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Physics
UTME / JAMB 2022
Measurement of Heat Energy
Solution
What quantity of heat is required to convert 20 g of ice at 0 ºC to water at the same temperature? (Specific latent heat of ice = 336 Jg\(^{-1}\))
A
7.06 x 10\(^{3}\)J
B
5.38 x 10\(^{3}\)J
C
6.72 x 10\(^{3}\)J
D
1.35 x 10\(^{3}\)J
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
quantity of heat = mass * Specific latent heat → 20 * 336
quantity of heat = 6720j or 6.72 x 10\(^{3}\)J
Source: WAEC / JAMB / NECO Classroom Archive (Record #65087)
Physics
UTME / JAMB 2022
Evaporation and Boiling
Solution
The vapour pressure?
A
increases non-linearly with measuring temperature
B
increases linearly with increasing temperature
C
decreases linearly with increasing temperature
D
decreases non-linearly ith measuring temperature
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
The vapor pressure of any substance increases non-linearly with temperature, often described by the Clausius–Clapeyron relation.
As the temperature of a liquid or solid increases its vapor pressure also increases.
Conversely, vapor pressure decreases as the temperature decreases.
i.e. vapor pressure is directly proportional to temperature
Source: WAEC / JAMB / NECO Classroom Archive (Record #64940)
Physics
UTME / JAMB 2022
Gravitational Field
Solution
The gravitational pull on the moon is \(\frac{1}{6}\) that of the earth. If a body weighs 6.0 N on the moon, what will be the weight on the earth?
A
6.0 N
B
5.0 N
C
12.0 N
D
36.0 N
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
A person would weigh six times less on the moon than they do on Earth.
OR
A person would weigh six times more on the earth than they do on moon.
\(\frac{1}{6} of x\) = 6.0N on the moon
x = 6 * 6 = 36
Source: WAEC / JAMB / NECO Classroom Archive (Record #64953)
Physics
UTME / JAMB 2022
Electric Field
Diagram
Solution
For a pear-shaped conductor shown above, the concentration of charge on the outside is highest at?
Attached Figure / Diagram
A
X
B
Z
C
Y
D
K
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
The electric field at the surface of the conductor is perpendicular to the surface.
Charge accumulates, and the field is strongest, on pointy parts of the conductor.
Source: WAEC / JAMB / NECO Classroom Archive (Record #64939)
Physics
UTME / JAMB 2022
Magnetic Field
Solution
A bar magnet is divided into two pieces, which of the following statement is correct?
A
two new magnets are created
B
the magnetic field of each separate piece becomes stronger
C
the electric field is created
D
the bar magnet is demagnetized
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
When it is cut into two, the two cut pieces will have their own north and south poles.
Source: WAEC / JAMB / NECO Classroom Archive (Record #64911)
Physics
UTME / JAMB 2022
Magnetic Field
Solution
A bar magnet is placed near and lying along the axis of a solenoid connected to a galvanometer. The pointer of the galvanometer shows no deflection when?
A
the magnet is moved towards the stationary solenoid
B
there is no relative motion
C
the magnet is moved away from the stationary solenoid
D
the solenoid is moved away from the stationary magnet
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
If both the coil and the magnet are stationary, then there is no change in the magnetic flux and hence no current is induced in the coil.
Source: WAEC / JAMB / NECO Classroom Archive (Record #64915)
Physics
UTME / JAMB 2022
Magnetic Field
Solution
A magnet relay is a device used for?
A
reading the magnitude of magnetic flux
B
controlling another circuit carrying larger current
C
turning in sports
D
storing magnetic field
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Relays are electrically operated switches that open and close the circuits by receiving electrical signals from outside sources.
Source: WAEC / JAMB / NECO Classroom Archive (Record #64933)
Physics
UTME / JAMB 2022
Magnetic Field
Solution
Which expression gives magnetic flux?
A
qVB sin\(\theta\)
B
\(\frac{\mu \phi I}{2 \pi r}\)
C
BA cos \(\theta\)
D
-N \(\frac{d \phi}{dt}\)
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
the magnetic flux through a surface is the surface integral of the normal component of the magnetic field B over that surface.
It is usually denoted Φ or ΦB. The SI unit of magnetic flux is the weber
Mathematically it is represented as B = Φ/A
where B is magnetic flux density in teslas (T),
Φ is magnetic flux in webers (Wb), and
A is area in square meters (m2).
Source: WAEC / JAMB / NECO Classroom Archive (Record #64956)
Physics
UTME / JAMB 2022
Electric Field
Solution
When the plate area of a capacitor increases?
A
the voltage can withstand increase
B
the capacitance decreases
C
the capacitance is unaffected
D
the capacitance increases
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
Therefore, as the area of the plates increase, capacitance increases.
Source: WAEC / JAMB / NECO Classroom Archive (Record #64932)
Physics
UTME / JAMB 2022
Current Electricity
Solution
Which of the following is not a consequence of hydrogen bubbles covering the copper plate of a primary cell?
A
formation of hydrogen bubbles on the electrode
B
increase in the resistance of the cell
C
local action
D
polarization
medium Difficulty
Verified Correct Answer: Option C
Physical Principles & Numerical Solution
If the zinc used in the simple cell is of the impure commercial variety bubbles of hydrogen will be seen coming off the zinc. This is called local action.
Source: WAEC / JAMB / NECO Classroom Archive (Record #64920)
Physics
UTME / JAMB 2022
Current Electricity
Solution
A cell whose internal resistance is 0.55\(\Omega\) delivers a current of 4 A to an external resistor. The lost voltage of the cell is?
A
4.00 V
B
2.20 V
C
0.15 V
D
8.00 V
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
Lost voltage = I x R
= 4 x 0.55
= 2.2V
Source: WAEC / JAMB / NECO Classroom Archive (Record #64923)
Physics
UTME / JAMB 2022
Current Electricity
Solution
Which of the following liquid is a poor conductor of electricity?
A
Distilled water
B
Tap water
C
Sea water
D
Drinking water
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Distilled water is free of salts and is a poor conductor of electricity.
Source: WAEC / JAMB / NECO Classroom Archive (Record #64924)
Physics
UTME / JAMB 2022
Energy and Power
Solution
A current of 0.5 A flows through a resistor when connected to a 40 V battery. How much energy is dispatched in 2 minutes?
A
2400 J
B
9600 J
C
1500 J
D
1200 J
medium Difficulty
Verified Correct Answer: Option A
Physical Principles & Numerical Solution
Energy = power x time
Power = voltage x current.
Energy = voltage x current x time
Energy = 40 x 0.5 x 60 x 2
→ 2,400j
Source: WAEC / JAMB / NECO Classroom Archive (Record #64937)
Physics
UTME / JAMB 2022
Semi Conductor
Solution
A semiconductor is formed by?
A
co-ordinate bonds
B
electrovalent bonds
C
a substance free of bonds
D
covalent bonds
medium Difficulty
Verified Correct Answer: Option D
Physical Principles & Numerical Solution
It's generally created using silicon, germanium, or other pure elements.
Semiconductors are created by adding impurities to the element.
The conductance or inductance of the element depends on the type and intensity of the added impurities.
The electrons surrounding each atom in a semiconductor are part of a covalent bond
Source: WAEC / JAMB / NECO Classroom Archive (Record #65090)
Physics
UTME / JAMB 2022
Structure of the Nucleus
Solution
An isotope has an initial activity of 120 Bq. 6 days later its activity is 15 Bq. The half-life is?
A
3 days
B
2 days
C
1 day
D
4 days
medium Difficulty
Verified Correct Answer: Option B
Physical Principles & Numerical Solution
The equation that establishes a relationship between the amount left undecayed,
A, the initial amount, A0, and the number of half-lives that pass in a period of time t looks like this:
\(\frac{1}{2^n} * A_0 = A\)
\(\frac{1}{2^n} * 120 = 15\)
\(\frac{1}{2^n}\) = \(\frac{15}{120}\)
\(\frac{1}{2^n}\) = \(\frac{1}{8}\)
\(\frac{1}{2^n}\) = \(\frac{1}{2^3}\)
\(2^n = 2^3\)
n = 3
:6days \div 3 = 2days
Source: WAEC / JAMB / NECO Classroom Archive (Record #64925)