A force of 15N stretches a spring to a total length of 30cm. An additional force of 10N stretches the spring 5cm further. Find the natural length of the spring
A
25.0cm
B
22.5cm
C
20.0cm
D
15.0cm
Verified Correct Answer: B.
Physical Principles & Numerical Solution
\(\frac{15}{30 - L}\) = \(\frac{10}{5}\)
L = 22.5cm
Source: Myschool Past Questions Archive (Record #27882)