A 12V battery has an internal resistance of 0.5W.If a cable of 1.0W resistance is connected across the two terminals of the battery, the current drawn from the battery is
A
16.0A
B
8.0A
C
0.8A
D
0.4A
Verified Correct Answer: B.
Physical Principles & Numerical Solution
I = \(\frac{E.m.f}{R + r}\)
= \(\frac{12}{1 + 0.5}\)
I = 8A
Source: Myschool Past Questions Archive (Record #27847)