A 20-toothed gear wheel drives a 60-toothed one. If the angular speed of the smaller wheel is 120 rev s-1, the angular speed of the larger wheel is
A
3 rev s-1
B
40 rev s-1
C
360 rev s-1
D
2400 rev s-1
Verified Correct Answer: C.
Physical Principles & Numerical Solution
\(\frac{\text {speed of driver}}{\text {speeder driven}}\) = \(\frac{\text {no. of teeth of driver}}{\text {no. of teeth of driven}}\)
\(\frac{120}{V}\) = \(\frac{20}{60}\)
v = 360 rev s-1
Source: Myschool Past Questions Archive (Record #28370)