A piece of wood of mass 40g and uniform cross-sectional area of 2cm2 floats upright in water. The length of the wood immersed is
A
30cm
B
40cm
C
20cm
D
2cm
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Mw displaced = 40g
density = \(\frac{mass}{\text{area x height}}\)
I = \(\frac{40}{2\times h}\)
h = 20cm
Source: Myschool Past Questions Archive (Record #28323)