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Biology
UTME / JAMB 2020
Supporting Tissues & Skeletal System
Which of the following vertebrates has the most simple structured heart
A
reptile
B
fish
C
mammal
D
Amphibian
medium Difficulty
Verified Correct Answer: Option B
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option B.
Source: Myschool Past Questions Archive (Record #56854)
Biology
UTME / JAMB 2020
Adaptation & Evolution
Diagram
Use the diagram to answer the question.
The type of protective adaption exhibited by the animal is
Attached Figure / Diagram
A
disruptive colouration
B
flash colouration
C
countershading colouration
D
warning colouration
medium Difficulty
Verified Correct Answer: Option C
Biological Concept & Syllabus Guide
No expanded working has been attached for this question yet. The verified answer is Option C.
Source: Myschool Past Questions Archive (Record #56855)
Mathematics
UTME / JAMB 2019
Statistics (Data Representation, Central Tendency & Dispersion)
Diagram
Solution
The histogram above represents the number of candidates who did Further Mathematics examination in a school. How many candidates scored more than 40?
Attached Figure / Diagram
A
100
B
79
C
150
D
90
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
Number of students that scored above 40 = 55 + 45 + 30 + 15 + 5
= 150 students.
Source: WAEC / JAMB / NECO Classroom Archive (Record #55453)
Physics
UTME / JAMB 2019
Calorimetry, Latent Heat & Change of State
Solution
A metal rod has a length of 100cm at 200°C. At what temperature will its length be 99.4cm. If the linear expansivity of the material of the rod is 2 × 10\(^{-5}\)C\(^{-1}\)
A
\(300^0C\)
B
\(200^0C\)
C
\(100^0C\)
D
\(-100^0C\)
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
L\(_1\) = 100cm, T\(_1\) = 200^\circC
L\(_2\) = 99.4cm, T\(_2\) = ?
\alpha 2 \times 10\(^{-5}\) C\(^{-1}\)
\alpha
=
L\(_2\) - L\(_1\)
L\(_1\)(T\(_2\) - T\(_1\))
2
\times
10\(^{-5}\)
=
110 - 99.4
100(200 - T\(_2\))
=
0.6
100(200 - T\(_2\))
2 \times 10\(^{-5} \times 100(200 - T_2\)) = 0.6
200
-
T\(_2\)
=
0.6
0.002
=
300^\circC
T\(_2\) = 200 - 300 = -100^\circC
Source: WAEC / JAMB / NECO Classroom Archive (Record #55260)
Physics
UTME / JAMB 2019
Equilibrium of Forces, Moments & Flotation
Diagram
Solution
The diagram shows a uniform meter rule AB which balances horizontally at the 90cm mark when a mass of 0.2kg is suspended from B. Calculate the mass of the meter rule.
Attached Figure / Diagram
A
0.05kg
B
0.20kg
C
0.80kg
D
1.00kg
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
M\(_r\)(90 - 50) = 0.2(100 - 90)
40M\(_r\) = 0.2 \times 10
M\(_r\) = \(\frac{2}{40}\) = 0.05kg
Source: WAEC / JAMB / NECO Classroom Archive (Record #55821)
Physics
UTME / JAMB 2019
Circular Motion, Gravitation & Simple Harmonic Motion
Solution
A siren having a ring of 200 hole makes 132 rev/min. A jet of air is directed on the set of holes. Calculate the frequency and wavelength in air of the note produced (take v = 350m/s)
A
0.795m
B
0.625m
C
0.335m
D
0.125m
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
n = 200, S = 132 rev/min, v = 350m/s\(^2\)
f
=
ns
=
200
\times
132
rev
min
\times
1min
60s
=
440Hz
\lambda
=
v
f
=
350
440
=
0.795m
Source: WAEC / JAMB / NECO Classroom Archive (Record #55265)
Physics
UTME / JAMB 2019
Magnetism, Electromagnetism & AC Circuits
Diagram
Solution
A coil X is moved quickly away from the end Y of a stationary metal bar and a current then flows in X as shown above.
Then
Attached Figure / Diagram
A
the bar is not a magnet
B
Y is a north pole
C
Y is a South pole
D
Y repels coil X
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
N - S magnet is moved towards a coil production clockwise direction of current in the coil.
- This is the same as a coil moved away from S-N (Y - North pole)
Source: WAEC / JAMB / NECO Classroom Archive (Record #55653)
Chemistry
UTME / JAMB 2019
Kinetic Theory of Matter & Gas Laws
Solution
The velocity, V of a gas is related to its mass, M by (k = proportionality constant)
A
V = \(\frac{k}{M}\)
B
V = \(\frac{k}{M^{\frac{1}{2}}}\)
C
V = \(kM^2\)
D
V = \((\frac{k}{M})^{\frac{1}{2}}\)
medium Difficulty
Verified Correct Answer: Option B
Chemical Principles & Mechanism
Recall:
V = \(\sqrt{\frac{3RT}{M}}\)
\(\therefore V \propto \frac{1}{\sqrt{M}}\)
\(V = \frac{k}{\sqrt{M}}\)
V = \(\frac{k}{M^{\frac{1}{2}}}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #56012)
Chemistry
UTME / JAMB 2019
Organic Chemistry II: Functional Groups, Polymers & Biomolecules
Solution
2-methylprop-1-ene is an isomer of?
A
3-methyl but-1-ene
B
2-methyl but-1-ene
C
but-2-ene
D
pent-2-ene
medium Difficulty
Verified Correct Answer: Option C
Chemical Principles & Mechanism
Isomers of Butene: are But-1-ene, But-2-ene, 2-Methylpropene / 2-methylprop-1-ene
Source: WAEC / JAMB / NECO Classroom Archive (Record #55522)
Chemistry
UTME / JAMB 2019
Organic Chemistry I: Hydrocarbons & Crude Oil
Solution
A certain hydrocarbon on complete combustion at s.t.p produced 89.6dm\(^3\) of CO\(_2\) and 54g of water. The hydrocarbon should be?
A
C\(_6\)H\(_6\)
B
C\(_4\)H\(_{10}\)
C
C\(_5\)H\(_{10}\)
D
C\(_4\)H\(_6\)
medium Difficulty
Verified Correct Answer: Option D
Chemical Principles & Mechanism
C\(_x\)H\(_y\) + (x + y/4)O\(_2\) \(\to\) x CO\(_2\) + y/2 H\(_2\)O
89.6 dm\(^3\) \(\to\) x moles CO\(_2\)
22.4 dm\(^3\) \(\to\) 1 mole CO\(_2\)
x = \(\frac{89.6}{22.4}\)
= 4 moles CO\(_2\)
54g of H\(_2\)O \(\to\) k moles H\(_2\)O
18g H\(_2\)O \(\to\) 1 mole H\(_2\)O
k = \(\frac{54}{18}\)
= 3 moles H\(_2\)O
From the equation above,
x = 4
k = y/2 = 3
y/2 = 3 \(\implies\) y = 6
\(\therefore\) The hydrocarbon C\(_x\)H\(_y\) = C\(_4\)H\(_6\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #55521)
Mathematics
UTME / JAMB 2019
Algebraic Expressions, Polynomials & Factorisation
Solution
Make q the subject of the formula in the equation \(\frac{mn}{a^2} - \frac{pq}{b^2} = 1\)
A
\(q = \frac{b^2(mn - a^2)}{a^2 p}\)
B
\(q = \frac{m^2 n - a^2}{p^2}\)
C
\(q = \frac{mn - 2b^2}{a^2}\)
D
\(q = \frac{b^2 (n^2 - ma^2)}{n}\)
medium Difficulty
Verified Correct Answer: Option A
Step-by-Step Mathematical Solution
\(\frac{mn}{a^2} - \frac{pq}{b^2} = 1\)
\(\frac{mn}{a^2} - 1 = \frac{pq}{b^2}\)
\(\frac{mn - a^2}{a^2} = \frac{pq}{b^2}\)
\(pq = \frac{b^2 (mn - a^2)}{a^2}\)
\(q = \frac{b^2(mn - a^2)}{a^2 p}\)
Source: Myschool Past Questions Archive (Record #54942)
Mathematics
UTME / JAMB 2019
Trigonometry, Elevation & Bearings
Solution
The angle of elevation of the top of a tree from a point on the ground 60m away from the foot of the tree is 78^\circ. Find the height of the tree correct to the nearest whole number.
A
148m
B
382m
C
282m
D
248m
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
\(\tan 78 = \frac{h}{60}\)
\(h = 60 \tan 78\)
\(h = 60 \times 4.705 = 282.27m\)
\(\approxeq\) 282m to the nearest whole number.
Source: Myschool Past Questions Archive (Record #54944)
Mathematics
UTME / JAMB 2019
Binary Operations, Matrices & Determinants
Solution
A binary operation \(\otimes\) is defined by \(m \otimes n = mn + m - n\) on the set of real numbers, for all m, n \(\in\) R. Find the value of 3 \(\otimes\) (2 \(\otimes\) 4).
A
6
B
25
C
15
D
18
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
\(m \otimes n = mn + m - n\)
3 \(\otimes\) (2 \(\otimes\) 4)
2 \(\otimes\) 4 = 2(4) + 2 - 4 = 6
3 \(otimes\) 6 = 3(6) + 3 - 6 = 15
Source: Myschool Past Questions Archive (Record #54945)
Mathematics
UTME / JAMB 2019
Statistics (Data Representation, Central Tendency & Dispersion)
Solution
Age in years
7
8
9
10
11
No of pupils
4
13
30
44
9
The table above shows the number of pupils in a class with respect to their ages. If a pie chart is constructed to represent the age, the angle corresponding to 8 years old is
A
48.6°
B
56.3°
C
46.8°
D
13°
medium Difficulty
Verified Correct Answer: Option C
Step-by-Step Mathematical Solution
Total number of pupils : 4 + 13 + 30 + 44 + 9 = 100
The number of 8 - year olds = 13
The angle represented by the 8-year olds on the pie chart = \(\frac{13}{100} \times 360^\circ\)
= 46.8^\circ
Source: Myschool Past Questions Archive (Record #54946)
Mathematics
UTME / JAMB 2019
Plane Geometry, Polygons & Circle Theorems
Solution
In a class of 50 students, 40 students offered Physics and 30 offered Biology. How many offered both Physics and Biology?
A
42
B
20
C
70
D
54
medium Difficulty
Verified Correct Answer: Option B
Step-by-Step Mathematical Solution
n(Total) = 50
n(Physics) = 40
n(Biology) = 30
Let n(Physics and Biology) = x
n(Physics only) = 40 -x
n(Biology only) = 30 - x
40 - x + 30 - x + x = 50
70 - x = 50
x = 20
Source: Myschool Past Questions Archive (Record #54947)