The energy contained in a wire when it extended by 0.02m by a force 500 N is
A
5J
B
10J
C
103J
D
104
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Energy = \(\frac{1}{2}\)Fe
= \(\frac{1}{2}\) x 500 x 0.02
E = 5J
Source: Myschool Past Questions Archive (Record #27774)