Three resistors, with substances 250\(\Omega\), 500\(\Omega\) and 1k\(\Omega\) are connected in series. A 6V battery is connected to either end of the combination. Calculate the pot3ential difference between the end of the 250\(\Omega\) resistor.
A
0.20V
B
0.86V
C
1.71V
D
3.43V
Verified Correct Answer: B.
Physical Principles & Numerical Solution
Using voltage - divider method
v1 = \(\frac{(R_1)}{R_T}\)VT
= \(\frac{250}{1750}\) x \(\frac{6}{1}\)
= 0.86V
Source: Myschool Past Questions Archive (Record #28357)