The magnification of the image of an object placed in front of a convex mirror is \(\frac{1}{3}\). If the radius of curvature of the mirror is 24cm, what is the distance between its object and its image?
A
8cm
B
16cm
C
24cm
D
32cm
Verified Correct Answer: D.
Physical Principles & Numerical Solution
F = uv ; v = 1u
12 = \(\frac{v + 3v}{v + 3v}\)
v = 16cm, u = 48cm
distance between U and V
= 48 - 16 =32cm
Source: Myschool Past Questions Archive (Record #28345)