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Mathematics
UTME / JAMB 2004
Indices, Logarithms & Surds
Solution
Simplify \(\frac{1}{\sqrt{3}+2}\) in the form \(a+b\sqrt{3}\)
A
2 -√3
B
-2 - √3
C
2 + √3
D
-2 + √3
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
\(\frac{1}{\sqrt{3}+2}\)
= \(\frac{1}{\sqrt{3}+2}\times \frac{\sqrt{3} - 2}{\sqrt{3} - 2}\)
= \(\frac{\sqrt{3}-2}{(\sqrt{3})^{2} -2^{2}}\)
= \(\frac{\sqrt{3}-2}{3-4}\)
= \(\frac{\sqrt{3}-2}{1}\) = -\(\sqrt{3}+2\)
= 2- \(\sqrt{3}\)
Source: Myschool Past Questions Archive (Record #8214)
Mathematics
UTME / JAMB 2004
Fractions, Decimals, Percentages & Approximations
Solution
A farmer planted 5000 grains of maize and harvested 5000 cobs, each bearing 500 grains. What is the ratio of the number of grains sowed to the number harvested?
A
1 : 250 000
B
1 : 25 000
C
1 : 500
D
1 : 5 000
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
5000 : 5000 * 500
5000 : 2500000
5 : 2500
1 : 500
Source: Myschool Past Questions Archive (Record #8215)
Physics
UTME / JAMB 2004
Work, Energy, Power & Simple Machines
Solution
A machine whose efficiency is 60% has a velocity ratio of 5. If a force of 500N is applied to lift a load P, what is the magnitude of P?
A
1500N
B
500N
C
4166N
D
750N
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
efficiency = (M.A / V.R) x 100/1 => 60/100 = M.A/5
∴M.A = (60 X 5) / 100 = 3
But M.A = Load/Effort; => 3 = Load/500
∴Load = 500 x 3
= 1500N
Source: WAEC / JAMB / NECO Classroom Archive (Record #12891)
Physics
UTME / JAMB 2004
Newton's Laws, Momentum & Collisions
Solution
I. Jet propelled aircraft
II. Rocket propulsion
III. The recoil of a gun
IV. A person walking
Which of the above is based on Newton's third law of motion
A
I and II only
B
I, II, III, and IV only
C
I and III only
D
I, II and III only
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
I. Jet aircraft — Expel gases backward → push aircraft forward (thrust).
II. Rocket — Expel gases backward → move forward (even in space).
III. Gun recoil — Bullet forward → gun moves backward.
IV. Walking — Foot pushes ground backward → ground pushes you forward.
Source: WAEC / JAMB / NECO Classroom Archive (Record #12892)
Physics
UTME / JAMB 2004
Equilibrium of Forces, Moments & Flotation
Solution
The change in volume when 450kg of ice is completely melted is [density of ice = 900 kgm\(^{-3}\), density of water = 1000 kgm\(^{-3}\)]
A
0.50m3
B
0.45m3
C
0.05m3
D
4.50m3
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Vol. of ice = \(\frac{\text{M}}{\text{D}}\) = \(\frac{450}{900}\) = 0.500m\(^3\)
vol. of water = \(\frac{\text{M}}{\text{D}}\) = \(\frac{450}{1000}\) = 0.450m\(^3\)
∴ Difference in vol. = 0.500 - 0.450
= 0.05m\(^3\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #12936)
Physics
UTME / JAMB 2004
Electrostatics & Capacitors
Solution
The instrument used for securing a large number of similar charges by induction is called
A
electrophorus
B
capacitor
C
proof-plane
D
electroscope
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
An Electrophorus is a simple manual electrostatic generator used to produce a large number of similar charges through the process of induction.
Source: WAEC / JAMB / NECO Classroom Archive (Record #12801)
Physics
UTME / JAMB 2004
Magnetism, Electromagnetism & AC Circuits
Solution
A generator manufacturing company was contracted to produce an a.c dynamo but inadvertently produced a d.c dynamo. To correct this error, the
A
armature coil should be made of silver
B
commutator should be replaced with slip ring
C
commutator should be replaced with split rings
D
armature coil should be made of aluminium
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
The company built a DC dynamo (with a commutator) instead of the required AC one (which needs slip rings). The simplest and most direct way to correct this—without rewinding the coil or major redesign—is to replace the commutator with slip rings.
Source: WAEC / JAMB / NECO Classroom Archive (Record #12786)
Physics
UTME / JAMB 2004
Current Electricity & Electric Circuits
Solution
Electrical appliances at home are normally earthed so that?
A
the appliances are maintained at a lower p.d than the earth
B
both the a.c and d.c sources can be used
C
a person touching the appliances is safe from electric shock
D
the appliances are maintained at a higher p.d than the earth
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Earthing is used to protect you from an electric shock. It does this by providing a path (a protective conductor) for a fault current to flow to earth. It also causes the protective device (either a circuit-breaker or fuse) to switch off the electric current to the circuit that has the fault.
Source: WAEC / JAMB / NECO Classroom Archive (Record #12803)
Physics
UTME / JAMB 2004
Atomic, Quantum, Nuclear Physics & Electronics
Solution
X rays can be used in the study of crystal structure because they
A
have a very long-reaching wavelength
B
have extremely short wavelength
C
are invisible
D
are very fast
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
The extremely short wavelength of X-rays allows them to interact with the atomic-scale structure of crystals via diffraction, revealing details of the crystal lattice, atomic positions, and bond lengths.
Source: WAEC / JAMB / NECO Classroom Archive (Record #12790)
Physics
UTME / JAMB 2004
Atomic, Quantum, Nuclear Physics & Electronics
Solution
Flourescent tubes produces light by the
A
excitation of gas molecules
B
conduction of solar energy
C
refraction of light by gas molecules
D
thermal agitation of electron in the tubes
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Electricity excites the gas atoms inside the tube, causing them to release UV light. This UV light then hits a phosphor coating on the glass, which glows to produce visible light.
Source: WAEC / JAMB / NECO Classroom Archive (Record #12797)
Chemistry
UTME / JAMB 2004
Particulate Nature of Matter, Laws & Formulae
Solution
It is difficult to achieve an orderly arrangement of the molecules of a gas because they?
A
have no definite shape
B
have little force of attraction between them
C
can collide with one another in the container
D
are too small in size
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
In most cases, there are essentially no attractive forces between particles. This means that a gas has nothing to hold a specific shape or volume.
It's difficult to achieve an orderly arrangement of gas molecules due to their high kinetic energy, large distances between particles, and lack of intermolecular forces. These factors cause the molecules to move randomly and freely, making it difficult to constrain them into a structured arrangement.
Source: WAEC / JAMB / NECO Classroom Archive (Record #2632)
Chemistry
UTME / JAMB 2004
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
What volume of gas is evolved at S.t.p if 2g of calcium trioxocarbonate (IV) is added to a solution of hydrochloric acid?
[Ca = 40, C = 12, O = 16, Cl = 35.5, H = 1 Molar volume of a gas at s.t.p = 22.4 dm\(^3\)
A
112 cm3
B
224 cm3
C
448 cm3
D
2240 cm3
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
CaCO\(_3\)(s) + 2HCl(aq) → CaCl\(_2\) + H\(_2\)O(l) + CO\(_2\)
The relative molecular mass of CaCO\(_3\) = 40 + 12 + (16 x 3) = 52 + 48 = 100 ;
Relative molecular mass of CO\(_2\)= 12 + (10 x 2) = 44
From the above equation, 100g of CaCO\(_3\) reacts with 44g of CO\(_2\) at s.t.p. i.e 22.4 dm\(^3\)
2g of CaCO\(_3\) will react with (2 x 22.4)/100 of CO\(_2\) = 0.448 dm\(^3\)
0.448 dm\(^3\) = 0.448 x 1000 = 448cm\(^3\)
Alternatively,
CaCO\(_3\)(s) + 2HCl(aq) → CaCl\(_2\) + H\(_2\)O(l) + CO\(_2\)
1 : 2 1
The focus is on CaCO\(_3\) and CO\(_2\) and they are in ratio 1 : 1, hence, we can calculate the number of moles of CaCO\(_3\) and substitute the value for the number of moles of CO\(_2\), since their number of moles will also be the same.
Molar mass of CaCO\(_3\) = Ca + C + O\(_3\) = 40 + 12 + (16 x 3) = 100g/mol
Number of moles of CaCO\(_3\) = \(\frac{mass}{molar mass}\) = \(\frac{2}{100}\) = 0.02 mole
Number of moles = \(\frac{Volume}{molar volume}\)
0.02 = \(\frac{volume}{22.4}\)
Volume = 0.02 x 22.4 = 0.02 x 22400 = 448 cm\(^3\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #2630)
Mathematics
UTME / JAMB 2004
Trigonometry, Elevation & Bearings
Solution
The shadow of a pole 5√3m high is 5m. Find the angle of elevation of the sun.
A
45o
B
75o
C
30o
D
60o
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
Tan θ = 5√3/5
Tan θ = √3
θ = 60o
Source: Myschool Past Questions Archive (Record #11100)
Mathematics
UTME / JAMB 2004
Inequalities & Linear Programming
Diagram
Solution
The shaded area in the diagram above is represented by
Attached Figure / Diagram
A
{(x,y) : y - 3x < -6}
B
{(x,y) : y + 3x < 6}
C
{(x,y) : y + 3x < -6}
D
{(x,y) : y - 3x < 6}
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
Coordinates of the line are (x1 y1)(0,2) respectively and (x2 y2)(2,0) respectively
Gradient (m) of the line = (y2 - y1) / (x2 - x1) = (0-6) / (2-0) = -6/2
= -3
Equation of the line y-y1 = m(x-x1)
y - 6 = -3(x - 0)
y - 6 = -3x
y + 3x = 6
inequality; from the y axis, the shaded region is below the line
∴ y + 3x ∠ 6 and line is a broken line
Source: Myschool Past Questions Archive (Record #11101)
Mathematics
UTME / JAMB 2004
Plane Geometry, Polygons & Circle Theorems
Solution
PQRSTV is a regular polygon of side 7 cm inscribed in a circle. Find the circumference of the circle PQRSTV.
A
56 cm
B
22 cm
C
42 cm
D
44 cm
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
Each interior Angle of the polygon = (n-2)180_n
= (6-2)180_6
= 4 x 30
= 120o
i.e ∠PQR = 120o ∴ RQD = 120/2 = 60o also
∴ Δ QOR is equilateral Δ ∴ QO = 7cm
∴ PO = QO = RO ...... = 7cm radius of the circumference of the circle = 2πr
= 2 x 22/7 x 7/1
= 44 cm
Source: Myschool Past Questions Archive (Record #11111)