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Chemistry
UTME / JAMB 2015
Metals, Transition Elements & Extraction
Solution
The substance that is used in the steel industry for the removal of carbon. Sulphur and phosphorus impurities from pig iron is
A
oxygen
B
chlorine
C
nitrogen
D
hydrogen
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Oxygen is a substance that is used to remove impurities from pig iron. Options B, C, D will be effective in removing impurities positive]
Source: Myschool Past Questions Archive (Record #41225)
Chemistry
UTME / JAMB 2015
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Solution
If glucose is heated with concentrated tetraoxosulphate(vi)acid, it will be dehydrated to?
A
carbon
B
carbon(iv)oxide
C
ethane
D
ethanol
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Carbon concentration of 4 will not give a precipitate heating. Option B,C,D will not be dehydrated
Source: Myschool Past Questions Archive (Record #41226)
Chemistry
UTME / JAMB 2015
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Solution
Which of the following compounds can be represented by the molecular formula C2 H6O?
A
propanal
B
ethanol
C
methanoic acid
D
glucose
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Ethanol has the molecular formula C2H6O. Option A, C, D are not because their molecular are not different
Source: Myschool Past Questions Archive (Record #41228)
Chemistry
UTME / JAMB 2015
Acids, Bases, pH & Salts
Solution
what is the pH of 0.00lmoldm3 solution of sodium hydroxide
A
14
B
13
C
12
D
11
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
[H+][OH−] = 10 − 4
[H+] =10 − 14 ÷ [OH+]
=10 −14 ÷ (1 × 10 − 3) = 10 − 11
pH = − log10[H+ ]
= − log10[10 − 11] = − 1 × −11
log10[10 − 11] = 1
= − 1 × 11 × 1
= − 11
Source: Myschool Past Questions Archive (Record #41230)
Chemistry
UTME / JAMB 2015
Chemical Energetics & Thermochemistry
Solution
N2O4(g)→ 2NO2(g)
In the endothermic reaction above, more products formed will be favored by
A
A constant values
B
an increase in pressure
C
a decrease pressure
D
a decrease volume
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
A decrease in pressure will result in the breaking or splitting of a larger molecule into a simpler ones. Options A, B, D are not in conformance to the reaction
Source: Myschool Past Questions Archive (Record #41232)
Chemistry
UTME / JAMB 2015
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Solution
Chlorine gas turns damp starch-iodide paper
A
pink
B
colourless
C
red
D
dark blue
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Chlorine turns a damp starch iodide paper into dark blue or blue black.
Source: Myschool Past Questions Archive (Record #41233)
Chemistry
UTME / JAMB 2015
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
Chlorine consisting of two isotope of mass number 35 and 37 in the ratio 3:1 has an atomic mass of 35.5. Calculate the relative abundance of the isotope of mass number 37
A
20
B
25
C
60
D
75
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Let the relative abundance of the energy with mass 37 be
Total relative abundance of the isotope of mass 359100-k)
Total mass of isotope of mass 37-37x, while that of 35-359(100x)
-37x + 3500 − 35 − 35.5
-37x + 3500 − 35n − 35.5
Mean mass of chlorine atom − (2n + 3500)/ ÷ 100
= 35.5
2x + 3500 − 3550yx = 50/2
Source: Myschool Past Questions Archive (Record #41234)
Chemistry
UTME / JAMB 2015
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
The principal constituent of natural gas is
A
methane
B
ethane
C
propane
D
Butane
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Methane CH4.A. is the principal and commercial constituent natural gas. Option B,C,D are also constituent of natural gas but they are not commercial and of economic importance
Source: Myschool Past Questions Archive (Record #41235)
Chemistry
UTME / JAMB 2015
Electrolysis & Electrochemical Cells
Solution
In the electrolysis of CuSo4(g) using platinum electrode the reaction at the anode is
A
4H+ 4e - 2H2
B
4OH= 4e- + 2H2O + O2
C
2OH - 2e- = 2OH
D
2OH- + 2OH = 2H2O + O2
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
40H − 4e → 2H2O + O2is the reaction of sun at the anode in the electrolysis of CuSO4 (g) using platinum particles. Option A,C,D are not formed as a result of the equation
Source: Myschool Past Questions Archive (Record #41237)
Chemistry
UTME / JAMB 2015
Periodic Table & Periodicity
Solution
S block elements of the periodic table one made up of
A
groups 1, 2, 3
B
groups 1, and 2
C
group 3
D
group 3 to 7
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
S block elements only are made up of group 1 and 2 options A,C,D takes place of the other blocks in the periodic table p,d,f etc.
Source: Myschool Past Questions Archive (Record #41238)
Chemistry
UTME / JAMB 2015
Oxidation, Reduction & Redox Reactions
Solution
The oxidation state of sulphur on H2SO4 acid is
A
-4
B
+6
C
4
D
-8
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
In SO4. The state of oxygen oxidation number is -2. Options A,C,D do not belong to the oxidation state in SO4
Source: Myschool Past Questions Archive (Record #41240)
Chemistry
UTME / JAMB 2015
Electrolysis & Electrochemical Cells
Solution
In the electrolysis of brine the anode is
A
platinum
B
copper
C
zinc
D
carbon
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
In the industrial of brine carbon is the anode while mercury is the cathode. Options of A, B, C are not used in brine solution because they are alloy of mercury
Source: Myschool Past Questions Archive (Record #41241)
Chemistry
UTME / JAMB 2015
Particulate Nature of Matter, Laws & Formulae
Solution
Calculate the relative molecular mass of Limestone CaCO3, (Ca = 40, C =12, O = 16)
A
56
B
100
C
76
D
90
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
One molecule of CaCO has 1Ca, 1C and 30 atom relative molecular mass of CaCO3
1 × Ar of Ca +1 × Ar of C +3 × Ar of O
(1 × 40 + 1 × 12 + 3 × 1)
40 + 12 + 48
=100
Option A,C and D will not give 100
Source: Myschool Past Questions Archive (Record #41243)
Chemistry
UTME / JAMB 2015
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
When steam is passed over red hot carbon the substances produced are
A
hydrogen and trioxocarbonate (IV) acid
B
hydrogen, oxygen and carbon (IV) oxide
C
hydrogen and carbon (ii) oxide
D
hydrogen and carbon (IV) oxide
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Hydrogen and carbon (ii) oxide will be formed when red steam is passed ever red-hot carbon. Option A,B,D are not produced through this process
Source: Myschool Past Questions Archive (Record #41245)
Chemistry
UTME / JAMB 2015
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
When steam is passed over red hot carbon the substances produced are
A
hydrogen and trioxocarbonate (IV) acid
B
hydrogen, oxygen and carbon (IV) oxide
C
hydrogen and carbon (ii) oxide
D
hydrogen and carbon (IV) oxide
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Hydrogen and carbon (ii) oxide will be formed when red steam is passed ever red-hot carbon. Option A,B,D are not produced through this process
Source: Official Exam / Past Question Archive