The relationship between L and the wavelength I of the stationary wave is
A
2L = \(\lambda\)
B
L = \(\lambda\)
C
L = \(\frac {\lambda}{3}\)
D
4L = 3 \(\lambda\)
Verified Correct Answer: D.
Physical Principles & Numerical Solution
L = - \(\lambda\) \(\Rightarrow\)4L = 3 \(\lambda\)
Source: Myschool Past Questions Archive (Record #27992)