Three cells each of e.m.f. 1.5v and an internal resistance of 1.0\(\Omega\) are connected in parallel across a load resistance of 2.67\(\Omega\). Calculate the current in the load?
A
0.26A
B
0.41A
C
0.50A
D
0.79A
Verified Correct Answer: C.
Physical Principles & Numerical Solution
E = 1.5v
rT = \(\frac{1 \times 1\times 1}{(1\times1)+ (1\times1) +(1\times1)}\)
E.m. f = I(R + r) = 0.33\(\Omega\)
1.5 = I(2.67 + 0.33)
I = 0.5A
Source: Myschool Past Questions Archive (Record #28278)