In a sound wave in air, the adjacent rarefactions and compressions are separated by a distance of 17cm. If the velocity of the sound wave is 340ms-1. Determine the frequency
A
10Hz
B
20Hz
C
1000Hz
D
5780Hz
Verified Correct Answer: C.
Physical Principles & Numerical Solution
\(\lambda\) = 2L
2 x 17 = 34cm
F = \(\frac{V}{\lambda}\)
= \(\frac{340}{34 \times 10^{-2}}\)
= 1000Hz
Source: Myschool Past Questions Archive (Record #28342)