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Physics
UTME / JAMB 2025
Heat Energy & Temperature
Solution
A method of demagnetization is
A
placing the magnetic bar in a solenoid
B
double-stroking the magnet with soft in n-s direction
C
heating a magnetic bar red hot and allowed to cool e-w direction
D
hammering the magnetic bar repeatedly in n-s direction
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
This process disrupts the alignment of magnetic domains, effectively demagnetizing the bar.
Source: Official Exam / Past Question Archive
Chemistry
UTME / JAMB 2025
Atomic Structure and Periodic Table
Solution
The molecule with the highest number of lone pair of electrons is
A
H\(_2\)O
B
NH\(_3\)
C
CH\(_4\)
D
C0\(_2\)
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
A lone pair of electrons is a pair of valence electrons in an atom that are not shared with another atom in a chemical bond, also known as a non-bonding pair. These electrons reside in the outermost electron shell, occupy space, and significantly influence a molecule's shape, polarity, and reactivity, often depicted as dots in Lewis structures.
To determine the number of lone pairs, we analyze the Lewis structure of each molecule:
CH\(_4\)(Methane): Carbon forms four single bonds with hydrogen atoms. There are zero lone pairs in the molecule.
NH\(_3\)(Ammonia): Nitrogen forms three single bonds with hydrogen atoms and has one lone pair of electrons.
H\(_2\)O(Water): Oxygen forms two single bonds with hydrogen atoms and has two lone pairs of electrons.
CO\(_2\)(Carbon Dioxide): Carbon forms two double bonds with oxygen atoms. Each oxygen atom has two lone pairs, totaling four lone pairs of electrons in the molecule. :. The molecule with the highest number of lone pairs of electrons is CO\(_2\) - Option D
Source: Myschool Past Questions Archive (Record #74083)
Chemistry
UTME / JAMB 2025
Matter & Separation Techniques
Solution
The composition of petroleum varies because it is a
A
hydrocarbon
B
liquid
C
mixture
D
natural resource
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The correct option is C. mixture.
Petroleum is a naturally occurring complex mixture of various organic compounds, predominantly hydrocarbons, including alkanes, cycloalkanes and hydrocarbons. The exact composition of crude oil can vary depending on its source, location and geological history of the oil deposit.
The other options are not correct because:
A. hydrocarbon is a component of crude oil, but does not explain the variation in composition.
B. liquid is a state of matter, not a reason for variation in composition.
D. natural resources is a broad term that includes petroleum, but it doesn't specifically address the variation in composition.
Source: Myschool Past Questions Archive (Record #74084)
Chemistry
UTME / JAMB 2025
Matter & Separation Techniques
Diagram
Solution
In the table above, the two compounds that will combine in the presence of an acid-catalyzed compound, V is
Attached Figure / Diagram
A
I and IV
B
III and IV
C
I and II
D
II and III
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Th formula RCOOR' represents alkanoates (esters). However, the two compounds that combine in the presence of an acid catalyst to form an alkanoate (ester) and water are an alkanoic acid (carboxylic acid) and an alkanol (alcohol). This reaction is known as esterification. The general equation is:
I IV Acid catalyst V
ROH + RCOOH → RCOOR' + H\(_2\)O
alkanol alkanoic acid esters water
B. The reaction between a carboxylic acid (RCOOH) and an ether (ROR′) generally does not readily occur under normal conditions because ethers are relatively unreactive. Ethers are stable compounds and do not typically react directly with carboxylic acids to form a new product.
C. The reaction between an alcohol (ROH) and a ketone (RCOR') can produce hemiacetals and, with excess alcohol and an acid catalyst, acetals.
ROH + RCOR' ⇌ R\(_2\)C(OH)(OR')
D. The functional groups involved are an ether (R-O-R′) and a ketone (R-CO-R′). Ethers are known for being generally unreactive, often used as solvents because they do not easily undergo chemical reactions. In the absence of specific strong reagents (like strong acids, bases, or reducing/oxidizing agents) or extreme conditions, these two stable organic compounds will simply coexist as a mixture, with no new product formed
The correct answer is option A
Source: Myschool Past Questions Archive (Record #74085)
Chemistry
UTME / JAMB 2025
Atomic Structure and Periodic Table
Solution
An example of an alkaline gas is
A
HCl
B
N\(_2\)
C
NH\(_3\)
D
NO\(_2\)
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
The correct answer is NH\(_3\) - option C
A. HCl (Hydrogen Chloride) is a colourless, pungent gas that is highly soluble in water, forming a strong acid (hydrochloric acid), and is classified as a hydrogen halide. While the gas itself isn't acidic (it needs water), it's highly corrosive and an air pollutant, reacting with moisture to create corrosive acid aerosols.
B. N\(_2\) is a neutral gas and not an alkaline gas because it's very unreactive and doesn't readily donate or accept protons or electron pairs when dissolved in water, showing no effect on litmus paper.
C. NH\(_3\) is an example of an alkaline gas. Ammonia (NH\(_3\)), which is a colourless gas with a pungent smell, forms basic (alkaline) solutions when dissolved in water, producing hydroxide ions.
D. NO\(_2\) is an acidic gas and not an alkaline gas because it reacts with water in the atmosphere to form nitric acid (HNO\(_3\) and nitrous acid(HNO\(_2\)), thereby forming acid rain.
:. The answer is NH\(_3\) - option C
Source: Myschool Past Questions Archive (Record #74086)
Chemistry
UTME / JAMB 2025
Matter & Separation Techniques
Solution
The dusty and sand particles present in the air is an example of
A
a suspension
B
a dispersion
C
an emulsion
D
a saturated solution
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Dusty and sand particles present in the air form a suspension because it is a heterogeneous mixture where solid particles are dispersed in a gas (air).
B. a dispersion: is a general term for any system in which particles of one material are distributed in a continuous phase of another. Suspension is a specific type of dispersion.
C. an emulsion: is a specific type of colloid where both the dispersed phase and the dispersion medium are liquids that are typically immiscible (do not mix). Eg milk.
D. a saturated solution: is a homogeneous mixture (a true solution) where the maximum amount of a solute has been dissolved in a solvent at a specific temperature. The particles are molecular in size and do not settle. Air with dust and sand is not a solution as the particles do not dissolve.
The correct answer is suspension - option A
Source: Myschool Past Questions Archive (Record #74087)
Chemistry
UTME / JAMB 2025
Atomic Structure and Periodic Table
Solution
The property of metal that makes it suitable as a catalyst is
A
filled f-orbital
B
partially filled d-orbitals
C
partially filled f-orbital
D
filled d-orbital
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Transition metals are elements in the d-block (Groups 3-12) of the periodic table, defined by having partially filled d-orbitals, allowing them to form multiple ions with varying charges, create coloured compounds, act as catalysts, and form strong alloys.
The catalytic activity of metals, particularly transition metals, is largely due to the presence of partially filled d-orbitals- Option B
A. filled f-orbital and C. partially filled f-orbital: These orbitals are characteristic of f-block elements (lanthanides and actinides), which have different properties and are not typically the primary metals used as catalysts in the way transition metals are.
D. filled d-orbital: Elements with completely filled d-orbitals in their common oxidation states (like zinc, cadmium, and mercury) are not considered transition metals and do not exhibit the same significant catalytic properties.
Source: Myschool Past Questions Archive (Record #74088)
Chemistry
UTME / JAMB 2025
Kinetics, Energetics and Equilibrium
Solution
When \DeltaH is positive and small, and \DeltaS is positive and large, the reaction will be
A
Non-spontaneous
B
favour forward reaction only
C
favour backward reaction only
D
spontaneous
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
The spontaneity of a reaction is determined by the Gibbs free energy change (\DeltaG), given by the equation: \DeltaG = \DeltaH − T\DeltaS.
For a reaction to be spontaneous, \DeltaG must be negative (\DeltaG < 0).
When a small positive number is subtracted from a large negative number (or a large positive T\DeltaS term) is subtracted from a small \DeltaH, the resulting \DeltaG. Therefore, a reaction with a positive (endothermic) and small \DeltaH, and a positive (increase in disorder) and large \DeltaS, will be spontaneous, especially at high temperatures where the T\DeltaS term dominates.
A. Non-spontaneous: A non-spontaneous reaction would have a positive \DeltaG. Under the given conditions, \DeltaG is negative, so the reaction is not non-spontaneous.
B. favour forward reaction only: A spontaneous reaction inherently favors the forward reaction, leading to the formation of products. Thus, "spontaneous" is a more complete and accurate thermodynamic description than just "favor forward reaction only," which could imply specific equilibrium conditions not fully defined by spontaneity alone (though they are related).
C. favour backward reaction only: The backward reaction is spontaneous if the forward reaction is non-spontaneous (\DeltaG>0). Since the forward reaction is spontaneous under these conditions, the backward reaction is non-spontaneous.
The correct answer is spontaneous - option D.
Source: Myschool Past Questions Archive (Record #74089)
Chemistry
UTME / JAMB 2025
Acids, Bases, and Salts
Solution
Calculate the pH of 0.001M KOH solution.
A
11
B
14
C
12
D
3
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Given:
Concentration of OH = [OH\(^-\)] = 0.001 M
At 25\(^0\)C, pH + pOH = 14
Hence, to find pH of KOH, we need to find the pOH first, then substitute the value into the equation above.
Recall, pOH = - Log [OH\(^-\)]
= - Log [0.001]
= - ( - 3)
pOH = 3
pH + pOH = 14
pH + 3 = 14
pH = 14 - 3 = 11
;. pH = 11 - option A
Source: Myschool Past Questions Archive (Record #74103)
Chemistry
UTME / JAMB 2025
Acids, Bases, and Salts
Solution
The acid used in making baking soda and soft drink is
A
tartaric acid
B
fatty acid
C
boric acid
D
citric acid
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Tartaric acid is a common edible acid used as a component of baking powder. It reacts with the baking soda (sodium bicarbonate) in the presence of moisture and heat to produce carbon dioxide gas, which causes baked goods to rise and become fluffy. It is also used industrially as an acidulant in many food products, including carbonated soft drinks, fruit jellies, and candies.
B. fatty acid: Fatty acids are carboxylic acids with long aliphatic chains and are a major component of fats and lipids. They are not used as an acidulant in soft drinks or as a component in baking powder.
C. boric acid: Boric acid is a weak acid often used as an antiseptic, insecticide, or fire retardant. It is not an edible acid used in food products like baking soda or soft drinks.
D. citric acid: While citric acid is a very common acidulant in soft drinks and other food products, where it provides a sharp, tangy flavor, tartaric acid is the option specifically associated with both baking soda (as a baking powder component) and soft drinks.
The correct answer is tartaric acid - option A
Source: Myschool Past Questions Archive (Record #74104)
Chemistry
UTME / JAMB 2025
Stoichiometry & Mole Concept
Solution
NH\(_3\) \((_g\)) + HCl\((_g\)) → NH\(_4\)Cl \(_(g)\)
In the reaction above, increase in pressure will
A
lower the equilibrium constant
B
favour the product
C
favour the reactant
D
increase the equilibrium constant
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
An increase in pressure will favour the forward reaction (production of NH\(_4\)Cl).
According to Le Chatelier's principle, increasing the pressure on a system at equilibrium will cause the equilibrium to shift in the direction that reduces the total number of moles of gas. In this reaction, the reactant side has two moles of gas (one NH\(_3\) and one HCl), while the product side has zero moles of gas (solid NH\(_4\)Cl). The system relieves the pressure by favoring the side with fewer gas molecules, thus promoting the formation of the solid product.
NH\(_3\) + HCl ⇌ NH\(_4\)Cl
An increase in pressure will favour the forward reaction (production of NH\(_4\)Cl).
Source: Myschool Past Questions Archive (Record #74105)
Chemistry
UTME / JAMB 2025
Atomic Structure and Periodic Table
Solution
The compound CH\(_3\)CH(NH\(_2\))CH\(_2\)CH\(_2\)CH\(_3\) is an example of a
A
primary amine
B
tertiary amine
C
quaternary amine
D
secondary amine
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
An amine is classified based on the number of carbon atoms directly bonded to the nitrogen atom. An amine is classified as primary, secondary, or tertiary based on the number of alkyl or aryl groups (carbon-containing groups) attached directly to the nitrogen atom.
B. tertiary amine: A tertiary amine has the nitrogen atom bonded to three carbon-containing groups and no hydrogen atoms.
C. quaternary amine: A quaternary amine (or quaternary ammonium salt) has the nitrogen atom bonded to four carbon-containing groups and carries a positive charge (it is an ion, not a neutral amine).
D. secondary amine: A secondary amine has the nitrogen atom bonded to two carbon-containing groups and one hydrogen atom.
In the compound CH\(_3\)CH(NH\(_2\))CH\(_2\)CH\(_2\)CH\(_3\),(also known as 2-pentanamine), the nitrogen atom is bonded to two hydrogen atoms and one alkyl group (the pentan-2-yl group). However, since the nitrogen atom is bonded to only one carbon-containing group, it is a primary amine.
The correct answer is primary amine - option A
Source: Myschool Past Questions Archive (Record #74106)
Chemistry
UTME / JAMB 2025
Acids, Bases, and Salts
Solution
Nitrogen, a component of air is used for
A
production of cooling agent
B
production of margarine
C
production of HNO\(_3\)
D
manufacturing of oil
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Nitrogen from the air is a key component in the industrial manufacture of ammonia (NH\(_3\)) through the Haber process, which is then used as a primary material in the production of nitric acid (HNO\(_3\)) - Option C
A. production of cooling agent: While liquid nitrogen is an excellent cooling agent (refrigerant), this is a use of the separated gas and not a large-scale process for which nitrogen is primarily sourced from the air in the context of the other options provided. The main large-scale use is chemical manufacturing.
B. production of margarine: Margarine is made from vegetable oils and water, sometimes involving hydrogenation processes, but nitrogen itself is not a primary component in its manufacture, though it may be used in food packaging to prevent oxidation.
D. manufacturing of oil: Nitrogen is not used to manufacture oil. It is used as an inert atmosphere in various industrial processes, including potentially parts of the petrochemical industry, but not the synthesis of oil itself.
Source: Myschool Past Questions Archive (Record #74107)
Chemistry
UTME / JAMB 2025
Atomic Structure and Periodic Table
Solution
2Na + Cl\(_2\) → 2NaCl
In the reaction above, the specie that undergoes reduction is
A
Na
B
NaCl
C
Cl\(^-\)
D
Cl\(_2\)
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
By definitions, Reduction is defined as the gain of electrons or a decrease in oxidation state.
In the reaction, elemental chlorine (Cl₂) has an initial oxidation state of 0.
In the product, sodium chloride (NaCl), the chlorine is in the form of a chloride ion (Cl⁻), with an oxidation state of -1.
The change from an oxidation state of 0 to -1 indicates a gain of electrons and thus, Cl₂ is the species that undergoes reduction.
Consequently, the correct answer is option D.
Source: Myschool Past Questions Archive (Record #74108)
Chemistry
UTME / JAMB 2025
Matter & Separation Techniques
Solution
The sublimation of solid to gas involves
A
energy absorption
B
vapourization
C
melting
D
osmotic diffusion
medium Difficulty
Verified Correct Answer: Option A
Chemical Principles & Mechanism
Sublimation is the process of a substance transitioning directly from the solid to the gas state without passing through the liquid state. This process is endothermic, meaning it absorbs heat energy from its surroundings to provide enough energy for the molecules to overcome the intermolecular forces holding them in the solid state and escape into the vapour phase. Hence, the correct answer is option A - energy absorption
B. vapourization is the phase transition from a liquid to a gas (either through evaporation or boiling).
C. melting is the process where a solid changes into a liquid.
D. osmotic diffusion is a biological or chemical process related to the movement of solvents and solutes across a semipermeable membrane and is unrelated to the phase change of sublimation.
Source: Myschool Past Questions Archive (Record #74109)