If a solid X floats in liquids P of relative density 2.0 and in liquid Q of relative density 1.5, it can be inferred that the
A
weight of P displaced is greater than that of Q
B
weight of P displaced is less than that of Q
C
volume of P displaced is greater than that of Q
D
volume of P displaced is less than that of Q
Verified Correct Answer: A.
Physical Principles & Numerical Solution
R.d \(\alpha\) weight of liquid displaced
\(\frac{\text {R.d of P}}{\text {R.d of Q}}\) = \(\frac{\text{weight of p displaced}}{\text{weight of Q displaced}}\)
\(\frac{2}{1.5}\) = \(\frac{\text {weight of p displaced}}{\text {weight of Q displaced}}\)
A solid floats when the weight of the liquid it displaces is equal to the weight of the solid.
The relative density indicates that liquid P is denser than liquid Q.
Conclusion: Since liquid P is denser, for the same volume of the solid X displaced, the weight of the liquid displaced will be greater in liquid P than in liquid Q.
Source: Myschool Past Questions Archive (Record #27889)