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Option D is correct. This is because, salivary glands are found in the mouth, which secretes a juice called saliva that contains an enzyme called ptyalin.

Option B is correct. This is because, leucocytes is another name for white blood cells

Option B is correct. This is because, the removal of the remnant particles of digestion called faeces is done through a process called egestion.

Options A and B are not correct. Option C is correct. This is because, the mouth is the location where enzyme ptyalin acts on starchy food. Option D is wrong. This is because, stomach is location for the action of renin and pepsin enzymes.

Options A and B are not correct. Option C is correct. This is because, the mouth is the location where enzyme ptyalin acts on starchy food. Option D is wrong. This is because, stomach is location for the action of renin and pepsin enzymes.

The colour of a neutral litmus solution is purple. Litmus solution is made up of purple dye which is extracted from Lichens. It is a natural Indicator and it is used to indicate the presence of an acid or a base. A litmus paper will turn red in the presence of an acid and it turns blue in the presence of a base.

At the beginning of periods 2 and 3 of the Periodic Table, there are several cases where an element at the top of one group has some similarities with an element in the next group. For example, boron is a non-metal with some properties rather like silicon. Unlike the rest of Group 2, beryllium has some properties resembling aluminium. And lithium has some properties which differ from the other elements in Group 1, and in some ways resembles magnesium. There is said to be a diagonal relationship between these elements. There are several reasons for this, but each depends on the way atomic properties like electronegativity vary around the Periodic Table.

To find \( 110111_2 + 10100_2 \): Convert to decimal: \(110111_2 = 55_{10}, \quad 10100_2 = 20_{10}\) Add: \(55 + 20 = 75\) Convert back to binary: \(75_{10} = 1001011_2\) Final result: \(110111_2 + 10100_2 = 1001011_2\) OR \(\begin{array}{r} 110111_2 \\ + 010100_2 \\ \hline 1001011_2 \end{array}\) \(\therefore \; 110111_2 + 10100_2 = 1001011_2\)

SP = Nx CP = N60,000 Percentage loss = 15% Using percentage loss... \(\frac{CP - SP}{CP} = \text{100%}\) \(\text{15%} = \frac{60000 - x}{60000} \times \text{100%}\) \(\text{15%} \times 60000 = (60000 - x)\text{100%}\) \(60000 - x = \frac{\text{15%} \times 60000}{\text{100%}}\) 60000 - x = 3 x 3000 60000 -x = 9000 x = 60000 - 9000 x = N51,000

0.00043 x 2000 = 43 x 10-5 x 2 x 103 = 43 x 2 x 10-5+3 = 86 x 10-2 = 8.6 x 101 x 10-2 = 8.6 x 10-1

Let; M = Man monthly net earnings Then; \(\text{N4500} = \frac{\text{10%}}{\text{100%}} \times M \) \(M = \frac{\text{N4500} \times \text{100%}}{\text{10%}} \) M = N45,000

If log 7.5 = 0.8751 Then 2log75 + log750 = 2(1.8751) + 2.8751 = 3.7502 + 2.8751 = 6.6253

8x-2 = 2/25 x-2 = 2/25 x 1/8 x-2 = 2/200 x-2 = 1/100 1/x2 = 1/100 x2 = 100 x = 10

\(= \frac{2\sqrt{2} - \sqrt{3}}{\sqrt{2} + \sqrt{3}} \times \frac{\sqrt{2} - \sqrt{3}}{\sqrt{2} - \sqrt{3}}\) \(= \frac{2\sqrt{2}(\sqrt{2}) + (2\sqrt{2})(-\sqrt{3})-\sqrt{3}(\sqrt{2})-\sqrt{3}(-\sqrt{3})}{(\sqrt{2})^2-(\sqrt{3})^2}\) \(= \frac{2 \times 2 - 2\sqrt{6} - \sqrt{6} + 3}{2 - 3}\) \(= \frac{4 - 3\sqrt{6} + 3}{-1}\) \(= \frac{7 - 3\sqrt{6}}{-1}\) \(= \frac{7}{-1} - \frac{3\sqrt{6}}{-1}\) \(= -7 + 3\sqrt{6}\) \(= 3\sqrt{6}-7\)

\( = log_2 \frac{8 \times 16}{4}\) \( = log_2 32\) \( = log_2 2^5\) \( = 5log_2 2\) \( = 5 \times 1\) \( = 5 \)