pmatrix} a & b \\ c & d \end{pmatrix} \).
Identify \( a, b, c, d \)}
In our matrix, we have:
\(a = 2, \quad b = 1, \quad c = 1, \quad d = 1\)
Calculate the determinant \( ad - bc \)
Calculating the determinant:
\(ad - bc = (2)(1) - (1)(1) = 2 - 1 = 1\)
Calculate the inverse:
Now substituting into the formula for the inverse:
\(A^{-1} = \frac{1}{1} \begin{pmatrix} 1 & -1 \\ -1 & 2 \end{pmatrix} = \begin{pmatrix} 1 & -1 \\ -1 & 2 \end{pmatrix}\)
Thus, the inverse of the matrix \( \begin{pmatrix} 2 & 1 \\ 1 & 1 \end{pmatrix} \) is \(\begin{pmatrix} 1 & -1 \\ -1 & 2 \end{pmatrix}\)
Source: Myschool Past Questions Archive (Record #72305)
Mathematics
UTME / JAMB 2004
Binary Operations, Matrices & Determinants
Solution
If P = \(\begin{pmatrix} 1 & 0 & -1 \\ 3 & 4 & 5 \\ -1 & 0 & 1 \end{pmatrix}\), then |P| is
A
-8
B
0
C
4
D
8
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
The determinant of the matrix
\(P = \begin{pmatrix} 1 & 0 & -1 \\ 3 & 4 & 5 \\ -1 & 0 & 1 \end{pmatrix}\)
is calculated as follows:
\(|P| = 1 \cdot (4 \cdot 1 - 5 \cdot 0) - 0 \cdot (3 \cdot 1 - 5 \cdot -1) + (-1) \cdot (3 \cdot 0 - 4 \cdot -1) = 4 - 0 - 4 = 0\)
Thus, the determinant of the matrix \( P \) is
\(|P| = 0\).
Source: Myschool Past Questions Archive (Record #72307)
Mathematics
UTME / JAMB 2004
Linear, Simultaneous & Quadratic Equations
Solution
Find the values of x where the curve y = x\(^3\) + 2x\(^2\) - 5x - 6 crosses the x - axis.
A
-2, -1, and 3
B
-2, 1 and -3
C
2, -1, and -3
D
2, 1, and 3
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
To find the values of \( x \) where the curve
\(y = x^3 + 2x^2 - 5x - 6\)
crosses the x-axis, we set \( y = 0 \):
\(x^3 + 2x^2 - 5x - 6 = 0\)
Testing for rational roots, we find that \( x = -1 \) is a root. Factoring the polynomial gives:
\(x^3 + 2x^2 - 5x - 6 = (x + 1)(x^2 + x - 6)\)
Solving the quadratic \( x^2 + x - 6 = 0 \) using the quadratic formula yields:
\(x = \frac{-1 \pm \sqrt{1^2 - 4 \cdot 1 \cdot -6}}{2 \cdot 1} = \frac{-1 \pm 5}{2}\)
Thus, the solutions are:
\(x = -1, \quad x = 2, \quad x = -3\)
Therefore, the values of \( x \) where the curve crosses the x-axis are \(x = -1, \quad x = 2, \quad x = -3\).
Source: Myschool Past Questions Archive (Record #72310)