Let \(x\) = number of VIP tickets sold and \(y\) = number of regular tickets sold Total number of tickets sold = 200 ⇒ \(x\) + \(y\) = 200 ---- (i) If it costs ₦1,200 for a VIP ticket, then it costs ₦1200x for \(x\) number of VIP tickets sold and If it costs ₦700 for a regular ticket, then it costs ₦700\(y\) for \(y\) number of VIP tickets sold The total amount realised from the sale of tickets = ₦180,000 ⇒ 1200\(x\) + 700\(y\) = 180000 ----- (ii) From equation (i) \(x\) = 200 - \(y\) ----- (iii) Substitute (200 - \(y\)) for \(x\) in equation (ii) ⇒ 1200(200 - \(y\)) + 700\(y\) = 180000 ⇒ 240000 - 1200\(y\) + 700\(y\) = 180000 ⇒ 240000 - 500\(y\) = 180000 Collect like terms ⇒ 240000 - 180000 = 500\(y\) ⇒ 60000 = 500\(y\) ⇒ \(y = \frac{60000}{500} = 120\) Substitute 120 for \(y\) in equation (iii) ⇒ \(x = 200 - 120\) ⇒ \(x = 80\) ∴ The total number of VIP tickets sold is 80 and regular is 120