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Mathematics
UTME / JAMB 2015
Fractions, Decimals, Percentages & Approximations
Solution
Simplify 2.04 × 3.7 (Leave your answer in 2 decimal place)
A
7.51
B
7.71
C
5.5
D
7.55
medium Difficulty
Verified Correct Answer: Option D
Step-by-Step Mathematical Solution
2.04 x 3.7
=
204
x 37
-----
7548 = 7.548
= 7.55(2dp)
Source: Myschool Past Questions Archive (Record #41297)
Mathematics
UTME / JAMB 2015
Fractions, Decimals, Percentages & Approximations
Solution
A public car dealer marked up the cost of a car at 30% in an attempt to make 20% gross profit. Due to the value of dollar, he now placed 20% discount on the car. What profit or loss will he make?
A
3%
B
2%
C
4%
D
1%
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
Let assume the cost price is 100%
Marked up price + cost price = 20 + 100 = 120%
Discount at 20% = 20/100 × 120 % of cost price
Selling price = cost price − gain
= (120 − 24)% of cost price
= 96% of cost price
Loss = (100− 96)% of cost price
= 4% of cost price
∴ He will wake 4% loss
Source: Myschool Past Questions Archive (Record #41298)
Mathematics
UTME / JAMB 2015
Indices, Logarithms & Surds
Solution
Rationalize 5 ÷ (2 − √3)
A
3(2 + √5)
B
2(3 + √5)
C
5(2 + √3)
D
3 √2 + 1
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
5÷ (2 − √3)
Using conjugate surds
[5 ÷ (2 − √3)]×(2 + √3) ÷ (2 + √3)]
[5(2+√3)÷((2− √3))2]
[5(2 +√3) ÷ (2)2− (√3)2]
[5(2 +√3) ÷(4− 3)]
= 5(2 + √3)
Source: Myschool Past Questions Archive (Record #41299)
Mathematics
UTME / JAMB 2015
Algebraic Expressions, Polynomials & Factorisation
Solution
Factorize \( a^2 − b^2 − 4a + 4 \)
A
(a + b)(a − b)
B
(a − 2 + b)(a - 2- b)
C
(a + 1)(a − 2 + b)
D
(a + b) 2
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
The trinomial = \( a^2 − 4a + 4 \\
a^2 − b^2− 4a + 4 = (a^2 − 4a + 4) − b^2 \\
(a^2 − 2a − 2a + 4) − b^2 \\
a(a − 2)− 2(a − 2)] − b^2 \\
(a − 2)2 − b^2 \\
(a − 2 + b)(a − 2 − b )\)
Source: Myschool Past Questions Archive (Record #41300)
Mathematics
UTME / JAMB 2015
Indices, Logarithms & Surds
Solution
Given that tan x = \(\frac{2}{3}\), where 0o d" x d" 90o, Find the value of 2sinx.
A
\(\frac{2\sqrt{13}}{13}\)
B
\(\frac{3\sqrt{13}}{13}\)
C
\(\frac{4\sqrt{13}}{13}\)
D
\(\frac{6\sqrt{13}}{13}\)
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
tan x = \(\frac{2}{3}\)(given), is illustrated in a right-angled \(\Delta\)
thus m2 = 22 + 32
= 4 + 9 = 13
m = \(\sqrt{13}\)
Hence, 2sin x = 2 x \(\frac{2}{m}\)
2 x\(\frac{2}{\sqrt{13}}\)
= \(\frac{4}{\sqrt{13}}\)
= \(\frac{4}{\sqrt{13}} = \frac{\sqrt{13}}{\sqrt{13}}\)
= \(\frac{4\sqrt{13}}{13}\)
Source: Myschool Past Questions Archive (Record #45797)
Physics
UTME / JAMB 2015
Gas Laws & Heat Transfer
Solution
If the volume of a gas is recorded as 76cm3 at a temperature of 27^\circC with a pressure of 800mmHg. What will be the volume of the gas at S.T.P?
A
36.2cm3
B
25.7cm3
C
72.8cm3
D
24.3cm3
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Using the general gas laws:
\(\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\)
P\(_1\) = 800mmHg, V\(_1\) = 76cm\(^3\), T\(_1\) = 273 + 27 = 300k
P\(_2\) = 760mmHg, V\(_2\) = ? T\(_2\) = 273 + 0 = 273 (@ STP)
\(\frac{800 \times 76}{300} = \frac{760 \times V_2}{273}\)
V\(_2 = \frac{800 \times 76 \times 273}{300 \times 760}\) = 72.8cm\(^3\)
Therefore, the volume of gas at S.T.P = 72.8 cm\(^3\)
Source: Myschool Past Questions Archive (Record #40761)
Physics
UTME / JAMB 2015
Gas Laws & Heat Transfer
Solution
Boyle’s law may be Written as
A
P1V1= P2V2
B
V1 = V2 ÷ T1T2
C
P1T1 = P2T2
D
P1V1 ÷ T1 = P1V1 ÷ T2
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Boyle‘s law stats that the volume of a given mass of a gas, at a constant temperature is inversely proportional to us pressure.
Mathematically
V ∝ l/p, v = k/p (where k is constant)
K = VP
Let k = k1
Then, if k = k, V and P = V1P1
V1P1 = V2P2
Source: Myschool Past Questions Archive (Record #40762)
Physics
UTME / JAMB 2015
Gas Laws & Heat Transfer
Solution
The direction of the path taken by light is called
A
Locus
B
Lines
C
Ray
D
Beam
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
Ray – a beam of light or radiation
Source: Myschool Past Questions Archive (Record #40764)
Physics
UTME / JAMB 2015
Magnetism, Electromagnetism & AC Circuits
Solution
What is the inductance (L) of an inductor whose reactance is 1Ω at 50/ π hertz (H)?
A
100 H
B
0.01H
C
10H
D
1H
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
XL = WL = 2πFL (w = 2πf)
XL = reactance inductor (S.I unit Ω)
L = inductance (L) in Henry
XL = 1Ω, f = 50/π, L = ?
1 = 2× π × 50/π × L
1 = 100L
i.e. 100L = 1
L = 1/100
0.01H
∴ Inductance (L) of a inductor = 0.01H
Source: Myschool Past Questions Archive (Record #40766)
Physics
UTME / JAMB 2015
Current Electricity & Electric Circuits
Solution
A stroboscope can be used to make the wave appear …………..
A
Stationary
B
In motion
C
Dipper
D
Ripple
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Stroboscope is a scientific instrument used to make a wave appears stationary when used
Source: Myschool Past Questions Archive (Record #40768)
Physics
UTME / JAMB 2015
Newton's Laws, Momentum & Collisions
Solution
In an elastic collision
I. Energy is conserved
II. Energy is decreased
III. Energy is increased
IV. Linear momentum conserved
A
I only
B
I and IV only
C
II only
D
III only
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
In an inelastic collision, linear momentum is conserved and energy is decreased
Momentum and kinetic energy are conserved in elastic collision
Source: Myschool Past Questions Archive (Record #40769)
Physics
UTME / JAMB 2015
Equilibrium of Forces, Moments & Flotation
Solution
Body floats in fluid when its …………………
A
Displaces its own volume of the liquid (fluid)
B
Displaces its own weight of the fluid
C
Displace its own density of the fluid
D
Is no longer subjected to gravity
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Note:The principle of floatation states that a floating body displaces its own weight of the fluid or which its float.
For object to sink weight of the object (W) > upthrust of the fluid (v) i.e. w > u
(i.e. weight of the body (or object) mass of the fluid)
Source: Myschool Past Questions Archive (Record #40771)
Physics
UTME / JAMB 2015
Gas Laws & Heat Transfer
Solution
The general gas law can be written as
A
PV ÷ T = a constant
B
PV = a constant
C
v/t = a constant
D
p/T = a constant
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Formula for general gas law
V × 1/T × P
N [(PV) ÷ T] = K is constant
Source: Myschool Past Questions Archive (Record #40773)
Physics
UTME / JAMB 2015
Reflection, Refraction & Dispersion of Light
Solution
A motor boy of a driver saw what seems to appear to be a pool of water a head of him, while his driver drives a new truck on a sunny day. Which of the following explains his observation?
A
He saw a flying objects
B
He must be thinking of water and food
C
He was seeing the shadow of the car
D
The sun ray from the sky were passing from a hot air (layer) to cold layer
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
The appearance of pool of water on road surfaces is called MIRAGE
His observation show that light from the sun ray refracted through a layer of hot air(layer) which is closed to the ground, passes from a hot air layer to the cold layer
Source: Myschool Past Questions Archive (Record #40784)
Physics
UTME / JAMB 2015
Current Electricity & Electric Circuits
Solution
Which of the following is not luminous object?
A
The sun
B
The moon
C
light candle
D
Star
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Sun are self luminous source
Moon is a non – luminous
Source: Myschool Past Questions Archive (Record #40786)