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The simplest, cheapest and safest way to correct long sight is with glasses. Convex prescription lenses (called plus lenses) are used to bend light rays slightly inwards / converge them to give a little bit of additional focusing power to the eye.

Cud chewing is also necessary because the foods ruminant animals eat are difficult to digest and it takes extra effort to get all of the nutrients from the food. Other examples of ruminant animals include deer, camels, buffalo, goats, sheep, and giraffes. The main difference between ruminant and non-ruminant animals is that ruminant animals are herbivores whereas non-ruminant animals are omnivores or carnivores. Thus, ruminant animals have a complex rumen to digest plant material while non-ruminant animals have a simple stomach since their food is easy to digest. Non-ruminant animals are animals with a single-compartment stomach, such as swine, poultry, horses, dogs, cats, and humans.

Cud chewing is also necessary because the foods ruminant animals eat are difficult to digest and it takes extra effort to get all of the nutrients from the food. Other examples of ruminant animals include deer, camels, buffalo, goats, sheep, and giraffes. The main difference between ruminant and non-ruminant animals is that ruminant animals are herbivores whereas non-ruminant animals are omnivores or carnivores. Thus, ruminant animals have a complex rumen to digest plant material while non-ruminant animals have a simple stomach since their food is easy to digest. Non-ruminant animals are animals with a single-compartment stomach, such as swine, poultry, horses, dogs, cats, and humans.

1101\(_2\) + 10111\(_2\) + 111\(_2\) = 101011\(_2\)

125\(_x\) = 20\(_{10}\) 1 x X\(^2\) + 2 x X\(^1\) + 5x X \(^0\) = 20 X2 + 2X + 5 = 20 X\(^2\) + 2X - 15 = 0 (X + 5)( X - 3) = 0 X + 5 implies X = -5 X - 3 implies X = 3 But X cannot be negative ∴X = 3

No expanded working has been attached for this question yet. The verified answer is Option D.

NB: This is a correction to the solution in the video lesson. 123456 \(\approxeq\) 123000.

\(I = \frac{P \times T \times R}{100}\) = \(\frac{7500 \times 8 \times 5}{100}\) = N3000

N85 - N60 = N25 increase ∴percentage increase = \(\frac{25}{60}\times \frac{100}{1}\) = \(\frac{125}{3}\) = 41.67% = 42%

\(16^{\frac{-1}{2}}\times 4^{\frac{-1}{2}} \times 27^{\frac{1}{3}}\) =\(\frac{1}{16^{\frac{1}{2}}}\times \frac{1}{4^{\frac{1}{2}}}\times 27^{\frac{1}{3}}\) =\(\frac{1}{\sqrt{16}} \times \frac{1}{\sqrt{4}} \times \sqrt[3]{27}\) =\(\frac{1}{4} \times \frac{1}{2} \times \frac{3}{1}\) = \(\frac{3}{8}\)

If log\(_{x^{\frac{1}{2}}}\)64 = 3 (X\(^{\frac{1}{2}})^3\) = 64 (X\(^{\frac{1}{2}})^3\) = 4\(^3\) X\(^{\frac{1}{2}}\) = 4 X = 4\(^2\) X = 16

\(\frac{1+\sqrt{2}}{1-\sqrt{2}} \times \frac{1+\sqrt{2}}{1+\sqrt{2}}\) = \(\frac{1+(1+\sqrt{2})+\sqrt{2}(1+\sqrt{2})}{1^2 - (\sqrt{2})^2}\) = \(\frac{(1+\sqrt{2}+\sqrt{2}+2)}{1-2}\) = \(\frac{3+2\sqrt{2}}{-1}\) = - 3 - 2\(\sqrt{2}\) ∴ X and Y = -3 and -2

X = {1,5,10} Y = {3,4,6} X∩Y = ∅

(4x+3y)\(^2\) - (3x-2y)\(^2\) Using the differences of two squares: (4x+3y+3x-2y)(4x+3y-(3x-2y)) (4x+3y+3x-2y)(4x+3y-3x+2y) (x+5y)(7x+y)

n(M) only = 30-10 = 20 n(E) only = 20-10 = 10 n(M∩E) = 10 ∴M∪E = 20+10+10 = 40