A capacitor 8\(\mu\)F is charged to a potential difference of 100V. The energy stored by the capacitor is
A
1.0 x 104J
B
8.0 x 10J
C
1.25 x 10J
D
4.0 x 10-2J
Verified Correct Answer: D.
Physical Principles & Numerical Solution
Energy = \(\frac{1}{2}\)CV2
= \(\frac{1}{2}\) x 8 x 10-6 x (100)2
= 4 x 10-2J
Source: Myschool Past Questions Archive (Record #27932)