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Mathematics
UTME / JAMB 2016
Inequalities & Linear Programming
Diagram
Solution
From the diagram above, find the required roots/region of x.
Attached Figure / Diagram
A
x\(\leq\)-1, x \(\geq\)4
B
x\(\leq\)4
C
-1\(\leq\)x\(\leq\)4
D
x\(\leq\)-1, o\(\leq\)x\(\leq\)4
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
The required roots/region of x is -1\(\leq\)x\(\leq\)4
Source: Myschool Past Questions Archive (Record #44981)
Physics
UTME / JAMB 2016
Lenses & Optical Instruments
Solution
Myopic defects in the human eye can be corrected through the use of a
A
Concave Mirror
B
Concave lens
C
Prism
D
Convex lens
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
In myopia, distant objects appear blurry because light focuses in front of the retina. A concave lens diverges the light rays, shifting the focus point back onto the retina.
Source: Myschool Past Questions Archive (Record #44659)
Physics
UTME / JAMB 2016
Magnetism, Electromagnetism & AC Circuits
A charged particle is moving in a uniform magnetic field. if the direction of motion of the charged particle is parallel to the magnetic field, the path of the charge will
A
Be a straight line
B
Curve inwards
C
Be a parabola
D
Curve outwards
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #44661)
Physics
UTME / JAMB 2016
Calorimetry, Latent Heat & Change of State
What happens to a water pool on a day when the humidity of the air is very low?
A
Temperature decreases
B
Slow evaporation
C
Temperature increases
D
Rapid evaporation
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #44662)
Physics
UTME / JAMB 2016
Circular Motion, Gravitation & Simple Harmonic Motion
Solution
A satellite moves in a circular orbit of radius 4R round the earth. The acceleration of the satellite in terms of g is
A
\(\frac{g}{16}\)
B
\(\frac{g}{4}\)
C
\(\frac{4}{g}\)
D
\(\frac{16}{g}\)
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
\(\frac{g}{R^2}\) = \(\frac{g}{4^2}\) = \(\frac{g}{16}\)
Source: Myschool Past Questions Archive (Record #44663)
Physics
UTME / JAMB 2016
Current Electricity & Electric Circuits
I.Chemical II.Sound III.Electricity
Which of the above forms of energy can directly be converted to light energy?
A
I and II only
B
II and III only
C
I, II and III
D
I and III only
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #44664)
Physics
UTME / JAMB 2016
Reflection, Refraction & Dispersion of Light
If the distance between the object and the pinhole of a pinhole camera is reduced by half the size of the image of the object
A
Is quadrupled
B
Is halved
C
Remains the same
D
Is double
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option D.
Source: Myschool Past Questions Archive (Record #44665)
Physics
UTME / JAMB 2016
Reflection, Refraction & Dispersion of Light
Solution
An object is placed 15cm in front of a plane mirror. If the mirror is moved further 5cm away from the object and the image is
A
80cm
B
40cm
C
50cm
D
70cm
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
An object is placed 15 cm in front of a plane mirror.
Initial Image Position: The image is 15 cm behind the mirror.
Mirror Movement: The mirror is moved 5 cm further away from the object, making the distance to the mirror 20 cm.
New Image Position: The new image is now also 20cm behind the mirror.
Conclusion
The total distance from the object to the image is 20 cm + 20 cm = 40 cm.
Source: Myschool Past Questions Archive (Record #44666)
Physics
UTME / JAMB 2016
Work, Energy, Power & Simple Machines
Which of the following statements is correct about a machine?
A
Efficiency of a machine is always greater than I
B
Efficiency decreases with an increase in friction
C
Velocity ratio depends on friction
D
Mechanical advantage increases with an increase in friction
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #44667)
Physics
UTME / JAMB 2016
Current Electricity & Electric Circuits
The instrument used to view stars is the
A
Prism binoculars
B
Telescope
C
Film projector
D
Microscope
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #44668)
Physics
UTME / JAMB 2016
Current Electricity & Electric Circuits
Solution
What is the angular magnification of a telescope having objective and eyepiece lenses of a focal lengths 30cm and 3cm respectively?
A
60
B
10
C
30
D
90
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
M = \(\frac{y}{x}\) = \(\frac{30}{3}\)
= 10
Source: Myschool Past Questions Archive (Record #44679)
Physics
UTME / JAMB 2016
Current Electricity & Electric Circuits
A wire of length 10m is cooled from 50oC to 10oC. Calculate the decrease in the length of the wire. [c = 3 x 10-5K-1]
A
1.8 x 10-4m
B
1.5 x 10-4m
C
1.2 x 10-2m
D
1.8 x 10-3m
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #44681)
Physics
UTME / JAMB 2016
Gas Laws & Heat Transfer
Solution
When an athlete perspires after running, he loses heat through
A
Evaporation
B
Conduction
C
Radiation
D
Convection
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
When sweat evaporates from the surface of the skin, it absorbs heat from the body, effectively cooling the athlete down. Thus, evaporation is the primary way an athlete loses heat through perspiration.
Source: Myschool Past Questions Archive (Record #44682)
Physics
UTME / JAMB 2016
Current Electricity & Electric Circuits
Solution
The rate of cooling of a heated quantity of liquid in an enclosure depends on the
A
Pressure of the liquid
B
Temperature in the enclosure
C
Pressure of the enclosure
D
Volume of the liquid
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
The temperature difference between the heated liquid and the surrounding environment (the enclosure) is a crucial factor in determining the rate of heat transfer.
According to Newton's Law of Cooling, the rate of cooling is proportional to the temperature difference between the object and its surroundings.
Source: Myschool Past Questions Archive (Record #44684)
Physics
UTME / JAMB 2016
Calorimetry, Latent Heat & Change of State
Solution
The heat required to raise a mass of a substance through 1K is known as
A
Specific heat capacity
B
Specific latent heat of vaporization
C
Capacity latent heat of fusion
D
Heat capacity
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Heat capacity is the amount of heat required to raise the temperature of a given mass or object by 1 K (or 1 ^\circC).
Source: Myschool Past Questions Archive (Record #44685)