A body is projected from the earth's surface with the intention of letting it escape from the earth's gravitational field. What is the minimum escape velocity of the body? [Earth's radius = 6.4 x 103km, g = 10ms-2]
A
14 kms-1
B
13 kms-1
C
12 kms-1
D
11 kms-1
Verified Correct Answer: D.
Physical Principles & Numerical Solution
Velocity = \(\sqrt2gR\)
= 2 x 6400 x 100 x 10
= 11 km-1
Source: Myschool Past Questions Archive (Record #27760)