A lamp is rated 240V, 60W. The resistance of the filament is
A
960\(\Omega\)
B
16\(\Omega\)
C
15\(\Omega\)
D
4\(\Omega\)
Verified Correct Answer: A.
Physical Principles & Numerical Solution
P = \(\frac{V_2}{R}\) \(\Rightarrow\) R = \(\frac{V_2}{p}\)
= \(\frac{240\times 240}{60}\)
= 960\(\Omega\)
Source: Myschool Past Questions Archive (Record #28295)