An object which is 3cm high is placed vertically 10cm in front of a concave mirror. If this object produces an image 40cm from the mirror, the height of the image is
A
0.75cm
B
4.00cm
C
8.00cm
D
12.00cm
Verified Correct Answer: D.
Physical Principles & Numerical Solution
\(\frac{\text {object height}}{\text{image height}}\) = \(\frac{\text {object distance}}{\text{image distance}}\)
\(\frac{3}{\text{image height}}\) = \(\frac{10}{40}\)
Image height = 12cm
Source: Myschool Past Questions Archive (Record #28257)