Question Library
Browse, filter, and study verified past examination questions with step-by-step mathematical reasoning.
Searching 18,000+ Questions...
Sifting topics, KaTeX formulas & verified solutions
Showing 5566–5580 of 14893 verified questions
Sort by:
Biology
UTME / JAMB 2011
Adaptation & Evolution
The wings of a bat and those of a bird are examples of
A
convergent evolution
B
continuous variation
C
coevolution
D
divergent evolution
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #29701)
Biology
UTME / JAMB 2011
Variety of Organisms & Classification of Living Things
Diagram
Use the diagram above to answer this question.
Which of the organisms represented are notable agricultural pests?
Attached Figure / Diagram
A
ll and IV
B
l and IV
C
ll and lll
D
l and lll
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #31185)
Biology
UTME / JAMB 2011
Variety of Organisms & Classification of Living Things
Diagram
Use the diagram above to answer this question.
The gas evolved in the process is
Attached Figure / Diagram
A
carbon (IV) oxide
B
nitrogen
C
oxygen
D
carbon (II) oxide
medium Difficulty
Verified Correct Answer: Option A
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #31189)
Biology
UTME / JAMB 2011
Cell & Its Environment (Diffusion, Osmosis & Transport)
Diagram
Use the diagram above to answer this question.
The experimental set-up above is used to demonstrate the process of
Attached Figure / Diagram
A
diffusion
B
photosynthesis
C
fermentation
D
plasmolysis
medium Difficulty
Verified Correct Answer: Option C
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #31190)
Biology
UTME / JAMB 2011
Growth, Micro-organisms & Public Health
Diagram
Solution
The adult form of iii is a vector of
Attached Figure / Diagram
A
sleeping sickness
B
river blindness
C
cholera
D
elephantiasis
medium Difficulty
Verified Correct Answer: Option D
Biological Concept & Syllabus Guide
The diagram in III is the pupal stage of the mosquito. The adult form of it is the vector of elephantiasis
Elephantiasis, also known as lymphatic filariasis, is caused by parasitic worms that are transmitted by the bite of an infected mosquito. The disease damages the lymphatic system, which can lead to severe swelling in the limbs and other complications.
Source: Myschool Past Questions Archive (Record #37227)
Biology
UTME / JAMB 2011
Variety of Organisms & Classification of Living Things
Diagram
An economic importance of the organism represented by IV is that
Attached Figure / Diagram
A
it transmit water borne disease to humans
B
it is destructive to farm crops
C
its faeces pollutes drinkng water
D
it helps in the control of mosquito larvae
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #37226)
Biology
UTME / JAMB 2011
Variety of Organisms & Classification of Living Things
An economic importance of the organism represented by IV is that
A
it transmit water borne disease to humans
B
it is destructive to farm crops
C
its faeces pollutes drinkng water
D
it helps in the control of mosquito larvae
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Official Exam / Past Question Archive
Mathematics
UTME / JAMB 2010
Plane Geometry, Polygons & Circle Theorems
Diagram
Solution
From the diagram above, find x
Attached Figure / Diagram
A
65o
B
50o
C
75o
D
55o
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
∠RTS = 90o (∠ in semi circle)
∠UTS = 25o (∠ in alternate segment)
X + 90 + 25 = 180(sum of ∠s on a str line)
X + 115 = 180
X = 180 - 115
X = 65o
Source: WAEC / JAMB / NECO Classroom Archive (Record #9805)
Mathematics
UTME / JAMB 2010
Plane Geometry, Polygons & Circle Theorems
Diagram
Solution
From the cyclic quadrilateral TUVW above, find the value of x
Attached Figure / Diagram
A
26o
B
24o
C
20o
D
23o
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
TUVW is a cyclic quad
3χ + 20 + 88 = 180 (opp ∠ s of a cyclic quad are supplementary)
3χ + 108 = 180
3χ = 180 - 108
3χ = 72
χ = 72/3
χ = 24o
Source: WAEC / JAMB / NECO Classroom Archive (Record #9950)
Mathematics
UTME / JAMB 2010
Indices, Logarithms & Surds
Solution
If cot\(\theta\) = \(\frac{8}{15}\), where \(\theta\) is acute, find sin\(\theta\)
A
\(\frac{8}{17}\)
B
\(\frac{15}{17}\)
C
\(\frac{16}{17}\)
D
\(\frac{13}{17}\)
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
cot\(\theta\) = \(\frac{1}{\cos \theta}\)
= \(\frac{8}{15}\)(given)
tan\(\theta\) = \(\frac{15}{8}\)
By Pythagoras' theorem,
x\(^2\) = 15\(^2\) + 8\(^2\)
x\(^2\) = 225 + 64 = 289
x = \(\sqrt{289}\)
= 17
Hence sin\(\theta\) = \(\frac{15}{x}\)
= \(\frac{15}{17}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #29583)
Mathematics
UTME / JAMB 2010
Indices, Logarithms & Surds
Solution
Evaluate \(\left(\frac{81}{16}\right)^{\frac{-1}{4}}\times 2^{-1}\)
A
1/3
B
3
C
6
D
1/6
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
\(\left(\frac{81}{16}\right)^{\frac{-1}{4}}\times 2^{-1}\) = \(\frac{1}{\left(\frac{81}{16}\right)^{\frac{1}{4}}}\times \frac{1}{2}\)
= \(\left(\frac{16}{81}\right)^{\frac{1}{4}}\times \frac{1}{2}\)
= \(\left(\frac{2}{3}\right)^{4\times \frac{1}{4}}\)
=\(\frac{2}{3}\times \frac{1}{2}\)
= \(\frac{1}{3}\)
Source: Myschool Past Questions Archive (Record #9569)
Mathematics
UTME / JAMB 2010
Indices, Logarithms & Surds
Solution
Rationalize \(\frac{2\sqrt{3} + \sqrt{5}}{\sqrt{5} - \sqrt{3}}\)
A
(3 √ 15 +11) / 2
B
3 √ 15 -11
C
(3 √ 15 -11) / 2
D
3 √ 15 +11
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
\(\frac{2\sqrt{3} + \sqrt{5}}{\sqrt{5} - \sqrt{3}}\)
= \((\frac{2\sqrt{3} + \sqrt{5}}{\sqrt{5} - \sqrt{3}})(\frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} + \sqrt{3}})\)
= \(\frac{2\sqrt{15} + 6 + 5 + \sqrt{15}}{5 - 3}\)
= \(\frac{3\sqrt{15} + 11}{2}\)
Source: Myschool Past Questions Archive (Record #9642)
Mathematics
UTME / JAMB 2010
Fractions, Decimals, Percentages & Approximations
Solution
Express the product of 0.21 and 0.34 in standard form
A
7.14 x 10-3
B
7.14 x 10-2
C
7.14 x 10-1
D
7.14 x 10-4
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
0.21 x 0.34 = 0.0714
= 7.14 x 10-2
Source: Myschool Past Questions Archive (Record #9764)
Mathematics
UTME / JAMB 2010
Plane Geometry, Polygons & Circle Theorems
Solution
In a survey of 50 newspaper readers, 40 read Champion and 30 read Guardian, how many read both papers?
A
10
B
5
C
15
D
20
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
Let C n G = X
n C only = 40 - x
n G only = 30 - x
40 - X + 30 - X + X = 50
70 - X = 50
X = 70 - 50
X = 20
Source: Myschool Past Questions Archive (Record #9781)
Mathematics
UTME / JAMB 2010
Algebraic Expressions, Polynomials & Factorisation
Solution
Factorize completely \(\frac{x^{3} + 3x^{2} - 10x}{2x^{2} - 8}\)
A
x(x-5)2(x+2)
B
x(x-5)2(x-2)
C
x(x+5)2(x+2)
D
x2+52x+4
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
\(\frac{x^{3} + 3x^{2} - 10x}{2x^{2} - 8} = \frac{x(x^{2} + 3x - 10)}{2(x^{2} - 4)}\)
= \(\frac{x(x^{2} - 2x + 5x - 10)}{2(x - 2)(x + 2)}\)
= \(\frac{x(x - 2)(x + 5)}{2(x - 2)(x + 2)}\)
= \(\frac{x(x + 5)}{2(x + 2)}\)
Source: Myschool Past Questions Archive (Record #9794)