When the volume of a given mass of gas is halved and its temperature doubled, the pressure
A
remains constant
B
increases by a factor of 4
C
increases by a factor of 3
D
decreases by a factor of 4
Verified Correct Answer: B.
Physical Principles & Numerical Solution
\(\frac{P_1V_1}{T_1}\) = \(\frac{P_2V_2}{T_2}\)
V1 = 2V2 and T2 = 2T1
\(\frac{P_1\times 2V_2}{T_1}\) = \(\frac{P_2\times V_2}{2T_1}\)
P2 = 4P1
Source: Myschool Past Questions Archive (Record #27983)