An object is placed directly below a glass block of thickness 3.0cm. Calculate the lateral displacement of the object if the refractive index of the glass is 1.5.
A
1.0cm
B
1.5cm
C
2.0cm
D
2.5cm
Verified Correct Answer: A.
Physical Principles & Numerical Solution
1.5 = \(\frac{3}{\text {apparent displacement}}\)
Apparent depth = 2cm
displacement = 3 - 2
= 1cm
Source: Myschool Past Questions Archive (Record #27927)