Two parallel plates at a distance of 8.0 x 10-3m apart are maintained at a p.d of 600 volts with the negative plate earthed. What is the electric field strength?
A
4.8 Vm-1
B
75.0Vm-1
C
4800.0Vm-1
D
75000.0Vm-1
Verified Correct Answer: D.
Physical Principles & Numerical Solution
E = \(\frac{voltage}{distance}\)
= \(\frac{600}{8 \times 10^2}\)
= 75000.0Vm-1
Source: Myschool Past Questions Archive (Record #27844)