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Chemistry
UTME / JAMB 2017
Atomic Structure, Orbitals & Nuclear Chemistry
Solution
A particle that contains 9 protons, 10 neutrons and 10 electrons is
A
positive ion
B
neutral atom of a metal
C
neutral atom of a non-metal
D
negative ion
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
protons = 9
neutrons = 10
electrons = 10
Electronic configuration = 2, 8
Ground state Electronic configuration=2, 7
It means that the atom has gained an electron thereby making it have a negative ion.
When an atom donates an electron, it becomes positively charged.
When an atom accepts an electron, it becomes negatively charged
Source: Myschool Past Questions Archive (Record #46571)
Chemistry
UTME / JAMB 2017
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
Ethene is prepared industrially by
A
Reforming
B
Polymerization
C
Distillation
D
Cracking
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
Ethene is produced from cracking which involves breaking up large hydrocarbon molecules into smaller and more useful bits. This is achieved by using high temperatures and pressures without a catalyst.
C15H32 → 2C2H4 + C3H6 + C8H14
......Δheat...ethene........propene.........octane
Source: Myschool Past Questions Archive (Record #46575)
Chemistry
UTME / JAMB 2017
Kinetic Theory of Matter & Gas Laws
Solution
Calculate the amount in moles of a gas which occupies 10.5 dm3 at 6 atm and 30oC [R = 0.082 atm dm3 K-1 mol-1]
A
2.536
B
1.623
C
4.736
D
0.394
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
For an ideal gas PV = nRT
Amount in moles = n
Volume v = 10.5dm3
Pressure P = 6atm
Temperature T = 30^\circC + 273 = 303k
R, Gas constant = 0.082 atmdm3k-1 mol
Recall from ideal gas equation
pv = nRT
n = \(\frac{RV}{RT}\)
n = \(\frac{6 \times 10.5}{0.082 \times 303}\)
n= 2.536mol
Source: Myschool Past Questions Archive (Record #46587)
Chemistry
UTME / JAMB 2017
Kinetic Theory of Matter & Gas Laws
Solution
If 100cm3 of oxygen pass through a porous plug is 50 seconds, the time taken for the same volume of hydrogen to pass through the same porous plug is? [O = 16, H = 1]
A
10.0s
B
12.5s
C
17.7s
D
32.0s
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Rate of diffusion \(\frac{\alpha_1}{Density}\) or \(\frac{1}{\sqrt{Mm}}\)
Rate = \(\frac{1}{time}\)
\(\frac{1}{time}\) \(\frac{\alpha_1}{Density}\) or \(\frac{1}{\sqrt{Molarmass}}\)
Time \(\alpha \sqrt{Density}\) or \(\sqrt{Molarmass}\)
At constant volume of 100cm3
\(\frac{t_{o2}}{\sqrt{Mn_{o2}}}\) = \(\frac{t_{n2}}{\sqrt{1 \times 2}}\)
\(\frac{50}{4 \sqrt{2}}\) = \(\frac{t_{n2}}{\sqrt{2}}\)
tn2= 12.5s
Source: Myschool Past Questions Archive (Record #46593)
Chemistry
UTME / JAMB 2017
Metals, Transition Elements & Extraction
Solution
Due to the high reactivity of sodium, it is usually stored under
A
water
B
mercury
C
paraffin
D
phenol
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Na is kept under kerosene (paraffin) to avoid reactivity with air.
Paraffin is also known as Kerosene.
Na(sodium) is kept in kerosene to prevent it from coming in contact with oxygen and moisture. If this happens, it will react with the moisture present in air and form sodium hydroxide.
Source: Myschool Past Questions Archive (Record #46602)
Chemistry
UTME / JAMB 2017
Water, Solutions & Solubility
Solution
The furring of kettles is caused by the presence in water of
A
calcium hydrogentrioxocarbonate (IV)
B
calcium trioxocarbonate (IV)
C
calcium tetraoxosulphate (VI)
D
calcium hydroxide
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Furring of kettles is caused by the temporary hardness in water. Temporary hardness in water is caused by calcium and magnesium trioxocarbonate (IV)
CaCO3 causes the furring of kettles
Source: Myschool Past Questions Archive (Record #46604)
Chemistry
UTME / JAMB 2017
Water, Solutions & Solubility
Solution
Water for town supply is chlorinate to make it free from
A
bad colour
B
bacteria
C
temporary hardness
D
permanent hardness
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Chlorine helps to keep water from germs and bacteria.
Source: Myschool Past Questions Archive (Record #46605)
Chemistry
UTME / JAMB 2017
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
Ca(OH)2(s) + 2NH4Cl(s) → CaCl2(s) + 2H2O(l) + X. In the reaction above X is
A
NO2
B
NH3
C
N2O
D
NO2
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Balancing the chemical equation.
Ca[OH]2 + 2NH4Cl → CaCl2 + 2H2O + 2NH3
X = NH3
Source: Myschool Past Questions Archive (Record #46607)
Chemistry
UTME / JAMB 2017
Chemical Energetics & Thermochemistry
Solution
X(g) + 3Y(g) ---- 2z(g) H = +ve. if the reaction above takes place at room temperature, the G will be
A
negative
B
zero
C
positive
D
indeterminate
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
\DeltaG= \DeltaH − T\DeltaS.
To determine whether \DeltaG will be positive or negative, the value of \DeltaH(change in enthalpy) and \DeltaS (change in entropy) must be given. Likewise the temperature.
Entropy represents the degree of disorder in a system. In a gaseous reaction, this is determined by the change in the number of moles of gas.
Reactants: 1 mole of X + 3 moles of Y = 4 moles of gas
Products: 2 moles of Z = 2 moles of gas.
The spontaneity of a reaction is determined by the equation: \DeltaG= \DeltaH − T\DeltaS.
\DeltaH is positive , T = is always positive, \DeltaS = is negative. Substituting the signs into the equation: \DeltaG= \DeltaH − T\DeltaS = (+) - (T x (-)) = +
Since both terms are positive, \DeltaG must be positive regardless of the specific value of T as long as T is expressed in Kelvin (which is always > 0). A positive \DeltaG indicates the reaction is non-spontaneous at room temperature.
Source: Myschool Past Questions Archive (Record #46608)
Chemistry
UTME / JAMB 2017
Oxidation, Reduction & Redox Reactions
Solution
Cu\(_2\)S(g) + O\(_2\)(g) → 2Cu + SO\(_2\)(g)
What is the change in the oxidation number of copper in the reaction?
A
0 to + 2
B
0 to + 1
C
+ 1 to 0
D
+ 2 to + 1
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
In the reactant;
Cu\(_2\)S
2 Cu - 2(1) = 0
2 Cu = 2
Cu = \(\frac{2}{2}\)
Cu = +1
In the product, Cu
Cu = O (Oxidation state of an element in its free state is 0)
The oxidation number of Cu in Cu\(_2\)S and Cu respectively is +1 and 0 respectively
Source: Myschool Past Questions Archive (Record #46541)
Chemistry
UTME / JAMB 2017
Stoichiometry, Mole Concept & Volumetric Analysis
Diagram
Solution
In the diagram above. X is
Attached Figure / Diagram
A
SO3
B
SO2
C
S
D
H2S
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
The setup represents the production of sulfur dioxide. And the cylinder marked X is SO2
Source: Myschool Past Questions Archive (Record #46542)
Chemistry
UTME / JAMB 2017
Non-Metals & Their Compounds
Diagram
Solution
The diagram above. Y is
Attached Figure / Diagram
A
fused CaO
B
H2O
C
NaOH
D
Concentrated H2SO4
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
In the preparation of sulphur dioxide by the action of dilute acids on sulphates and bisulphites. conc H2SO4 helps to release SO2 from the mixture.
The setup represents the production of sulphur dioxide
Source: Myschool Past Questions Archive (Record #46543)
Chemistry
UTME / JAMB 2017
Electrolysis & Electrochemical Cells
Solution
Calculate the mass of copper deposited when a current of 0.5 ampere was passed through a solution of copper(II) chloride for 45 minutes in an electrolytic cell. [Cu = 64, F = 96500Cmol-1]
A
0.300g
B
0.250g
C
0.2242g
D
0.448g
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
M = \(\frac{\text{Molar mass × Quantity of Electricity}}{\text{96500 × no of charge}}\)
= \(\frac{MmIT}{96500n}\)
Copper II Chloride = CuCl2
CuCl2 → Cu2+ + 2Cl2
Mass of compound deposited = \(\frac{\text{Molar mass × Quantity of Electricity}}{\text{96500 × no of charge}}\)
Q = IT
I = 0.5A
T = 45 × 60
T = 2700s
Q = 0.5 × 2700
= 1350c
Molarmass = 64gmol-1
no of charge = + 2
Mass = \(\frac{64 \times 1350}{96500 \times 2}\)
Mass = 0.448g
Source: Myschool Past Questions Archive (Record #46544)
Chemistry
UTME / JAMB 2017
Stoichiometry, Mole Concept & Volumetric Analysis
Diagram
Solution
The IUPAC nomenclature of the structure above is
Attached Figure / Diagram
A
3-methybut-3-ene
B
2-methylbut-1-ene
C
2-ethylprop-1-ene
D
2-methylbut-2-ene
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
CH2CH2 - CCH3CH2
Start the numbering from the terminal carbon.
Source: Myschool Past Questions Archive (Record #46545)
Chemistry
UTME / JAMB 2017
Stoichiometry, Mole Concept & Volumetric Analysis
Solution
The IUPAC nomenclature of the structure above is
A
3-methybut-3-ene
B
2-methylbut-1-ene
C
2-ethylprop-1-ene
D
2-methylbut-2-ene
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
CH2CH2 - CCH3CH2
Start the numbering from the terminal carbon.
Source: Official Exam / Past Question Archive